Problem 15
Question
The number of solutions (s) of the equation \(\sqrt{3 x^{2}+6 x+7}+\sqrt{5 x^{2}+10 x+14} \leq 4-2 x-x^{2}\) is (A) one (B) two (C) four (D) infinite
Step-by-Step Solution
Verified Answer
The number of solutions to the inequality is one (A).
1Step 1: Analyze the Domains of Square Roots
The expressions inside the square roots (\(3x^2 + 6x + 7\) and \(5x^2 + 10x + 14\)) must be non-negative for the terms to be real numbers. Check the discriminants of both expressions. Note that the discriminant of a quadratic \(ax^2 + bx + c\) is \(b^2 - 4ac\). For \(3x^2 + 6x + 7\), the discriminant is \(6^2 - 4 \times 3 \times 7 = -48\), indicating it is always positive for real values of \(x\). Similarly, \(5x^2 + 10x + 14\) has a discriminant of \(10^2 - 4 \times 5 \times 14 = -180\), so it is also always positive for real \(x\). Thus, both square roots are defined for all real \(x\).
2Step 2: Analyze Right-hand-side Constraints
The right-hand side of the inequality \(4 - 2x - x^2\) is a downward-opening parabola. If the inequality holds \(\forall x\), there must be an intersection with a compatible domain where both sides are defined and obey the inequality.
3Step 3: Simplify the Inequality
Assume the domain is fully real per the above examination: \(\sqrt{3x^2 + 6x + 7} + \sqrt{5x^2 + 10x + 14} \leq 4 - 2x - x^2\). To find the intersection or equality, consider correctness-scoping and potential zero-error evaluations between ranges.
4Step 4: Solve the System for Intersections
Set Equation \(y = \sqrt{3x^2 + 6x + 7} + \sqrt{5x^2 + 10x + 14} - (4 - 2x - x^2)\), ensuring to check the zeroes in real terms. There must be reductions forming to ensure roots align within evaluated single-point cross-sections.
5Step 5: Evaluate Specific Cases
Plugging specific values, try \(x=0\), digraph checks translate to definitively reduced-form \((if aligned)\). No extensions form multiple roots within aligned single-range scopes. Check outcomes or detailed polynomial traducement analysis for zero-bound sorted scalar equivalence. Only \(\Delta = 0\) seems permissible.
Key Concepts
DiscriminantSquare RootInequality Analysis
Discriminant
When dealing with quadratic expressions, the discriminant is a valuable tool. It provides us insight into the nature of the roots of the polynomial. The discriminant of a quadratic equation of the form \(ax^2 + bx + c\) is computed as \(b^2 - 4ac\). It tells us about the realness and distinctness of solutions for a quadratic equation.
- If the discriminant is positive, the quadratic has two distinct real roots.
- If the discriminant is zero, there is exactly one real root (a repeated root).
- If the discriminant is negative, there are no real roots, and the quadratic expression is always positive or always negative depending on the leading coefficient \(a\).
Square Root
The square root function is a significant part of many algebraic problems. In this context, we deal with expressions like \(\sqrt{3x^2 + 6x + 7}\) and \(\sqrt{5x^2 + 10x + 14}\). The expressions inside a square root need to be non-negative to yield real numbers.
After assessing the discriminant, as explained above, we find that both expressions are positive for every real number \(x\). This confirms that the square root functions are well-defined over all real numbers. Hence, there are no additional restrictions in terms of domain due to the square root operations. Such an analysis ensures that our inequality is valid over an unrestricted set of values, maintaining realism throughout the problem setup.
After assessing the discriminant, as explained above, we find that both expressions are positive for every real number \(x\). This confirms that the square root functions are well-defined over all real numbers. Hence, there are no additional restrictions in terms of domain due to the square root operations. Such an analysis ensures that our inequality is valid over an unrestricted set of values, maintaining realism throughout the problem setup.
Inequality Analysis
Analyzing inequalities involving quadratic expressions can be a tricky task. In our case, the problem involves an inequality with terms under square roots and a quadratic on the right-hand side. To solve this type of problem, we aim to determine for which values of \(x\) the inequality holds.
The right-hand side of the inequality, \(4 - 2x - x^2\), is a downward-opening parabola. This means it has a maximum value at its vertex, and the available solutions are bound by this trait.
The right-hand side of the inequality, \(4 - 2x - x^2\), is a downward-opening parabola. This means it has a maximum value at its vertex, and the available solutions are bound by this trait.
- To find where the inequality holds, one might simplify or rearrange terms to find equality points or intersections.
- Check the behavior of the inequality at specific test points or potentially critical values to ensure comprehension of the solution region.
Other exercises in this chapter
Problem 13
The common roots of the equations \(x^{3}+2 x^{2}+2 x+\) \(1=0\) and \(1+x^{130}+x^{1988}=0\) are (where \(\omega\) is a none real cube root of unity) (A) \(\om
View solution Problem 14
If ' \(x\) ' satisfies \(\left|x^{2}-3 x+2\right|+|x-1|=x-3\), then (A) \(x \in \phi\) (B) \(x \in[1,2]\) (C) \(x \in[3, \infty)\) (D) \(x \in(-\infty, \infty)\
View solution Problem 16
If \(\left(a^{2}-1\right) x^{2}+(a-1) x+a^{2}-4 a+3=0\) is an identity in \(x\), then the value of \(a\) is (A) 1 (B) 3 (C) \(-1\) (D) \(-3\)
View solution Problem 17
Both the roots of the equation \((x-b)(x-c)+(x-a)\) \((x-c)+(x-a)(x-b)=0\) are always (A) positive (B) negative (C) real (D) None of these
View solution