Problem 15
Question
Simplify each boolean expression using the laws of boolean algebra. $$w x y z+w^{\prime} x y^{\prime} z^{\prime}+w x y z^{\prime}+w^{\prime} x y^{\prime} z$$
Step-by-Step Solution
Verified Answer
The simplified boolean expression using the laws of boolean algebra is: \(w'xy'z' + wxz'\).
1Step 1: Rewrite the boolean expression
We will first rewrite the expression using the latex environment to make it easier to read:
\[
+w'xyz'+wxyz'+w'xy'z
\]
2Step 2: Apply Consensus theorem
Next, apply the Consensus theorem to the expression. The consensus of the terms \(A B + A'C + BC\) can be written as \(AB + A'C\).
In our case, we have:
- \(A = w'\)
- \(B = xy'z'\)
- \(A' = w\)
- \(C = xz'\)
So, the original expression is in the form \(A B + A'C + BC\). By applying the Consensus theorem, we can simplify this expression to \(AB + A'C\):
\[
w'xy'z' + wxz'
\]
3Step 3: Final Simplified Expression
Now that we have applied the Consensus theorem, we have simplified the boolean expression to the following form:
\[
w'xy'z' + wxz' \text{ (Simplified boolean expression)}
\]
Key Concepts
Boolean Expression SimplificationConsensus TheoremBoolean Algebra Laws
Boolean Expression Simplification
Simplifying Boolean expressions involves reducing them to simpler forms. This process aims to make the expressions more efficient by using fewer terms or simpler operations. Boolean algebra provides a set of rules and laws that allow us to systematically reduce expressions, thereby making them easier to understand, implement, and compute.
There are several tools at your disposal when simplifying Boolean expressions:
There are several tools at your disposal when simplifying Boolean expressions:
- The elimination of terms using basic identities, such as the Law of Identity e.g., \(X \cdot 1 = X\)
- The Law of Nullification e.g., \(X \cdot 0 = 0\)
- The Law of Idempotent e.g., \(X + X = X\)
- Distribution, combining, and absorption laws ensure expressions are as compact as possible.
Consensus Theorem
The Consensus theorem in Boolean algebra is one of the most powerful tools for simplifying Boolean expressions. It states that the consensus term of the Boolean function can be omitted without altering the overall function's outcome. The theorem can be mathematically expressed as \(AB + A'C + BC = AB + A'C\)
Here's how it works:
Here's how it works:
- If a Boolean expression includes three terms of the form \(AB + A'C + BC\), it can be simplified by removing the "consensus" term, \(BC\).
- The consensus term is a redundancy that does not affect the logical output. Its removal results in a simpler expression \(AB + A'C\).
Boolean Algebra Laws
Boolean algebra is a mathematical framework crucial for computer science, electronics, and digital logic design. It is based on a set of laws that govern the manipulation of binary variables. Here are a few fundamental laws that guide Boolean expression simplification:
- Commutative Law: This law allows for the rearrangement of variables. Expressions such as \(A + B\) and \(B + A\) are equivalent.
- Associative Law: This law permits the regrouping of variables. Expressions like \((A + B) + C\) and \(A + (B + C)\) are seen as equal.
- Distributive Law: Similar to distribution in traditional algebra. For instance, \(A(B + C) = AB + AC\).
- Identity Law: Using 1 and 0 to retain variable values. Examples are \(A + 0 = A\) and \(A \, \cdot \, 1 = A\).
- Null Law: Expresses the annihilation effect of 0 and 1. Formula-like expressions are \(A \, \cdot \, 0 = 0\) and \(A + 1 = 1\).
- Domination Law: Describes the dominance of 0 and 1 over variables. Expressions like \(A + 1 = 1\) or \(A \, \cdot \, 0 = 0\).
Other exercises in this chapter
Problem 14
Find the DNF of each boolean function. $$f(x, y)=x \downarrow y$$
View solution Problem 14
Find the DNF of each boolean function. $$f(x, y)=x \downarrow y$$
View solution Problem 15
Construct a logic table for each boolean function defined by each boolean expression. $$x y z+x(y z)^{\prime}$$
View solution Problem 15
The set \(D_{70}=\\{1,2,5,7,10,14,35,70\\}\) of positive factors of 70 is a boolean algebra under the operations \(\oplus, \odot,\) and ' defined by \(x \oplus
View solution