Problem 15
Question
The functions are all one-to-one. For each function, a. Find an equation for \(f^{-1}(x),\) the inverse function. b. Verify that your equation is correct by showing that $$f\left(f^{-1}(x)\right)=x \text { and } f^{-1}(f(x))=x$$ $$ f(x)=2 x+3 $$
Step-by-Step Solution
Verified Answer
The inverse function of \(f(x) = 2x + 3\) is \(f^{-1}(x) = (x - 3)/2\). The verification process proves that this answer is correct because \(f^{-1}(f(x)) = x\) and \(f(f^{-1}(x)) = x\) for this particular inverse relation.
1Step 1: Derive the Inverse Function
To obtain the inverse of a function, one must replace \(f(x)\) with \(y\) and then solve the equation for \(x\). The function of \(f(x)\) is given as \(f(x)=2x+3\), so replacing \(f(x)\) with \(y\) we get \(y = 2x+3\). Rearranging this equation to find \(x\), we will have: \(x = (y-3)/2\). The inverse function \(f^{-1}(x)\) is therefore \(f^{-1}(x)= (x-3)/2\).
2Step 2: Verify the first property of the inverse function
Now, insert \(f^{-1}(x)\) into \(f(x)\) to verify the equation \(f(f^{-1}(x))= x\). This means we substitute \(f^{-1}(x)\) into the equation for \(f(x)\) as follows: \(f(f^{-1}(x)) = 2 * (f^{-1}(x)) + 3 = 2 * ((x-3)/2) + 3 =x\). So the first property of the inverse function is verified.
3Step 3: Verify the second property of the inverse function
Insert \(f(x)\) into \(f^{-1}(x)\) to verify the equation \(f^{-1}(f(x))=x\). This involves substituting \(f(x)\) into the equation for \(f^{-1}(x)\) as follows: \(f^{-1}(f(x)) = (f(x) - 3)/2 = ((2x+3) - 3)/2 = x\). Hence, the second property of the inverse function is also verified.
Key Concepts
One-to-One FunctionsVerifying Inverse FunctionsAlgebraic Manipulation
One-to-One Functions
A one-to-one function is a special type of function where each output value corresponds to exactly one input value. This means that no two different inputs can produce the same output. This property is crucial when dealing with inverse functions, because only one-to-one functions can have inverses that are also functions.
Let's consider the given function:
Let's consider the given function:
- For example, the function \(f(x) = 2x + 3\) is one-to-one because every different \(x\) gives a different \(f(x)\).
- If no horizontal line cuts the graph of the function more than once, then the function is one-to-one.
Verifying Inverse Functions
Once you've found what you assume is the inverse function, it's important to verify it to ensure accuracy. This involves checking two main properties:
- \(f(f^{-1}(x)) = x\)
- \(f^{-1}(f(x)) = x\)
- For \(f(f^{-1}(x))\), substitute \(f^{-1}(x)\) into \(f(x)\):
- \(f\left(f^{-1}(x)\right) = 2 \left(\frac{x-3}{2}\right) + 3 = x\)
- \(f^{-1}(f(x)) = \frac{(2x + 3) - 3}{2} = x\)
Algebraic Manipulation
Algebraic manipulation is a fundamental skill when handling inverse functions. It involves rearranging equations to solve for a particular variable. For inverse functions, this process is used to switch the roles of the input and output.
Take the original function \(f(x) = 2x + 3\). To find its inverse, follow these algebraic manipulation steps:
Take the original function \(f(x) = 2x + 3\). To find its inverse, follow these algebraic manipulation steps:
- Replace \(f(x)\) with \(y\): \(y = 2x + 3\).
- Solve for \(x\) by isolating it: \(x = \frac{y - 3}{2}\).
- Swap \(x\) and \(y\) to express the inverse: \(f^{-1}(x) = \frac{x - 3}{2}\).
Other exercises in this chapter
Problem 14
Find the domain of each function. $$ h(x)-\frac{5}{\frac{4}{x}-1} $$
View solution Problem 14
Use the given conditions to write an equation for each line in point-slope form and slope-intercept form. Slope \(-8,\) passing through \((4,-1)\)
View solution Problem 15
Find the distance between each pair of points. If necessary, round answers to two decimals places. $$(3 \sqrt{3}, \sqrt{5})\( and \)(-\sqrt{3}, 4 \sqrt{5})$$
View solution Problem 15
Use the given conditions to write an equation for each line in point-slope form and slope-intercept form. Slope \(--3,\) passing through \((-2,-3)\)
View solution