Problem 15
Question
Mortgage A couple secures a 30 -year loan of \(\$ 100,000\) at \(9 \frac{3}{4} \%\) per year, compounded monthly, to buy a house. (a) What is the amount of their monthly payment? (b) What total amount will they pay over the 30 -year period? (c) If, instead of taking the loan, the couple deposits the monthly payments in an account that pays \(9 \frac{3}{4} \%\) interest per year, compounded monthly, how much will be in the account at the end of the 30 -year period?
Step-by-Step Solution
Verified Answer
(a) Monthly payment: \$859.35.
(b) Total paid: \$309,366.
(c) Account value: \$2,078,671.
1Step 1: Understanding the Mortgage Loan Formula
To find the monthly payment on a mortgage, we use the formula:\[ M = P \times \frac{r(1+r)^n}{(1+r)^n - 1} \]where \( M \) is the monthly payment, \( P \) is the principal loan amount (\$100,000), \( r \) is the monthly interest rate, and \( n \) is the total number of payments. The given annual interest rate is \(9 \frac{3}{4}\% = 9.75\%\). We convert it to a monthly rate by dividing by 12, so \( r = \frac{9.75}{100 \times 12} \approx 0.008125 \). The total number of payments for a 30-year loan is \( n = 30 \times 12 = 360 \).
2Step 2: Calculate Monthly Payment
Substitute the values into the formula to calculate \( M \):\[ M = 100,000 \times \frac{0.008125(1+0.008125)^{360}}{(1+0.008125)^{360} - 1} \]Calculate the exponent, \( (1+0.008125)^{360} \approx 20.706 \).Now, substitute back to find \( M \):\[ M = 100,000 \times \frac{0.008125 \times 20.706}{20.706 - 1} \approx 859.35 \]Thus, the monthly payment is approximately \$859.35.
3Step 3: Calculating Total Payment Over 30 Years
To find the total amount paid, multiply the monthly payment by the number of months:\[ \text{Total payment} = 859.35 \times 360 \approx 309,366 \]The total amount paid over 30 years is approximately \$309,366.
4Step 4: Future Value of Monthly Payments as Investments
Now, calculate how much would accumulate if the monthly payments were invested in an account with the same interest rate. Use the future value of annuity formula:\[ FV = PMT \times \frac{(1 + r)^n - 1}{r} \]Substitute the known values:\[ FV = 859.35 \times \frac{(1 + 0.008125)^{360} - 1}{0.008125} \]Calculate:\[ (1 + 0.008125)^{360} - 1 = 20.706 - 1 = 19.706 \]Then:\[ FV = 859.35 \times \frac{19.706}{0.008125} \approx 2,078,671 \]Therefore, if deposited, the account would have approximately \$2,078,671 at the end of 30 years.
Key Concepts
Compounded InterestMonthly Payment FormulaFuture Value of Annuity
Compounded Interest
Compounded interest is the fundamental concept behind most financial growth calculations, including our mortgage example. It's the interest calculated on the initial principal, which also includes all of the accumulated interest from previous periods. Essentially, this means that interest is earned on interest.
To understand compounded interest more clearly, consider the following:
- When interest is compounded monthly, the annual interest rate is divided by 12 to give the monthly interest rate.
- With compounding, the principal amount grows each month by the interest earned, which means each subsequent interest calculation is based on a slightly larger principal.
Monthly Payment Formula
When securing a loan or calculating installments for a mortgage, the monthly payment formula is crucial. This formula helps in determining what you need to pay each month to fully pay off a loan.The formula used is:\[M = P \times \frac{r(1+r)^n}{(1+r)^n - 1}\]Where:
- \(M\) - the monthly payment
- \(P\) - the principal loan amount, in our case, \(100,000.
- \(r\) - the monthly interest rate (annual rate divided by 12).
- \(n\) - total number of payments (months), so 360 for a 30-year mortgage.
Future Value of Annuity
The future value of an annuity formula is used when determining how much accumulated value regular payments will have at a future date. It is especially useful in setting savings goals or evaluating what an investment will grow into over time.The standard formula for the future value of an annuity is:\[FV = PMT \times \frac{(1 + r)^n - 1}{r}\]Where:
- \(FV\) - the future accumulated value of the investments.
- \(PMT\) - the regular payment amount, which was \(859.35 in our case.
- \(r\) - the monthly interest rate.
- \(n\) - the number of payments.
Other exercises in this chapter
Problem 15
Show that \(n^{2}-n+41\) is odd for all natural numbers \(n\)
View solution Problem 15
Determine whether the sequence is geometric. If it is geometric, find the common ratio. $$1.0,1.1,1.21,1.331, \ldots$$
View solution Problem 15
Find the first five terms of the given recursively defined sequence. $$a_{n}=a_{n-1}+a_{n-2} \quad \text { and } \quad a_{1}=1, a_{2}=2$$
View solution Problem 16
Determine whether the sequence is arithmetic. If it is arithmetic, find the common difference. $$\frac{1}{2}, \frac{1}{3}, \frac{1}{4}, \frac{1}{5}, \dots$$
View solution