Problem 15
Question
Solve the equation by completing the square. \(x^{2}-6 x-11=0\)
Step-by-Step Solution
Verified Answer
The solutions are \(x = 3 + 2\sqrt{5}\) and \(x = 3 - 2\sqrt{5}\).
1Step 1: Move Constant to the Right Side
Start by isolating the quadratic and linear terms. Move the constant term to the right side of the equation:\[x^2 - 6x = 11\]
2Step 2: Complete the Square
To complete the square, find the number that will turn the left side into a perfect square trinomial. Take half the coefficient of \(x\), square it, and add it to both sides.Half of \(-6\) is \(-3\). Squaring it gives \(9\). Add \(9\) to both sides:\[x^2 - 6x + 9 = 11 + 9\]This becomes:\[(x - 3)^2 = 20\]
3Step 3: Solve for \(x\)
Solve for \(x\) by taking the square root of both sides of the equation:\[x - 3 = \pm \sqrt{20}\]\[x - 3 = \pm 2\sqrt{5}\]Add 3 to both sides to solve for \(x\):\[x = 3 \pm 2\sqrt{5}\]
Key Concepts
Completing the SquareQuadratic EquationAlgebraic Techniques
Completing the Square
Completing the square is a method used to solve quadratic equations. It transforms a standard quadratic equation, like \( ax^2 + bx + c = 0 \), into a perfect square trinomial form. Here’s how it works:
- Move the constant term to the other side of the equation. This isolates the quadratic and linear terms.
- Take half of the coefficient of the linear term (\(b\)), square it, and add this square to both sides. This process helps form a perfect square trinomial on the left side.
- Rewrite the trinomial as the square of a binomial. You can now solve it by taking the square root of both sides to find the values of \(x\).
Quadratic Equation
A quadratic equation is a second-degree polynomial, typically written in the form \(ax^2 + bx + c = 0\). It represents a parabola on a graph, and its solutions correspond to the points where the parabola intersects the x-axis.
Key features of quadratic equations include:
Key features of quadratic equations include:
- The leading coefficient \(a\) impacts the parabola's direction. If \(a > 0\), the parabola opens upwards; if \(a < 0\), it opens downwards.
- The solutions can be found using methods like factoring, completing the square, or the quadratic formula.
- Quadratic equations can have two solutions, one solution, or no real solutions, determined by the discriminant \(b^2 - 4ac\).
Algebraic Techniques
Algebraic techniques are the methods used to solve equations and simplify expressions. For quadratic equations, several techniques can be applied, such as:
- Factoring: Breaking down the quadratic into multiplicative components, useful when the equation is easily factorable.
- Completing the Square: Turning the quadratic into a perfect square trinomial, as we did by adding \(9\) to both sides of the equation.
- Quadratic Formula: A universal solution method, \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), useful when other methods are cumbersome.
Other exercises in this chapter
Problem 15
Evaluate the expression and write the result in the form \(a+b i .\) $$ \left(7-\frac{1}{2} i\right)-\left(5+\frac{3}{2} i\right) $$
View solution Problem 15
1–54 ? Find all real solutions of the equation. $$ \frac{1}{x-1}+\frac{1}{x+2}=\frac{5}{4} $$
View solution Problem 15
\(9- 46\) The given equation is either linear or equivalent to a linear equation. Solve the equation. $$ -7 w=15-2 w $$
View solution Problem 16
Solve the equation. $$ \left|\frac{3}{5} x+2\right|-\frac{1}{2}=4 $$
View solution