Problem 15
Question
Solve each equation. Check each solution. See Examples 1 through \(6 .\) \(1.7 x=10.71\)
Step-by-Step Solution
Verified Answer
The solution is \(x = 6.3\).
1Step 1: Identify the Equation
The equation given is a simple linear equation: \(1.7x = 10.71\). Our goal is to find the value of \(x\) that satisfies this equation.
2Step 2: Isolate the Variable
To isolate \(x\), divide both sides of the equation by 1.7: \[x = \frac{10.71}{1.7}\] This step simplifies to finding \(x\) by performing the division.
3Step 3: Perform the Division
Calculate \(\frac{10.71}{1.7}\) to find the value of \(x\). Performing the division: \[x = 6.3\] Thus, the solution for the equation is \(x = 6.3\).
4Step 4: Verify the Solution
To ensure the solution is correct, substitute \(x = 6.3\) back into the original equation and check:\[1.7 \times 6.3 = 10.71\]Calculate the left side: \(1.7 \times 6.3 = 10.71\), which matches the right side of the equation, confirming that \(x = 6.3\) is the correct solution.
Key Concepts
Linear EquationsDivision OperationChecking SolutionsVariable Isolation
Linear Equations
Linear equations are fundamental in mathematics. They form straight lines when graphed and have a standard format of \(ax + b = c\) where \(a\), \(b\), and \(c\) are constants, and \(x\) is the variable to solve for. In this exercise, the equation is simplified through operations to find the unknown value of \(x\).
Linear equations are straightforward because they only have one variable raised to the power of one. They are essential for understanding more complex algebraic principles.
Here is why linear equations are important:
Linear equations are straightforward because they only have one variable raised to the power of one. They are essential for understanding more complex algebraic principles.
Here is why linear equations are important:
- They model real-world problems and can help in decision making.
- They're foundational for understanding functions and graphing.
- They are an integral part of high school and college algebra curricula.
Division Operation
The division operation is a key step in solving linear equations. It helps in simplifying the equation and finding the value of the variable. In the original exercise, division is used to isolate \(x\).
When performing division in algebra:
This brings clarity and precision in solving and checking results, as demonstrated in the exercise.
When performing division in algebra:
- Ensure both sides of the equation are divided by the same non-zero number to maintain equality.
- Double-check calculations to avoid mistakes, especially with decimals.
This brings clarity and precision in solving and checking results, as demonstrated in the exercise.
Checking Solutions
After solving an equation, it's crucial to verify the solution. This means plugging the solution back into the original equation to see if it holds true.
Reasons for checking solutions include:
Reasons for checking solutions include:
- It confirms the accuracy of calculations.
- Identifies potential mistakes in earlier steps.
- It provides confidence in the final answer.
Variable Isolation
Variable isolation is about getting the variable alone on one side of the equation. This forms the core part of solving linear equations.
Here's how to effectively isolate variables:
In this exercise, we isolate \(x\) by dividing both sides by 1.7, which leads directly to finding \(x = 6.3\), the correct solution.
Here's how to effectively isolate variables:
- Use inverse operations like addition, subtraction, multiplication, or division.
- Maintain equilibrium by applying these operations to both sides of the equation.
- Reorganize and simplify until the variable stands alone.
In this exercise, we isolate \(x\) by dividing both sides by 1.7, which leads directly to finding \(x = 6.3\), the correct solution.
Other exercises in this chapter
Problem 15
Solve each equation. See Examples 1 and \(2 .\) $$ -2 y-10=5 y+18 $$
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Solve each equation. Don't forget to first simplify each side of the equation, if possible. Check each solution. See Examples 5 through 7 . $$ \frac{5}{6} x+\fr
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Solve each formula for the specified variable. \(3 x+y=7\) for \(y\)
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A plumber gave an estimate for the renovation of a kitchen. Her hourly pay is \(\$ 27\) per hour and the plumbing parts will cost \(\$ 80 .\) If her total estim
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