Problem 15
Question
Simplify each sum. \(\frac{5 x}{x^{2}-x-6}+\frac{4}{x^{2}+4 x+4}\)
Step-by-Step Solution
Verified Answer
\(\frac{5 x^{2}+10 x+4}{(x-3)(x+2)^{2}}\).
1Step 1: Factorize the denominators
The first fraction has a denominator \(x^{2}-x-6\), which can be factorized into \((x-3)(x+2)\). The second fraction has a denominator \(x^{2}+4x+4\), which can be factored into \((x+2)^{2}\). Thus, the fractions become: \(\frac{5 x}{(x-3)(x+2)}+\frac{4}{(x+2)^{2}}\).
2Step 2: Find a common denominator and simplify
The common denominator of the fractions is \((x-3)(x+2)^{2}\). So, we need to multiply the first fraction by \((x+2)/(x+2)\) to get the same denominator for both fractions: \(\frac{5 x(x+2)}{(x-3)(x+2)^{2}}+\frac{4}{(x+2)^{2}}\). After addition and simplification, the result is: \(\frac{5 x^{2}+10 x+4}{(x-3)(x+2)^{2}}\).
3Step 3: Combine similar terms
Upon combining similar terms, we get: \(\frac{5 x^{2}+10 x+4}{(x-3)(x+2)^{2}}\).
Key Concepts
Factoring PolynomialsLeast Common DenominatorSimplifying Expressions
Factoring Polynomials
Factoring polynomials is like finding the building blocks of a polynomial. Imagine a polynomial as a huge block tower. Factoring means breaking it down into simpler, smaller blocks.
For example, the polynomial \(x^2 - x - 6\) can be broken into \((x - 3)(x + 2)\). This tells us that if you multiply \((x - 3)\) and \((x + 2)\), you will get back to the original big tower, \(x^2 - x - 6\).
For example, the polynomial \(x^2 - x - 6\) can be broken into \((x - 3)(x + 2)\). This tells us that if you multiply \((x - 3)\) and \((x + 2)\), you will get back to the original big tower, \(x^2 - x - 6\).
- It makes complex algebraic expressions easier to manage.
- Useful for finding zeros or solving equations.
- First, try to find two numbers that multiply to the constant term and add to the middle coefficient.
- Then express the polynomial as a product of simpler binomials.
Least Common Denominator
When you want to add or subtract fractions, they need to have the same denominator, just like making sure everyone speaks the same language for better communication. The least common denominator (LCD) is the smallest possible denominator that makes both fractions compatible.
Take two fractions, \(\frac{5x}{(x-3)(x+2)}\) and \(\frac{4}{(x+2)^2}\). They need a common ground, which in this case is \((x-3)(x+2)^2\).
Take two fractions, \(\frac{5x}{(x-3)(x+2)}\) and \(\frac{4}{(x+2)^2}\). They need a common ground, which in this case is \((x-3)(x+2)^2\).
- Multiply the denominators of both fractions to find a common one.
- Adjust the numerators accordingly, being fair and logical as you adjust each fraction to have the same base.
Simplifying Expressions
Simplifying expressions is all about tidying up; think of it as cleaning a messy room. The goal is to make expressions neater and easier to understand or work with.
When you simplify, you combine like terms and reduce expressions to their simplest form, removing any clutter or redundancy.
Simplifying is the final touch, much like making a presentation visually appealing to better convey the underlying message.
When you simplify, you combine like terms and reduce expressions to their simplest form, removing any clutter or redundancy.
- Using known identities and algebraic rules helps make expressions clearer.
- Always aim to reduce the expression to involve the fewest number of terms with no unnecessary parts.
Simplifying is the final touch, much like making a presentation visually appealing to better convey the underlying message.
Other exercises in this chapter
Problem 15
Divide. State any restrictions on the variables. $$ \frac{6 x+6 y}{x-y} \div \frac{18}{5 x-5 y} $$
View solution Problem 15
Describe the vertical asymptotes and holes for the graph of each rational function. $$ y=\frac{x+5}{x^{2}+9} $$
View solution Problem 15
Sketch the asymptotes and the graph of each equation. \(y=\frac{-2}{x}-3\)
View solution Problem 15
Suppose that \(x\) and \(y\) vary inversely. Write a function that models each inverse variation and find \(y\) when \(x=10 .\) $$ x=5 \text { when } y=-\frac{1
View solution