Problem 15
Question
Wieviele Nullstellen (und gegebenenfalls welche) besitzen die Polynome \(p_{1}(x)=x^{2}+x+1\), \(p_{2}(x)=2 x^{2}+6 x-20, p_{3}(x)=x^{2}-2 x+1 ?\)
Step-by-Step Solution
Verified Answer
\(p_1(x)\) has no real roots; \(p_2(x)\) has roots at \(x=2\) and \(x=-5\); \(p_3(x)\) has a root at \(x=1\).
1Step 1: Identify Coefficients for Each Quadratic Polynomial
For a quadratic polynomial, the standard form is \(ax^2 + bx + c\). In \(p_1(x) = x^2 + x + 1\), coefficients are: \(a=1\), \(b=1\), \(c=1\). In \(p_2(x) = 2x^2 + 6x - 20\), coefficients are: \(a=2\), \(b=6\), \(c=-20\). In \(p_3(x) = x^2 - 2x + 1\), coefficients are: \(a=1\), \(b=-2\), \(c=1\).
2Step 2: Determine the Discriminant for Each Polynomial
The discriminant \(\Delta\) of a quadratic equation \(ax^2 + bx + c = 0\) is calculated as \(\Delta = b^2 - 4ac\). For \(p_1(x)\), \(\Delta = 1^2 - 4(1)(1) = 1 - 4 = -3\). For \(p_2(x)\), \(\Delta = 6^2 - 4(2)(-20) = 36 + 160 = 196\). For \(p_3(x)\), \(\Delta = (-2)^2 - 4(1)(1) = 4 - 4 = 0\).
3Step 3: Evaluate the Number of Solutions Using the Discriminant
The discriminant provides information about the number and nature of the roots. If \(\Delta > 0\), there are two distinct real roots. If \(\Delta = 0\), there is one real root (a repeated root). If \(\Delta < 0\), there are no real roots, but two complex roots. For \(p_1(x)\), \(\Delta = -3\), so no real solutions. For \(p_2(x)\), \(\Delta = 196\), so two distinct real solutions. For \(p_3(x)\), \(\Delta = 0\), so one real solution.
4Step 4: Solve for the Real Roots (if any)
For \(p_2(x)\), use the quadratic formula: \[x = \frac{-b \pm \sqrt{\Delta}}{2a}\]. Substitute \(b=6\), \(\Delta=196\), \(a=2\): \[x = \frac{-6 \pm \sqrt{196}}{4} = \frac{-6 \pm 14}{4}\]. The roots are \(x = 2\) and \(x = -5\). For \(p_3(x)\), since \(\Delta = 0\), the root is given by \(x = \frac{-b}{2a}\). Substitute \(b=-2\), \(a=1\): \(x = \frac{2}{2} = 1\).
Key Concepts
DiscriminantPolynomial RootsReal and Complex RootsQuadratic Formula
Discriminant
The discriminant is a key component in understanding quadratic equations. It helps determine the nature and the number of roots a quadratic equation will have. The formula for the discriminant, denoted as \( \Delta \), is \( \Delta = b^2 - 4ac \).
- If \( \Delta > 0 \), the quadratic equation has two distinct real roots. This indicates that the graph of the equation touches the x-axis at two separate points.
- If \( \Delta = 0 \), there is exactly one real root, often called a double or repeated root. This means the graph is tangent to the x-axis at a single point.
- If \( \Delta < 0 \), there are no real roots; instead, the equation has two complex conjugate roots. Here, the graph does not intersect the x-axis at all.
Polynomial Roots
In mathematics, the roots of a polynomial are the values of \( x \) that make the polynomial equal to zero. For a quadratic polynomial, these can be found using various methods like factoring, completing the square, or the quadratic formula.
- In equations like \( p_2(x) = 2x^2 + 6x - 20 \), finding roots involves calculating where the graph of the polynomial crosses the x-axis.
- Once the roots become known, they provide solutions to the equation when set to zero.
Real and Complex Roots
Understanding the nature of roots is crucial in solving quadratic equations. Real roots are those that can be plotted on a number line, while complex roots involve imaginary numbers and cannot be directly visualized on the standard number line.
- Real roots occur when the discriminant is non-negative (\( \Delta \geq 0 \)). They may occur as two distinct points or as one repeated root.
- Complex roots come in pairs and occur when the discriminant is negative (\( \Delta < 0 \)), making use of the imaginary unit \( i \) where \( i^2 = -1 \).
Quadratic Formula
The quadratic formula is a universal method for solving any quadratic equation \( ax^2 + bx + c = 0 \). The formula is:
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
- This formula provides a straightforward way to find the roots without needing to factor the polynomial.
- It incorporates the discriminant within the square root, making it pivotal in determining the type of roots (real or complex).
- For \( p_2(x) \), using the quadratic formula yielded roots \( x = 2 \) and \( x = -5 \).
Other exercises in this chapter
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