Problem 15
Question
In Problems, find all critical points of the given plane autonomous system. $$ \begin{aligned} &x^{\prime}=x\left(1-x^{2}-3 y^{2}\right) \\ &y^{\prime}=y\left(3-x^{2}-3 y^{2}\right) \end{aligned} $$
Step-by-Step Solution
Verified Answer
The critical points are \((0, 0), (0, 1), (0, -1), (1, 0), (-1, 0)\).
1Step 1: Identify Critical Points
A critical point occurs where both derivatives are zero: \(x' = 0\) and \(y' = 0\). So, we start by setting \(x' = 0\) and \(y' = 0\).
2Step 2: Solve \(x' = 0\)
Solve the equation \(x(1-x^2-3y^2)=0\). This can be true if either \(x=0\) or \(1-x^2-3y^2=0\).
3Step 3: Solve \(y' = 0\)
Solve the equation \(y(3-x^2-3y^2)=0\). This can be true if either \(y=0\) or \(3-x^2-3y^2=0\).
4Step 4: Identify Intersection of Conditions
Combine the conditions from \(x' = 0\) and \(y' = 0\), consider cases where \(x = 0\), \(y = 0\), and when both equations satisfy the conditions simultaneously.
5Step 5: Case 1: \(x = 0\)
Substitute \(x=0\) into \(y(3-x^2-3y^2)=0\) which becomes \(y(3-3y^2) = 0\). Thus, \(y = 0\) or \(3-3y^2 = 0\), leading to \(y = \pm1\). So the critical points are \((0, 0)\), \((0, 1)\), \((0, -1)\).
6Step 6: Case 2: \(y = 0\)
Substitute \(y=0\) into \(x(1-x^2-3y^2)=0\) which becomes \(x(1-x^2)=0\). Thus, \(x = 0\) or \(1-x^2 = 0\), leading to \(x = \pm1\). So the critical points are \((0, 0)\), \((1, 0)\), \((-1, 0)\).
7Step 7: Case 3: Solve Simultaneous Equations
If both \(1-x^2-3y^2=0\) and \(3-x^2-3y^2=0\) simultaneously, subtract the second from the first to get \(-2 = 0\), which is false. Hence, no additional solutions.
8Step 8: List all Critical Points
Combine all unique solutions from above cases: \((0, 0), (0, 1), (0, -1), (1, 0), (-1, 0)\).
Key Concepts
Autonomous SystemsDifferential EquationsPhase Plane AnalysisSystem of EquationsStability Analysis
Autonomous Systems
Autonomous systems are a special class of systems in the field of differential equations where time is not explicitly involved in the evolution of the system. This means the rates of change for the variables do not depend directly on the time variable. Instead, they depend solely on the current values of the variables themselves.
The function for each variable is defined by an equation that involves only the variables present, such as:
The function for each variable is defined by an equation that involves only the variables present, such as:
- In our exercise, we have functions for \(x'\) and \(y'\), representing the rates of change of \(x\) and \(y\).
- Each of these functions depends only on the variables \(x\) and \(y\).
Differential Equations
Differential equations are mathematical equations that involve derivatives, which represent how a quantity changes over time. These are fundamental tools in modeling natural phenomena and engineering systems because they can describe how dynamic processes occur.
Differential equations can be classified into different types, such as ordinary differential equations (ODEs), where the functions involved depend only on one variable, typically time. In our autonomous system exercise:
Differential equations can be classified into different types, such as ordinary differential equations (ODEs), where the functions involved depend only on one variable, typically time. In our autonomous system exercise:
- The differential equations \(x' = x(1-x^2-3y^2)\) and \(y' = y(3-x^2-3y^2)\) describe how the values of \(x\) and \(y\) change.
- They are used to find critical points by setting the rate of change to zero.
Phase Plane Analysis
Phase plane analysis is a graphical method used to study the behavior of autonomous systems by plotting the trajectories of the system in a two-dimensional plane. Each axis represents one of the variables.
Identifying critical points and observing their behavior in the phase plane helps us understand stability and ongoing system behavior better.
- The phase plane helps visualize how different initial conditions lead to different trajectories over time.
- Critical points, where the system changes nature, often become apparent in this plane.
Identifying critical points and observing their behavior in the phase plane helps us understand stability and ongoing system behavior better.
System of Equations
A system of equations involves multiple equations that are solved together to find values satisfying all equations simultaneously. This is common in cases where multiple variables interact, each governed by different rules or constraints.
In the problem, we solve the system formed by \(x' = 0\) and \(y' = 0\) to find the critical points:
In the problem, we solve the system formed by \(x' = 0\) and \(y' = 0\) to find the critical points:
- These equations can be solved independently or simultaneously, depending on how they are structured.
- From the solution, we obtain a set of conditions or values where both \(x\) and \(y\) do not change, known as critical points.
Stability Analysis
Stability analysis is vital for understanding the behavior of critical points in a system, particularly whether they can maintain their state when subjected to small disturbances.
In essence, stability analysis answers the question: if a system is slightly disturbed, will it return to its previous state, move away, or reach a new state?
In essence, stability analysis answers the question: if a system is slightly disturbed, will it return to its previous state, move away, or reach a new state?
- Critical points are evaluated to see if they are stable, unstable, or semi-stable.
- Techniques such as eigenvalue analysis or linearization around the critical points are used.
Other exercises in this chapter
Problem 15
In Problems, find a circular invariant region for the given plane autonomous system. $$ \begin{aligned} &x^{\prime}=-x+y+x y \\ &y^{\prime}=x-y-x^{2}-y^{3} \end
View solution Problem 15
In Problems \(11-20\), classify (if possible) each critical point of the given plane autonomous system as a stable node, a stable spiral point, an unstable spir
View solution Problem 15
Find a circular invariant region for the given plane autonomous system. $$ \begin{aligned} &x^{\prime}=-x+y+x y \\ &y^{\prime}=x-y-x^{2}-y^{3} \end{aligned} $$
View solution Problem 15
Find all critical points of the given plane autonomous system. $$ \begin{aligned} &x^{\prime}=x\left(1-x^{2}-3 y^{2}\right) \\ &y^{\prime}=y\left(3-x^{2}-3 y^{2
View solution