Problem 15
Question
$$\text { Factor by grouping.}$$ $$3 x^{3}-2 x^{2}-6 x+4$$
Step-by-Step Solution
Verified Answer
Hence the factorized form by grouping of \(3x^3 - 2x^2 - 6x + 4\) is \((3x - 2) (x^2 - 2)\).
1Step 1: Group the terms
The initial step to factoring by grouping is to divide the polynomial into two groups. Here, the given polynomial is \(3x^3 - 2x^2 - 6x + 4\). Accordingly, it can be divided into two groups: \(3x^3 - 2x^2\) and \(-6x + 4\).
2Step 2: Factor out the Greatest Common Factor (GCF) from each group
For each group, factor out the Greatest Common Factor. For the first group \(3x^3 - 2x^2\), the common factor is \(x^2\). After factoring out \(x^2\), the expression becomes \(x^2 (3x - 2)\). Similarly, for the second group \(-6x + 4\), the common factor is \(-2\), factoring out which leads us to \(-2 (3x - 2)\).
3Step 3: Factor out common binomial
The two terms of the polynomial now are \(x^2 (3x - 2)\) and \(-2 (3x - 2)\). Here, the common binomial factor is \((3x - 2)\). Factor out \((3x - 2)\) and it becomes: \((3x - 2) (x^2 - 2)\).
Key Concepts
Greatest Common FactorPolynomial FactoringBinomial Factor
Greatest Common Factor
The greatest common factor, or GCF, is a crucial concept when it comes to polynomial factoring. Think of the GCF as the biggest number or expression that can evenly divide each term in a group, without leaving a remainder. This is similar to finding the greatest common divisor in basic arithmetic but applied to algebraic expressions.
The advantage of identifying the GCF is that it simplifies polynomials, making them more manageable.
The advantage of identifying the GCF is that it simplifies polynomials, making them more manageable.
- For example, take a look at the group of terms like \(3x^3\) and \(-2x^2\). By spotting the GCF, which is \(x^2\), you can factor it out to simplify the group to \(x^2(3x - 2)\).
- In another group, say \(-6x + 4\), \(-2\) is the greatest factor. By factoring \(-2\) out, you get \(-2(3x - 2)\).
Polynomial Factoring
Polynomial factoring is like breaking down a complex object into simpler parts, a bit like dismantling a machine to understand how it functions. This technique is used to express a polynomial as a product of simpler polynomials or factors.
Mastering this process involves practice and an understanding of how to identify patterns and common factors within given expressions.
- In the exercise we have, the polynomial start is \(3x^3 - 2x^2 - 6x + 4\).
- By grouping terms and factoring the GCF from each group, we manage to transform the polynomial into an expression with a common binomial factor.
Mastering this process involves practice and an understanding of how to identify patterns and common factors within given expressions.
Binomial Factor
A binomial factor refers to a polynomial with two terms, much like a simple mathematical phrase. Recognizing a common binomial factor within different parts of a polynomial is a powerful strategy in polynomial factoring.
Once you identify like terms in separate groups, the binomial factor becomes a shared term in the overarching polynomial.
Once you identify like terms in separate groups, the binomial factor becomes a shared term in the overarching polynomial.
- For example, you may notice \((3x - 2)\) repeatedly showing up after grouping and factoring the polynomial \(3x^3 - 2x^2 - 6x + 4\).
- In such cases, this commonality allows you to "factor it out", leading to a factorization such as \((3x - 2)(x^2 - 2)\).
Other exercises in this chapter
Problem 15
Evaluate each exponential expression. $$\left(2^{2}\right)^{3}$$
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Multiply or divide as indicated. $$\frac{x-2}{3 x+9} \cdot \frac{2 x+6}{2 x-4}$$
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In Exercises 15–58, find each product. $$(x+1)\left(x^{2}-x+1\right)$$
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Use the product rule to simplify the expressions in Exercises \(13-22\) In Exercises \(17-22,\) assume that variables represent nonnegative real Numbers. $$\sqr
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