Problem 15
Question
Test for symmetry with respect to the line \(\theta=\pi 2,\) the polar axis, and the pole. $$r=\frac{2}{1+\sin \theta}$$
Step-by-Step Solution
Verified Answer
The polar function \(r = \frac{2}{1 + \sin \theta}\) is not symmetric with respect to the line \(\theta = \frac{\pi}{2}\), the polar axis, or the pole.
1Step 1: Test for Symmetry with Respect to the Line \(\theta = \frac{\pi}{2}\)
To test for symmetry about the line \(\theta = \frac{\pi}{2}\), substitute \(-\theta\) for \(\theta\) in the polar equation and simplify. If the new equation is the same as the original equation, the plot is symmetric with respect to the line \(\theta = \frac{\pi}{2}\).\nSo, \[r = \frac{2}{1+\sin(-\theta)} = \frac{2}{1 - \sin(\theta)}\] which is not the same as the original equation. So, the plot is not symmetric with respect to the line \(\theta = \frac{\pi}{2}\)
2Step 2: Test for Symmetry with Respect to the Polar Axis
To test for symmetry with respect to the polar axis, replace \(\theta\) by \(-\theta\) in the polar equation and simplify. If we get back the original equation, then the graph of the equation is symmetrical about the polar axis.\nSo, \[r = \frac{2}{1 + \sin(-\theta)} = \frac{2}{1 - \sin(\theta)}\] which does not reduce to the original equation. Therefore, the function is not symmetrical with respect to the polar axis.
3Step 3: Test for Symmetry with Respect to the Pole
To test for symmetry with respect to the pole, replace \(r\) with \(-r\) in the polar equation and simplify.However, we can see directly that replacing \(r\) with \(-r\) doesn't make any sense as \(r\) equals to a fraction and replacing it with \(-r\) would mean that we replace the fraction with its negative. Hence, the function is not symmetric with respect to the pole.
Key Concepts
Symmetry in Polar GraphsRational FunctionsSin Functions
Symmetry in Polar Graphs
Symmetry in polar graphs is an important concept for understanding the behavior of curves plotted in polar coordinates. Polar coordinates use a distance from the origin and an angle to define a point in a plane.
The symmetries we typically look for include:
The symmetries we typically look for include:
- Symmetry with respect to the line \(\theta = \frac{\pi}{2}\)
- Symmetry with respect to the polar axis (the horizontal axis)
- Symmetry with respect to the pole (the origin)
- We substituted \(-\theta\) in \(r = \frac{2}{1+\sin(\theta)}\), getting \(\frac{2}{1-\sin(\theta)}\). This is not the same as the original equation, indicating no symmetry with the polar axis.
Rational Functions
Rational functions play a critical role in various areas of mathematics and are defined as the ratio of two polynomials.
In the exercise, we used the rational function \(r = \frac{2}{1+\sin(\theta)}\) .
This particular function is a ratio of a constant and a polynomial involving a trigonometric function.
The behavior of rational functions can significantly change depending on the numerator and the denominator:
In the exercise, we used the rational function \(r = \frac{2}{1+\sin(\theta)}\) .
This particular function is a ratio of a constant and a polynomial involving a trigonometric function.
The behavior of rational functions can significantly change depending on the numerator and the denominator:
- Zeros: Occur when the numerator of the function equals zero.
- Undefined Points: Occur when the denominator equals zero, as division by zero is undefined.
- Horizontal Asymptotes: Appear when the degree of the polynomial in the denominator is equal to or greater than the numerator.
Sin Functions
Sin functions are foundational to trigonometry and play a significant part in describing wave-like shapes and periodic behaviors.
When applied in polar coordinates, they help define points on a graph using \(r\) as the radius and \(\theta\) as the angle. In the exercise, the given function is \(r = \frac{2}{1+\sin(\theta)}\), employing a trigonometric function.Sin functions have unique features in polar graphs:
When applied in polar coordinates, they help define points on a graph using \(r\) as the radius and \(\theta\) as the angle. In the exercise, the given function is \(r = \frac{2}{1+\sin(\theta)}\), employing a trigonometric function.Sin functions have unique features in polar graphs:
- Periodicity: The function repeats its values over specific intervals, typically every \(2\pi\).
- Symmetry: Sin functions often create symmetrical shapes, especially around the polar axis.
- Maximum and Minimum: The sinusoidal nature causes alternate crests and troughs, representing maximum and minimum values.
Other exercises in this chapter
Problem 15
Identify the conic and sketch its graph. $$r=\frac{3}{1-\cos \theta}$$
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Find the slope of the line with inclination \(\theta\). $$\boldsymbol{\theta}=1.81 \text { radians }$$
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(A) sketch the curve represented by the parametric equations (indicate the orientation of the curve) and (b) eliminate the parameter and write the resulting rec
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