Problem 15
Question
Use power series operations to find the Taylor series at \(x=0\) for the functions in Exercises \(11-28 .\) $$x \cos \pi x$$
Step-by-Step Solution
Verified Answer
The Taylor series for \(x\cos(\pi x)\) at \(x=0\) is \(x - \frac{\pi^2}{2}x^3 + \frac{\pi^4}{24}x^5 - \frac{\pi^6}{720}x^7 + \ldots\).
1Step 1: Recall the Taylor series for cosine
The Taylor series for the cosine function centered at 0 is given by: \[ ext{cos}(x) = extstyleegin{align}egin{aligned} ext{1} - rac{x^2}{2!} + rac{x^4}{4!} - rac{x^6}{6!} + ext{...} = extstyleegin{align}egin{aligned} ext{ extstyleegin{align}egin{aligned} ext{ ext{}}} ext{1} + ext{i} ext{i}}}}}}}}dots \] This series will be used by substituting \(x\) with \(\pi x\).
2Step 2: Substitute and simplify
Substitute \(\pi x\) into the Taylor series expansion for cosine: \[ ext{cos}( ext{πx}) = 1 - rac{( ext{πx})^2}{2!} + rac{( ext{πx})^4}{4!} - rac{( ext{πx})^6}{6!} + ext{...} \] This simplifies to: \[ 1 - rac{ ext{π}^2 x^2}{2!} + rac{ ext{π}^4 x^4}{4!} - rac{ ext{π}^6 x^6}{6!} + ext{...} \] Each term now involves \(x\) raised to an even power.
3Step 3: Multiply by x to find the series of xcos(πx)
Multiply the function \(x\) by the series of \( ext{cos}( ext{πx})\): \[ x( ext{cos}( ext{πx})) = x\left(1 - \frac{\text{π}^2 x^2}{2!} + \frac{\text{π}^4 x^4}{4!} - \frac{\text{π}^6 x^6}{6!} + \text{...}\right) \] Distribute \(x\) through the series: \[ x - \frac{\text{π}^2 x^3}{2!} + \frac{\text{π}^4 x^5}{4!} - \frac{\text{π}^6 x^7}{6!} + \text{...} \] This is the series of \(x\cos(\text{πx})\).
4Step 4: Write the final expression
The Taylor series for \(x\cos(\text{πx})\) at \(x=0\) is: \[ x - \frac{\text{π}^2 x^3}{2} + \frac{\text{π}^4 x^5}{24} - \frac{\text{π}^6 x^7}{720} + \text{...} \] Each term is obtained by multiplying \(x\) with the corresponding term of the cosine series expanded with \(\pi x\).
Key Concepts
Power SeriesCosine FunctionSeries Expansion
Power Series
A power series is a way to represent a function as an infinite sum of terms involving powers of a variable. It is expressed in the form:
In mathematics, a power series can converge, which means the sum becomes a finite value, or diverge, meaning it doesn't sum to a specific value. Convergence depends on the application and the values of \(x\).
Using power series allows us to understand and use functions in ways that can't be done using simple algebra. It's like having a magic formula that can simplify complex tasks. This concept is particularly crucial when dealing with the series expansion of functions like the cosine function.
- Sum of \(a_n x^n\)
- Where \(a_n\) are coefficients
- \(x\) is a variable
In mathematics, a power series can converge, which means the sum becomes a finite value, or diverge, meaning it doesn't sum to a specific value. Convergence depends on the application and the values of \(x\).
Using power series allows us to understand and use functions in ways that can't be done using simple algebra. It's like having a magic formula that can simplify complex tasks. This concept is particularly crucial when dealing with the series expansion of functions like the cosine function.
Cosine Function
The cosine function, denoted as \( ext{cos}(x)\), is one of the basic trigonometric functions. It depicts the ratio of the adjacent side to the hypotenuse of a right-angled triangle. However, in calculus and more advanced mathematics, we often explore it beyond its geometric definition.
The Taylor series offers a way to express \(\text{cos}(x)\) as an infinite series centered around 0. This series is:
This series is particularly useful when working with angles beyond the usual range or when using a computer or calculator. By substituting variables into this series, like substituting \(\pi x\) for the problem in question, it adjusts the calculation to suit various applications.
The Taylor series offers a way to express \(\text{cos}(x)\) as an infinite series centered around 0. This series is:
- \(\text{cos}(x) = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{6!} + \cdots\)
This series is particularly useful when working with angles beyond the usual range or when using a computer or calculator. By substituting variables into this series, like substituting \(\pi x\) for the problem in question, it adjusts the calculation to suit various applications.
Series Expansion
Series expansion involves expressing a feature of a mathematical function as an infinite sum of terms based on powers of a variable. In the context of this problem, we dealt with a Taylor series, which is a type of series expansion.
A Taylor series gives a function's idea as an infinite sum around a certain point, often 0. This is called the function's expanded form and shows how the function behaves around this specific point.
For the cosine function, we modified the general Taylor series expression to accommodate \(\pi x\) and further adjusted for \(x\cos(\pi x)\).
A Taylor series gives a function's idea as an infinite sum around a certain point, often 0. This is called the function's expanded form and shows how the function behaves around this specific point.
For the cosine function, we modified the general Taylor series expression to accommodate \(\pi x\) and further adjusted for \(x\cos(\pi x)\).
- Start with the known cosine series
- Substitute with \(\pi x\)
- Multiply the series by \(x\) to achieve the desired function
- Each step transforms the series for specific applications
Other exercises in this chapter
Problem 14
Use power series operations to find the Taylor series at \(x=0\) for the functions in Exercises \(11-28 .\) $$\sin x-x+\frac{x^{3}}{3 !}$$
View solution Problem 15
In Exercises \(15-18\) , use series to estimate the integrals' values with an error of magnitude less than \(10^{-5}\) . (The answer section gives the integrals
View solution Problem 15
Find the Maclaurin series for the functions \(\sin 3 x\)
View solution Problem 15
Which of the series Converge absolutely, which converge, and which diverge? Give reasons for your answers. $$ \sum_{n=1}^{\infty}(-1)^{n+1}(0.1)^{n} $$
View solution