Problem 15
Question
Suppose that a woman weighing \(130 \mathrm{lb}\) and wearing highheeled shoes momentarily places all her weight on the heel of one foot. If the area of the heel is \(0.50 \mathrm{in}^{2}\), calculate the pressure exerted on the underlying surface in (a) kilopascals, (b) atmospheres, and (c) pounds per square inch.
Step-by-Step Solution
Verified Answer
The pressure exerted on the surface by the woman's heel is approximately (a) 1793 kilopascals (kPa), (b) 17.69 atmospheres (atm), and (c) 260 pounds per square inch (psi).
1Step 1: Calculate the pressure in pounds per square inch (psi)
Use the formula for pressure to find the pressure exerted on the surface:
Pressure (P) = Force (F) / Area (A)
The force comes from the woman's weight, which is given as 130 lb. The area of the heel is given as 0.50 in². Plug in their values:
P = 130 lb / 0.50 in² = 260 psi
2Step 2: Convert the pressure to kilopascals (kPa)
To convert the pressure from psi to kPa, we can use the following conversion factor:
1 psi ≈ 6.895 kPa
Now, multiply the pressure in psi by the conversion factor:
260 psi × 6.895 kPa/psi ≈ 1793 kPa
3Step 3: Convert the pressure to atmospheres (atm)
To convert the pressure from psi to atm, we can use the following conversion factor:
1 psi ≈ 0.06804 atm
Now, multiply the pressure in psi by the conversion factor:
260 psi × 0.06804 atm/psi ≈ 17.69 atm
#Conclusion#
The pressure exerted on the surface by the woman's heel is approximately:
(a) 1793 kilopascals (kPa)
(b) 17.69 atmospheres (atm)
(c) 260 pounds per square inch (psi)
Key Concepts
Understanding KilopascalsUnderstanding AtmospheresUnderstanding Pounds per Square Inch
Understanding Kilopascals
Pressure is a measure of force distributed over an area, and the kilopascal (kPa) is one common unit used to express pressure. One Pascal (Pa) is equal to one Newton per square meter, and a kilopascal is just 1000 Pascals.
This means that it simplifies the expression of larger pressure values, as kilopascals are used for practical applications where values might otherwise become large. For example, atmospheric pressure at sea level is about 101.3 kPa.
- The prefix 'kilo-' signifies a thousand, so a conversion from Pascals to kilopascals requires dividing by 1000.
- In the exercise example, converting from pounds per square inch to kilopascals involves using the factor 1 psi ≈ 6.895 kPa, directly multiplying to yield approximately 1793 kPa.
Understanding Atmospheres
The atmosphere (atm) is a unit of measurement that has significance mostly in the context of atmospheric pressure.
Pressure that we naturally encounter in daily life, especially at sea level, is termed 1 atmosphere.
This metric is beneficial because it normalizes the pressure related to the ambient air that surrounds us.
- An atmosphere is defined as 101,325 Pascals, and in conversion from psi, 1 psi ≈ 0.06804 atm.
- In our exercise, this conversion results in an approximate value of 17.69 atmospheres, when applying the pressure exertion of the heel.
Understanding Pounds per Square Inch
Pounds per square inch (psi) is a common unit of pressure primarily used in the United States.
It relates the amount of force (in pounds) applied to one square inch of area.
This unit is quite intuitive in everyday physical scenarios, such as measuring tire pressure or even the force exerted by an object on a surface.
- In the exercise, the woman's weight is 130 pounds applied over the heel's area of 0.5 square inches, calculated straightforwardly as 260 psi.
- Converting to other units, like kilopascals or atmospheres, often involves standard factors - showing how versatile psi can be across different systems.
Other exercises in this chapter
Problem 13
How does a gas compare with a liquid for each of the following properties: (a) density, (b) compressibility, (c) ability to mix with other substances of the sam
View solution Problem 14
(a) A liquid and a gas are moved to larger containers. How does their behavior differ once they are in the larger containers? Explain the difference in molecula
View solution Problem 16
A set of bookshelves rests on a hard floor surface on four legs, each having a cross-sectional dimension of \(3.0 \times 4.1 \mathrm{~cm}\) in contact with the
View solution Problem 17
(a) How high in meters must a column of water be to exert a pressure equal to that of a \(760-\mathrm{mm}\) column of mercury? The density of water is \(1.0 \ma
View solution