Problem 15
Question
Solve the following quadratic equations. \((x+2)^{2}=9\)
Step-by-Step Solution
Verified Answer
The solutions are \( x = 1 \) and \( x = -5 \).
1Step 1: Expand the equation
Start by recognizing that \( (x+2)^2 = 9 \) represents a difference of squares. We can solve this by taking the square root of both sides.
2Step 2: Take the square root of both sides
Take the square root of both sides to simplify: \[ \sqrt{(x+2)^2} = \sqrt{9} \] This results in \ x+2 = \pm 3 \.
3Step 3: Solve for the positive case
First, solve for \( x+2 = 3 \). Subtract 2 from both sides: \ x = 3 - 2 \ Therefore, \ x = 1 \.
4Step 4: Solve for the negative case
Next, solve for \( x+2 = -3 \). Subtract 2 from both sides: \ x = -3 - 2 \ Therefore, \ x = -5 \.
5Step 5: Verify the solutions
Substitute \( x = 1 \) and \( x = -5 \) back into the original equation to verify. \( (1+2)^2 = 3^2 = 9 \) and \((-5+2)^2 = (-3)^2 = 9\). Both solutions satisfy the original equation.
Key Concepts
square root methoddifference of squaressolution verification
square root method
The square root method is a useful approach for solving quadratic equations when the equation is in the form of a perfect square. This method involves taking the square root of both sides of the equation to simplify it.
For example, consider the equation \( (x + 2)^2 = 9 \). Here, the left side of the equation is a perfect square. To solve it using the square root method, follow these steps:
For example, consider the equation \( (x + 2)^2 = 9 \). Here, the left side of the equation is a perfect square. To solve it using the square root method, follow these steps:
- Take the square root of both sides: \[ \text{\textbackslash sqrt\textbraceleft (x + 2)\textasciicircum2\textbraceright = \text{\textbackslash sqrt\textbraceleft 9\textbraceright} \] This simplifies to \[ x + 2 = \text{\pm} 3 \]
- \( x + 2 = 3 \)
- \( x + 2 = -3 \)
difference of squares
The term 'difference of squares' refers to a special way of recognizing and solving quadratic equations. This method is most useful for equations that can be expressed as the difference between two perfect squares. However, in the provided exercise, recognizing the form is key to applying the square root method.
In the equation \( (x + 2)^2 = 9 \), observe that both sides are squares: the left side is a squared binomial and the right side is simply a number squared (\(3^2\)).
When an equation is structured this way, it hints at the use of the square root method. Essentially, the difference of squares concept helps identify the simpler path to solve the equation, leading directly to breaking down the problem via square roots.
In the equation \( (x + 2)^2 = 9 \), observe that both sides are squares: the left side is a squared binomial and the right side is simply a number squared (\(3^2\)).
When an equation is structured this way, it hints at the use of the square root method. Essentially, the difference of squares concept helps identify the simpler path to solve the equation, leading directly to breaking down the problem via square roots.
solution verification
Verifying your solutions is a critical step in solving quadratic equations. It ensures that the solutions you have found actually satisfy the original equation.
For the provided exercise, the solutions found are \( x = 1 \) and \( x = -5 \). To verify:
1. Substitute \( x = 1 \) back into the original equation \( (x + 2)^2 = 9 \):
For the provided exercise, the solutions found are \( x = 1 \) and \( x = -5 \). To verify:
1. Substitute \( x = 1 \) back into the original equation \( (x + 2)^2 = 9 \):
- \( (1 + 2)^2 = 3^2 = 9 \)
- This verifies that \( x = 1 \) is a correct solution.
- \( (-5 + 2)^2 = (-3)^2 = 9 \)
- This verifies that \( x = -5 \) is also a correct solution.
Other exercises in this chapter
Problem 13
Solve the following quadratic equations. \(7 p^{2}+10=26\)
View solution Problem 14
Solve the following quadratic equations. \(2 q^{2}+5=30\)
View solution Problem 16
Solve the following quadratic equations. \((y-5)^{2}=36\)
View solution Problem 17
Solve the following quadratic equations. \((u-6)^{2}=64\)
View solution