Problem 15
Question
Prove the identity. \(\cosh (x+y)=\cosh x \cosh y+\sinh x \sinh y\)
Step-by-Step Solution
Verified Answer
Using the definitions of hyperbolic sine and cosine functions, we find expressions for \(\sinh(x+y)\) and \(\cosh(x+y)\). Then, we evaluate expressions for the products of \(\cosh x \cdot \cosh y\) and \(\sinh x \cdot \sinh y\) and expand the expressions. By combining the terms and simplifying, we prove the identity \(\cosh (x+y) = \cosh x \cdot \cosh y + \sinh x \cdot \sinh y\).
1Step 1: Using the definitions of sinh and cosh, we can find expressions for sinh(x+y) and cosh(x+y): \[\sinh(x+y) = \frac{e^{x+y} - e^{-(x+y)}}{2}\] \[\cosh(x+y) = \frac{e^{x+y} + e^{-(x+y)}}{2}\] #Step 2: Simplify sinh(x+y) expression
Using properties of exponents, let's simplify the expression for \(\sinh(x+y)\):
\[\sinh(x+y) = \frac{e^x e^y - e^{-x}e^{-y}}{2}\]
#Step 3: Simplify cosh(x+y) expression
2Step 2: Similarly, let's simplify the expression for \(\cosh(x+y)\): \[\cosh(x+y) = \frac{e^x e^y + e^{-x} e^{-y}}{2}\] #Step 4: Evalute expressions for products of sinh, cosh and their combinations
Now we need to find the expressions for the following combinations using the definitions of sinh and cosh:
1. \(\cosh x \cdot \cosh y\)
2. \(\sinh x \cdot \sinh y\)
\[\cosh x \cdot \cosh y = \frac{e^x + e^{-x}}{2} \cdot \frac{e^y + e^{-y}}{2}\]
\[\sinh x \cdot \sinh y = \frac{e^x - e^{-x}}{2} \cdot \frac{e^y - e^{-y}}{2}\]
#Step 5: Expand the expressions
3Step 3: Now let's expand the expressions in step 4: \[\cosh x \cdot \cosh y = \frac{e^{x+y} + e^{-x+y} + e^{x-y} + e^{-x-y}}{4}\] \[\sinh x \cdot \sinh y = \frac{- e^{-x+y} - e^{x-y} + e^{x+y} + e^{-x-y}}{4}\] #Step 6: Combine terms and prove the identity
Next, let's add the expressions for \(\cosh x \cdot \cosh y\) and \(\sinh x \cdot \sinh y\) and simplify:
\[\cosh x \cdot \cosh y + \sinh x \cdot \sinh y = \frac{e^{x+y} + e^{-x+y} + e^{x-y} + e^{-x-y}}{4} + \frac{- e^{-x+y} - e^{x-y} + e^{x+y} + e^{-x-y}}{4}\]
\[\cosh x \cdot \cosh y + \sinh x \cdot \sinh y = \frac{2e^{x+y} + 2e^{-x-y}}{4}\]
\[\cosh x \cdot \cosh y + \sinh x \cdot \sinh y = \frac{e^{x+y} + e^{-x-y}}{2}\]
Now, compare the results of Step 3 and 6:
\[\cosh(x+y) = \frac{e^{x+y} + e^{-x-y}}{2}\]
\[\cosh x \cdot \cosh y + \sinh x \cdot \sinh y = \frac{e^{x+y} + e^{-x-y}}{2}\]
As both sides are equal, we've proven the identity:
\[\cosh (x+y) = \cosh x \cdot \cosh y + \sinh x \cdot \sinh y\]
Key Concepts
Hyperbolic FunctionsSinhCoshExponential Functions
Hyperbolic Functions
Hyperbolic functions are analogs of the well-known trigonometric functions but based on hyperbolas instead of circles. These functions have significant applications in calculus, complex numbers, and various branches of physics and engineering.
They often appear when solving linear differential equations and in calculations involving exponential functions.
Understanding these connections allows us to apply them in solving various mathematical problems effectively.
They often appear when solving linear differential equations and in calculations involving exponential functions.
- Sinh, or hyperbolic sine, which we'll discuss more in depth, is the hyperbolic counterpart of the sine function.
- Cosh, or hyperbolic cosine, resembles the cosine function but has its unique properties and uses.
Understanding these connections allows us to apply them in solving various mathematical problems effectively.
Sinh
The hyperbolic sine function, denoted as sinh, is defined in terms of exponential functions.
Its definition is \[\sinh(x) = \frac{e^x - e^{-x}}{2}\] This definition makes it clear that sinh is closely tied to exponential growth and decay.
This behavior is crucial in contexts where modeling rapid changes or reactions in systems is needed.
Its definition is \[\sinh(x) = \frac{e^x - e^{-x}}{2}\] This definition makes it clear that sinh is closely tied to exponential growth and decay.
- The simple structure enables us to express combinations like sinh(x+y) using properties of exponents, leading to higher-level simplifications.
- One notable identity involves the addition formula, which can be proven using the exponential formula: \[\sinh(x+y) = \sinh x \cosh y + \cosh x \sinh y\]
This behavior is crucial in contexts where modeling rapid changes or reactions in systems is needed.
Cosh
The hyperbolic cosine function, abbreviated as cosh, is another critical hyperbolic function.
Its defining formula via exponential expressions is:\[\cosh(x) = \frac{e^x + e^{-x}}{2}\]This definition highlights its symmetry and stability.
Understanding cosh's behavior is essential, given its role in shaping various physical and theoretical models in science and engineering.
Its defining formula via exponential expressions is:\[\cosh(x) = \frac{e^x + e^{-x}}{2}\]This definition highlights its symmetry and stability.
- Cosh is even, meaning \(\cosh(-x) = \cosh(x)\), which provides unique symmetry around the y-axis.
- It is frequently used in expressing hyperbolic identities and modeling phenomena like hanging cables (catenary) and certain mechanical systems.
Understanding cosh's behavior is essential, given its role in shaping various physical and theoretical models in science and engineering.
Exponential Functions
Exponential functions are foundational for understanding hyperbolic functions.
These functions are expressed in the form \(e^x\), where \(e\) is Euler's number, approximately 2.718.
When you see identities involving hyperbolic functions, they are often reduced to manipulating exponential terms, making their mastery crucial for deeper mathematical studies.
These functions are expressed in the form \(e^x\), where \(e\) is Euler's number, approximately 2.718.
- Exponential functions describe growth and decay processes, from population increases to radioactive decay.
- Their properties, like \(e^{a+b} = e^a \cdot e^b\), are pivotal in simplifying expressions in calculus and hyperbolic function proofs.
When you see identities involving hyperbolic functions, they are often reduced to manipulating exponential terms, making their mastery crucial for deeper mathematical studies.
Other exercises in this chapter
Problem 14
In Exercises \(13-34\), find the volume of the solid generated by revolving the region bounded by the graphs of the equations and/or inequalities about the indi
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In Exercises \(9-40\), sketch the region bounded by the graphs of the given equations and find the area of that region. $$ y=x^{2}-4 x, \quad y=-x+4 $$
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Find the centroid of the region bounded by the graphs of the given equations. $$ y=2 x-x^{2}, \quad y=0 $$
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A trough has vertical ends that are equilateral triangles with sides of length \(2 \mathrm{ft}\). If the trough is filled with water to a depth of \(1 \mathrm{f
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