Problem 15
Question
Light of two different wavelengths is used in a double-slit experiment. The location of the third-order maximum for the first light, yellow-orange light \((\lambda=600 \mathrm{nm})\) coincides with the location of the fourth-order maximum for the other color's light. What is the wavelength of the other light?
Step-by-Step Solution
Verified Answer
The wavelength of the other light is 450 nm.
1Step 1: Understanding the Problem
In a double-slit experiment, the location of a maximum for light of a certain order is given by the path difference formula: \( m_1 \lambda_1 = m_2 \lambda_2 \). Here, \( \lambda_1 = 600 \text{ nm} \), \( m_1 = 3 \) for the yellow-orange light, and \( m_2 = 4 \) for the other light. We need to find \( \lambda_2 \).
2Step 2: Setting up the Equation
We know that the third-order maximum of the yellow-orange light coincides with the fourth-order maximum of the other light. We use the equation \( m_1 \lambda_1 = m_2 \lambda_2 \), which becomes \( 3 \times 600 = 4 \times \lambda_2 \).
3Step 3: Solving the Equation
Rearrange the equation to solve for \( \lambda_2 \): \( \lambda_2 = \frac{3 \times 600}{4} \). Divide to find \( \lambda_2 = 450 \text{ nm} \).
4Step 4: Conclusion
The wavelength of the other light is \( \lambda_2 = 450 \text{ nm} \).
Key Concepts
Light WavelengthInterference PatternPath Difference FormulaOrder of Maximum
Light Wavelength
Light travels in waves and a crucial property of these waves is called the wavelength, symbolized by \( \lambda \). The wavelength is the distance between two consecutive peaks or troughs of a wave.
This concept is important in many scientific phenomena, including the double-slit experiment, where different wavelengths can result in different patterns.
Here are some important points about light wavelength you need to remember:
This concept is important in many scientific phenomena, including the double-slit experiment, where different wavelengths can result in different patterns.
Here are some important points about light wavelength you need to remember:
- The wavelength determines the color of the light we see. For instance, yellow-orange light has a wavelength of about 600 nm (nanometers).
- Shorter wavelengths are typically found in the blue/violet end of the spectrum, while longer wavelengths reside in the red/orange end.
- In experiments, knowing the wavelength allows us to predict how light will behave as it moves through different materials or encounters obstacles.
Interference Pattern
When light passes through two slits close to each other, it creates an interference pattern on a screen behind the slits. This pattern is a series of bright and dark lines.
This interference is central to experiments such as the double-slit experiment, helping us understand fundamental properties of light and quantum mechanics.
The pattern observed provides clues to the wavelength of the light being used, which can be crucial for calculations and understanding material properties.
- The bright lines are called maxima, where light waves from the slits meet in phase, amplifying each other.
- The dark lines, or minima, occur where light waves meet out of phase, cancelling each other out.
This interference is central to experiments such as the double-slit experiment, helping us understand fundamental properties of light and quantum mechanics.
The pattern observed provides clues to the wavelength of the light being used, which can be crucial for calculations and understanding material properties.
Path Difference Formula
The path difference formula is a fundamental equation when studying the interference of light, especially in experiments like the double-slit experiment.
This formula helps us calculate the position of maxima and minima.
Here's the core equation and details to note:
This formula helps us calculate the position of maxima and minima.
Here's the core equation and details to note:
- The formula is expressed as \( m \lambda = d \sin \theta \), where \( m \) represents the order of the maximum, \( \lambda \) is the wavelength, \( d \) is the distance between the slits, and \( \theta \) is the angle of diffraction.
- In the exercise you encountered, the equation \( m_1 \lambda_1 = m_2 \lambda_2 \) was adapted to find the wavelength of an unknown light source.
- This formula helps determine where bright and dark fringes appear on the screen, and is vital in understanding and predicting light patterns.
Order of Maximum
The order of maximum is a key term used when examining interference patterns from a double-slit experiment. It basically refers to the number in the sequence of bright spots where interference is constructive.
For example:
This concept is important because it allows us to calculate unknown variables in experiments by understanding how different light wavelengths relate to each other within the interference pattern.
For example:
- An order of 1 would be the first bright fringe from the center.
- An order of 2 is the second bright fringe, and so on.
This concept is important because it allows us to calculate unknown variables in experiments by understanding how different light wavelengths relate to each other within the interference pattern.
Other exercises in this chapter
Problem 12
(a) Derive a relationship that gives the locations of the minima in a Young's double-slit experiment. What is the distance between adjacent minima? (b) For a th
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When a double-slit setup is illuminated with light of wavelength \(632.8 \mathrm{nm}\), the distance between the center of the central bright position and the s
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Light of wavelength \(550 \mathrm{nm}\) in air is normally incident on a glass plate \((n=1.5)\) whose thickness is \(1.1 \times 10^{-5} \mathrm{~m} .\) (a) Wha
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A film of index of refraction of 1.4 and thickness of \(1.2 \times 10^{-5} \mathrm{~m}\) is on a lens with an index of refraction of 1.6. Light of wavelength \(
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