Problem 15
Question
Suppose that \(\sum_{i=1}^{10} a_{i}=40\) and \(\sum_{i=1}^{10} b_{i}=50 .\) Calculate each of the following. $$ \sum_{i=1}^{10}\left(a_{i}+b_{i}\right) $$
Step-by-Step Solution
Verified Answer
The sum \( \sum_{i=1}^{10} (a_i + b_i) \) is 90.
1Step 1: Understanding the Problem
We are given two separate summations, \( \sum_{i=1}^{10} a_{i} = 40 \) and \( \sum_{i=1}^{10} b_{i} = 50 \), and we need to find the value of \( \sum_{i=1}^{10}(a_{i} + b_{i}) \). This requires us to combine the individual sums to obtain the desired result.
2Step 2: Rewriting the Target Expression
The expression \( \sum_{i=1}^{10}(a_{i} + b_{i}) \) can be rewritten by separating the sum of \(a_i\)s and \(b_i\)s. This can be expressed as: \( \sum_{i=1}^{10} a_i + \sum_{i=1}^{10} b_i \).
3Step 3: Substituting Known Values
Using the given data, substitute \( \sum_{i=1}^{10} a_i = 40 \) and \( \sum_{i=1}^{10} b_i = 50 \) into the expression from the previous step. This gives us: \( 40 + 50 \).
4Step 4: Calculating the Result
Now simply add the two numbers: \( 40 + 50 = 90 \). This is the value of \( \sum_{i=1}^{10} (a_i + b_i) \).
Key Concepts
Algebraic ManipulationSummation PropertiesProblem Solving in Calculus
Algebraic Manipulation
In mathematics, algebraic manipulation involves rearranging and simplifying expressions to make them easier to solve or understand. This can include combining like terms, factoring, or using properties of operations, such as addition or multiplication, to rearrange terms.
In our exercise, algebraic manipulation is used by recognizing that the addition of two separate sums can simplify the expression. We are asked to find the sum of two sequences, \( \sum_{i=1}^{10} (a_i + b_i) \).
To handle this, we first separate the expression into two distinct sums: \( \sum_{i=1}^{10} a_i + \sum_{i=1}^{10} b_i \).
In our exercise, algebraic manipulation is used by recognizing that the addition of two separate sums can simplify the expression. We are asked to find the sum of two sequences, \( \sum_{i=1}^{10} (a_i + b_i) \).
To handle this, we first separate the expression into two distinct sums: \( \sum_{i=1}^{10} a_i + \sum_{i=1}^{10} b_i \).
- This step involves rearranging the terms within the summation to break it down into parts we already know the solution to.
- By rewriting the expression, we directly apply known information on each part of the problem and can therefore substitute the given values.
Summation Properties
Summation is a fundamental concept in calculus that involves adding a sequence of numbers systematically. It has special properties that help simplify calculations and problem-solving. One key property used here is the distributive property of summation over addition.
This property allows us to split the sum of two sequences into separate sums:
By recognizing and using this property, arithmetic tasks become manageable by breaking them into simpler, manageable parts.
This property allows us to split the sum of two sequences into separate sums:
- \( \sum_{i=1}^{10} (a_i + b_i) = \sum_{i=1}^{10} a_i + \sum_{i=1}^{10} b_i \)
By recognizing and using this property, arithmetic tasks become manageable by breaking them into simpler, manageable parts.
Problem Solving in Calculus
Problem solving in calculus often requires a combination of understanding concepts, recognizing patterns, and applying known techniques. In this exercise, solving the problem relies primarily on comprehending the behavior of sums and their properties.
The steps include:
These steps illustrate how mathematical reasoning in calculus isn’t just about computation but about recognizing relationships and knowing how to use them effectively. Such skills are vital in tackling broader, more complex problems in mathematics and beyond.
The steps include:
- Interpreting what the problem is asking, which forms the basis of a strategy to reach a solution.
- Simplifying or restructuring mathematical expressions using known rules, as demonstrated by rewriting the sum.
These steps illustrate how mathematical reasoning in calculus isn’t just about computation but about recognizing relationships and knowing how to use them effectively. Such skills are vital in tackling broader, more complex problems in mathematics and beyond.
Other exercises in this chapter
Problem 14
Find the average value of the function on the given interval. $$ G(v)=\frac{\sin v \cos v}{\sqrt{1+\cos ^{2} v}} ; \quad[0, \pi / 2] $$
View solution Problem 14
use the Second Fundamental Theorem of Calculus to evaluate each definite integral. $$ \int_{0}^{1}\left(x^{4 / 3}-2 x^{1 / 3}\right) d x $$
View solution Problem 15
Suppose that \(\int_{0}^{1} f(x) d x=2, \int_{1}^{2} f(x) d x=3, \int_{0}^{1} g(x) d x=-1\) and \(\int_{0}^{2} g(x) d x=4 .\) Use properties of definite integra
View solution Problem 15
Find all values of \(c\) that satisfy the Mean Value Theorem for Integrals on the given interval. $$ f(x)=\sqrt{x+1} ; \quad[0,3] $$
View solution