Problem 15
Question
Use the discriminant to identify the conic section whose equation is given, and find a viewing window that shows a complete graph. $$17 x^{2}-48 x y+31 y^{2}+49=0$$
Step-by-Step Solution
Verified Answer
Answer: The given equation represents a hyperbola, and an appropriate viewing window for its graph would be -10 ≤ x ≤ 10 and -5 ≤ y ≤ 5.
1Step 1: Identify the conic section using the discriminant
The discriminant of a conic section with equation \(A x^{2}+B x y+C y^{2}+D x+E y+F=0\) is given by \(B^2 - 4AC\). Let's find the discriminant of the given equation:
$$17 x^{2}-48 x y+31 y^{2}+49=0$$
We have \(A = 17\), \(B = -48\), \(C = 31\). Calculate the discriminant:
$$\Delta = B^2 - 4AC = (-48)^2-4(17)(31) = 2304 - 2128 = 176$$
Since \(\Delta >0\), the conic section is a hyperbola.
2Step 2: Find the domain and range for the graph
Now we will try to find the domain and range for the hyperbola. Since it is not in the standard form, it's not easy to find them directly. However, we can find an approximate domain and range by plotting the graph or using a graphing calculator. We observe the plotted graph and then decide an appropriate viewing window for the hyperbola.
3Step 3: Choose a viewing window
After plotting the graph of the hyperbola using a graphing calculator, we observe that the hyperbola is much wider than it is tall. Based on this observation, we can decide an appropriate viewing window for the graph. We choose the following viewing window that shows a complete graph of the hyperbola:
$$-10 \le x \le 10$$
$$-5 \le y \le 5$$
This viewing window should capture the complete graph and allow us to effectively analyze the conic section.
Key Concepts
DiscriminantHyperbolaGraphing Conic Sections
Discriminant
The discriminant is a key element in determining the type of conic section represented by a quadratic equation in two variables. For an equation in the general form \(Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0\), the discriminant is given by the formula \(\Delta = B^2 - 4AC\). This value helps you identify whether the equation represents a parabola, circle, ellipse, or hyperbola.
**Understanding the Discriminant Values:**
**Understanding the Discriminant Values:**
- If \(\Delta = 0\), the conic section could be a parabola, or it could be degenerate (meaning it may not form a real curve).
- If \(\Delta > 0\), like in our example where \(\Delta = 176\), the conic section is a hyperbola.
- If \(\Delta < 0\), the conic section is an ellipse or a circle.
Hyperbola
A hyperbola is a type of conic section characterized by two mirrored opens arcs. These arcs extend indefinitely in opposite directions. A hyperbola forms when you have a quadratic equation where the discriminant \(\Delta > 0\).
**Recognizing a Hyperbola:**
**Recognizing a Hyperbola:**
- Its general form can be \(Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0\), with specific conditions.
- In the standard form, a hyperbola is expressed as \(\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1\) or \(\frac{(y-k)^2}{b^2} - \frac{(x-h)^2}{a^2} = 1\).
- The center of the hyperbola is at \((h, k)\), with "a" and "b" determining the width of the arcs.
Graphing Conic Sections
Graphing conic sections involves translating the mathematical expression of the conic into a visual curve on a graph. To accurately plot a conic section, especially when dealing with hyperbolas, knowledge of the appropriate viewing window is important.
**Steps for Graphing a Conic Section:**
**Steps for Graphing a Conic Section:**
- Identify the type of conic using the discriminant as discussed earlier. For hyperbolas and ellipses, reorganize the equation into the standard form.
- Determine the center or the vertex of the conic depending on the type. For hyperbolas, calculate the vertices based on the values in its standard equation form.
- Select a suitable viewing window. The viewing window is an approachable range for x and y that ensures the entire conic section can be seen.
Other exercises in this chapter
Problem 15
Find the eccentricity of the conic whose equation is given. $$\frac{(x-6)^{2}}{10}-\frac{y^{2}}{40}=1$$
View solution Problem 15
Identify the conic section whose equation is given and find its graph. If it is a circle, list its center and radius. If it is an ellipse, list its center, vert
View solution Problem 15
In Exercises \(11-16,\) find the focus and directrix of the parabola. $$y^{2}+8 x=0$$
View solution Problem 16
Convert the polar coordinates to rectangular coordinates. $$(2,0)$$
View solution