Problem 15
Question
Use the difference-of-squares pattern to factor each of the following. $$4 x^{2}-(y+1)^{2}$$
Step-by-Step Solution
Verified Answer
\((2x + y + 1)(2x - y - 1)\)
1Step 1: Recognize the Difference of Squares
The expression given is \(4x^2 - (y+1)^2\). Notice that it is in the form \(a^2 - b^2\), where \(a^2 = (2x)^2\) and \(b^2 = (y+1)^2\). The formula for the difference of squares is \(a^2 - b^2 = (a+b)(a-b)\).
2Step 2: Identify \(a\) and \(b\)
From the expression \(4x^2 - (y+1)^2\), we can identify \(a = 2x\) and \(b = (y+1)\). These are the terms whose squares form the original expression.
3Step 3: Apply the Difference of Squares Formula
Substitute \(a = 2x\) and \(b = (y+1)\) into the formula \(a^2 - b^2 = (a+b)(a-b)\). This gives us:\[(2x + (y+1))(2x - (y+1))\].
4Step 4: Simplify the Factored Form
Simplify the expression inside the parentheses:- For the first term: \(2x + (y + 1) = 2x + y + 1\).- For the second term: \(2x - (y + 1) = 2x - y - 1\).Thus, the factored form is \((2x + y + 1)(2x - y - 1)\).
Key Concepts
Polynomial FactoringAlgebraic ExpressionsFactoring Techniques
Polynomial Factoring
Polynomial factoring is like breaking down a number into its prime components, but for polynomials. When you're dealing with polynomial expressions, factoring them can simplify problems and make them easier to solve. In this exercise, we focus on a specific type of polynomial factoring known as the "difference of squares."
- Polynomials are expressions that contain variables raised to varying powers and have coefficients.
- Factoring polynomials involves writing them as a product of simpler expressions or polynomials.
- It’s an essential skill because it helps in simplifying expressions and solving equations more efficiently.
Algebraic Expressions
Algebraic expressions are combinations of numbers, variables, and arithmetic operations. They are fundamental to algebra and appear in a variety of contexts, from simple equations to complex polynomials.
- Understanding algebraic expressions means recognizing how to manipulate them through the rules of algebra.
- In our example, the expression \(4x^2 - (y+1)^2\) includes two terms, each of which is a squared expression.
Factoring Techniques
Factoring techniques are methods used to break down complex expressions or numbers into their components. One particularly useful method in algebra is factoring by recognizing the difference of squares.
- The difference of squares is a pattern given by \(a^2 - b^2\), which can be factored into \((a+b)(a-b)\).
- In our example, it identifies that we have \((2x)^2 - (y+1)^2\), allowing us to apply the formula directly.
- Once the expression is factored, it simplifies into \((2x + y + 1)(2x - y - 1)\).
Other exercises in this chapter
Problem 15
Solve each equation. You will need to use the factoring techniques that we discussed throughout this chapter. $$6 x^{2}+25 x+14=0$$
View solution Problem 15
Factor completely each of the polynomials and indicate any that are not factorable using integers. $$x^{2}+15 x y+36 y^{2}$$
View solution Problem 15
Factor each of the composite numbers into the product of prime numbers. For example, \(30=2 \cdot 3 \cdot 5 .\) $$56$$
View solution Problem 15
Find each indicated product. Remember the shortcut for multiplying binomials and the other special patterns we discussed in this section. $$(y-5)(y+11)$$
View solution