Problem 15

Question

Use radical notation to write each expression. Simplify if possible. $$ -16^{1 / 4} $$

Step-by-Step Solution

Verified
Answer
\(\sqrt[4]{-16} = 2i\)
1Step 1: Understand Radical Notation
Radical notation involves expressing an expression with exponents as a root. The expression given is \(-16^{1/4}\), where the exponent \(\frac{1}{4}\) indicates the fourth root of \(-16\). Thus, the expression can be rewritten as \(\sqrt[4]{-16}\).
2Step 2: Simplify Using Properties of Even Roots
When dealing with even roots, such as the fourth root, we must consider that taking an even root of a negative number results in a complex number. Thus, the fourth root of \(-16\) can be expressed in terms of imaginary numbers. Let us proceed by recognizing that:\(-16 = 16 \times (-1)\)Therefore, we can write:\(\sqrt[4]{-16} = \sqrt[4]{16} \times \sqrt[4]{-1}\)
3Step 3: Simplify Each Component
Now, we simplify each part separately: - Calculate the fourth root of 16: \(\sqrt[4]{16} = 2\), because \(2^4 = 16\).- Calculate the fourth root of \(-1\): The fourth root of \(-1\) is an imaginary number, specifically a complex number, since odd roots of negative numbers can be real, whereas even roots cannot. The expression results in \(\sqrt[4]{-1} = i\), where \(i\) is the imaginary unit and \(i^4 = 1\).
4Step 4: Combine the Results
Now combine the results of the fourth roots together:\(\sqrt[4]{-16} = 2 \times i\), leading to the simplified form:\(\sqrt[4]{-16} = 2i\).

Key Concepts

Understanding Fourth RootsExploring Complex NumbersThe Role of the Imaginary Unit
Understanding Fourth Roots
The concept of fourth roots is integral to solving expressions like \(-16^{1/4}\). When you see an exponent of \(\frac{1}{4}\), it means you need to find a number which, when raised to the power of 4, equals the original number, in this case, -16. In radical notation, this is represented as \( \sqrt[4]{-16} \).

Key points about fourth roots:
  • The fourth root of a number is both a radical (root) and an exponent form (fractional exponent).
  • Even roots (like the fourth root) handle negative numbers differently than odd roots as they involve complex numbers.
The calculation involves separating the negative sign from the numerical value when an even root is involved. Here, \(-16\) is split into \(16 \times (-1)\), making solving for \(-16^{1/4}\) more manageable.
Exploring Complex Numbers
Complex numbers are a crucial concept when dealing with roots of negative numbers. A complex number is a combination of a real part and an imaginary part, typically written as \(a + bi\). In the context of \(-16^{1/4}\), the result involves a complex number.

Here's a breakdown:
  • Real numbers are the set of numbers we're most familiar with, including integers, fractions, and irrational numbers.
  • Complex numbers expand beyond the real numbers and allow for solutions to equations that involve even roots of negative numbers.
  • They are essential in fields such as engineering and physics for modeling oscillations and waves.
Understanding complex numbers helps in recognizing that, for instance, the fourth root of -16 leads to \(2i\). Thus, it helps bridge the gap in our mathematical toolset to solve advanced problems.
The Role of the Imaginary Unit
At the heart of complex numbers lies the imaginary unit, denoted as \(i\). The imaginary unit helps us handle the square roots of negative numbers, such as \( \sqrt{-1} \) which is defined as \(i\).

Key details about the imaginary unit:
  • The unit \(i\) is defined by the property that \(i^2 = -1\).
  • For even powers, like \(i^4, \) which equals 1, cyclical properties are key, as they repeat after every four exponents (i.e., \(i^4, i^8, i^{12}\), etc.).
  • When decomposing expressions such as \(\sqrt[4]{-1}\), understanding that this equals \(i\) simplifies many problems.
The imaginary unit is a powerful tool that allows high-level solutions for mathematical equations that were previously unsolvable using only real numbers. In \(\sqrt[4]{-16} = 2i\), recognizing \(i\) allows us to express results that encompass both magnitude and direction, pivotal in many advanced fields.