Problem 15
Question
The muscle isozyme of lactate dehydrogenase is inhibited by lactate. Steady-state kinetic analysis yielded the following data, with lactate either absent or present at a fixed concentration. (a) Pyruvate is the substrate whose concentration is varied in one plot, NADH in the other. Identify each. Use an arrow and the appropriate letter (b, c, d, or e) to identify each of the following. (b) Reciprocal of \(V_{\max }\) for the uninhibited enzyme. (c) The line representing data obtained in the presence of lactate acting as a competitive inhibitor with respect to the variable substrate. (d) The line representing data obtained in the presence of lactate acting as a noncompetitive inhibitor with respect to the variable substrate. (e) Reciprocal of \(K_{\mathrm{M}}\) in the presence of lactate acting as a competitive inhibitor. (f) If \(K_{\mathrm{M}}\) for NADH is \(2 \times 10^{-5} \mathrm{M}\), then which of the following is the most appropriate NADH concentration to use when determining \(K_{\mathrm{M}}\) for pyruvate: \(10^{-7} \mathrm{M}, 10^{-6} \mathrm{M}, 10^{-5} \mathrm{M}, 10^{-4} \mathrm{M}\), or \(10^{-3} \mathrm{M}\) ?
Step-by-Step Solution
VerifiedKey Concepts
Lactate Dehydrogenase
This enzyme has different isozymes, meaning there are variations of it in different tissues. In muscles, the isozyme of lactate dehydrogenase is slightly different compared to other tissues, which may affect how it is regulated or inhibited. Learning about how these isozymes react in different environments is key in understanding their function.
For instance, when lactate accumulates, it can act as an inhibitor to lactate dehydrogenase. Understanding how this occurs helps us in fields like exercise physiology, where the build-up of lactate is related to muscle fatigue.
Competitive Inhibition
What happens in this case is that lactate competes with pyruvate for the same active site on lactate dehydrogenase. As a result, more pyruvate molecules are needed to achieve the same level of enzyme activity, effectively increasing the apparent \( K_{M} \) and changing the slope in a Lineweaver-Burk plot. However, the maximum velocity \( V_{ ext{max}} \) remains the same because if enough substrate molecules are present, they can outnumber and outcompete the inhibitor at the active sites.
Noncompetitive Inhibition
The binding of the inhibitor reduces the enzyme's activity regardless of how much substrate is present. This results in a decreased \( V_{ ext{max}} \) since the enzyme's efficiency is compromised. In a Lineweaver-Burk plot, both the slope and the y-intercept change, indicating that the enzyme cannot reach its previous maximum rate, even if there is ample substrate.
Lineweaver-Burk Plot
In this plot, the y-intercept represents \( 1/V_{ ext{max}} \), while the x-intercept reflects the negative reciprocal of \( K_{M} \). The slope illustrates \( K_{M}/V_{ ext{max}} \). Lineweaver-Burk plots are especially useful for visualizing how different types of inhibition affect enzyme activity. For instance:
- Competitive inhibition increases the slope due to increased apparent \( K_{M} \), but does not change the y-intercept.
- Noncompetitive inhibition alters both the slope and y-intercept, reflecting changes in both \( K_{M} \) and \( V_{ ext{max}} \).