Problem 15
Question
Solve the formula for the indicated variable. Show all your steps. Then evaluate the new formula by substituting the given values. Solve \(A=\ell w\) for \(\ell\) Find the value of \(\ell\) when \(A=112\) and \(w=7\)
Step-by-Step Solution
Verified Answer
The length (\(\ell\)) is 16 units.
1Step 1: Solve for Length
To solve for length, \(\ell\), divide both sides of the equation by width, \(w\). It will yield a new formula: \(\ell = \frac{A}{w}\)
2Step 2: Substitute Values
Substitute the given values, \(A=112\) and \(w=7\), into the new equation. So, it becomes \(\ell = \frac{112}{7}\)
3Step 3: Simplify
Simplify the above equation to find the value of length. That gives us \(\ell = 16\)
Key Concepts
Solving EquationsVariable ManipulationSubstitution Method
Solving Equations
In algebra, solving equations is a fundamental skill that involves finding the value of an unknown variable that makes the equation true. When given an equation with a formula such as \[ A = \ell \cdot w \]the task is often to isolate and solve for a specific variable, like \( \ell \). This requires using inverse operations to break down the equation step by step.
If you're beginning with the equation, first identify what operations are connecting your variables. By seeing multiplication in the term \( \ell \cdot w \), you know that the opposite operation, division, will help you isolate one term from the multiplication. Thus, dividing both sides by \( w \) gives you \( \ell \) on its own, as shown:\[ \ell = \frac{A}{w} \]
Always ensure to perform the same operation on both sides of the equation. This keeps the equation balanced and steps you closer to the solution.
If you're beginning with the equation, first identify what operations are connecting your variables. By seeing multiplication in the term \( \ell \cdot w \), you know that the opposite operation, division, will help you isolate one term from the multiplication. Thus, dividing both sides by \( w \) gives you \( \ell \) on its own, as shown:\[ \ell = \frac{A}{w} \]
Always ensure to perform the same operation on both sides of the equation. This keeps the equation balanced and steps you closer to the solution.
Variable Manipulation
Variable manipulation refers to the operations we perform on variables in order to re-arrange equations or solve them. With an equation like \[ A = \ell \cdot w \],rearranging involves manipulating the variables to solve for \( \ell \). Start by moving terms around using basic algebra operations, such as addition, subtraction, multiplication, and division.
The goal is to express the equation in terms of the desired variable. In this case, you divided the entire equation by \( w \), the coefficient of \( \ell \), to isolate \( \ell \). This process of re-arranging simplifies to the formula:\[ \ell = \frac{A}{w} \]
Such manipulation is a crucial algebra skill, allowing you to rearrange and express equations in more useful or desired forms. This skill makes more complex problems manageable and easier to solve.
The goal is to express the equation in terms of the desired variable. In this case, you divided the entire equation by \( w \), the coefficient of \( \ell \), to isolate \( \ell \). This process of re-arranging simplifies to the formula:\[ \ell = \frac{A}{w} \]
Such manipulation is a crucial algebra skill, allowing you to rearrange and express equations in more useful or desired forms. This skill makes more complex problems manageable and easier to solve.
Substitution Method
The substitution method is a powerful tool in algebra where specific values are substituted into an equation to find the unknown variable's value. This method often follows re-arranging an equation to isolate a variable.
Take the newly formed equation:\[ \ell = \frac{A}{w} \]
if you know that \( A = 112 \) and \( w = 7 \), substitute these values in place of \( A \) and \( w \) respectively:\[ \ell = \frac{112}{7} \]
After substitution, compute the value to solve for \( \ell \). In this example, dividing 112 by 7 gives:\[ \ell = 16 \]
The substitution method allows you to evaluate and find numerical solutions easily once the equation is structured correctly.
Take the newly formed equation:\[ \ell = \frac{A}{w} \]
if you know that \( A = 112 \) and \( w = 7 \), substitute these values in place of \( A \) and \( w \) respectively:\[ \ell = \frac{112}{7} \]
After substitution, compute the value to solve for \( \ell \). In this example, dividing 112 by 7 gives:\[ \ell = 16 \]
The substitution method allows you to evaluate and find numerical solutions easily once the equation is structured correctly.
Other exercises in this chapter
Problem 15
Solve the equation. \(-4(x+6)=12\)
View solution Problem 15
Match the percent problem with the equation that represents it. $$39=0.50 b$$
View solution Problem 15
Find the unit rate. Round your answer to the nearest hundredth. 60 to 100
View solution Problem 15
Solve the equation. Round the result to the nearest hundredth. Check the rounded solution. $$ 2.2 x=15 $$
View solution