Problem 15
Question
Prove the identity. $$\frac{\tan x}{\sec x}=\sin x$$
Step-by-Step Solution
Verified Answer
Question: Prove the identity \(\frac{\tan x}{\sec x}=\sin x\)
Solution:
To prove the given identity, follow these steps:
Step 1: Rewrite the expressions in terms of sine and cosine.
Replace \(\tan x\) with \(\frac{\sin x}{\cos x}\) and \(\sec x\) with \(\frac{1}{\cos x}\).
Step 2: Substitute the expressions into the identity.
The identity becomes:
$$\frac{\frac{\sin x}{\cos x}}{\frac{1}{\cos x}}=\sin x$$
Step 3: Simplify the left side of the identity.
Rewrite the expression as a product:
$$\frac{\sin x}{\cos x} \cdot \frac{\cos x}{1} =\sin x$$
The \(\cos x\) in the numerator and denominator cancel out, leaving:
$$\sin x=\sin x$$
Thus, the identity is proven.
1Step 1: Rewrite the expressions in terms of sine and cosine.
We will rewrite the expression \(\frac{\tan x}{\sec x}\) in terms of sine and cosine. The tangent function, \(\tan x\), can be expressed as \(\frac{\sin x}{\cos x}\), while the secant function, \(\sec x\), can be expressed as \(\frac{1}{\cos x}\).
2Step 2: Substitute the expressions into the identity
By substituting the expressions from step 1, our identity now becomes:
$$\frac{\frac{\sin x}{\cos x}}{\frac{1}{\cos x}}=\sin x$$
3Step 3: Simplify the left side of the identity
Now, we will simplify the left side of the equation. To do this, we can rewrite the expression as a product:
$$\frac{\sin x}{\cos x} \cdot \frac{\cos x}{1} =\sin x$$
Notice that the \(\cos x\) in the numerator and denominator will cancel out:
$$\frac{\sin x}{\cancel{\cos x}} \cdot \frac{\cancel{\cos x}}{1} =\sin x$$
Leaving us with:
$$\sin x=\sin x$$
The identity has been proven.
Key Concepts
Tangent FunctionSecant FunctionSine Function
Tangent Function
The tangent function, often denoted as \( \tan x \), is a fundamental trigonometric function. It is defined using the sine and cosine functions. The relationship can be expressed as:\[ \tan x = \frac{\sin x}{\cos x} \]This equation illustrates that the tangent function is the ratio of the sine of angle \( x \) to the cosine of angle \( x \). It plays a crucial role in trigonometry, helping to solve right-angled triangle problems and analyze periodic behavior.
- The tangent function is periodic with a period of \( \pi \) radians.
- It is important to note that \( \tan x \) is undefined when \( \cos x = 0 \), which occurs at \( x = \frac{\pi}{2} + n\pi \), where \( n \) is an integer.
- This function is positive in the first and third quadrants of the unit circle, and negative in the second and fourth.
Secant Function
The secant function, denoted \( \sec x \), is another critical trigonometric function. It is the reciprocal of the cosine function. The definition is as follows:\[ \sec x = \frac{1}{\cos x} \]This implies that the secant function is undefined where the cosine function equals zero. These points occur at \( x = \frac{\pi}{2} + n\pi \), where \( n \) is any integer.
- Since \( \sec x \) is the reciprocal of \( \cos x \), it inherits the properties related to the sign of \( \cos x \): positive in the first and fourth quadrants, negative in the second and third.
- The secant function has a period of \( 2\pi \), like the cosine function.
- Its role is vital when working with trigonometric identities, especially those requiring transformations or inversions of cosine values.
Sine Function
The sine function, represented as \( \sin x \), is one of the primary trigonometric functions. It is critical in describing wave patterns, circular motion, and oscillations in physics and engineering.
- The sine function has a range of values from \(-1\) to \(1\).
- It is periodic with a period of \( 2\pi \), which means it repeats its values every \( 2\pi \) radians.
- The function is defined as the y-coordinate of the corresponding angle \( x \) on the unit circle.
Other exercises in this chapter
Problem 15
Use your knowledge of special values to find the exact solutions of the equation. $$\sin x=\sqrt{3} / 2$$
View solution Problem 15
Rewrite the given expression in terms of \(\sin x\) and \(\cos x\). $$\cos \left(x-\frac{3 \pi}{2}\right)$$
View solution Problem 16
Use the half-angle identities to evaluate the given expression exactly. $$\sin \frac{5 \pi}{8}$$
View solution Problem 16
Use a calculator in radian mode to approximate the functional value. $$\cos ^{-1} .76$$
View solution