Problem 15
Question
In Exercises \(5-18,\) solve each system by the substitution method. $$ \left\\{\begin{array}{l} 2 x-3 y=8-2 x \\ 3 x+4 y=x+3 y+14 \end{array}\right. $$
Step-by-Step Solution
Verified Answer
The solution to the system of equations is \(x = 17\) and \(y = 20\).
1Step 1: Simplify Equations
Simplify the given equations as follows,1) From \(2x - 3y = 8 - 2x\), simplify it to \(4x - 3y = 8\).2) From \(3x + 4y = x + 3y + 14\), simplify it to \(2x - y = 14\).
2Step 2: Solve for One Variable
Take the second equation and solve for one variable. Here, let's solve for y,\(2x - y = 14\) becomes \(y = 2x - 14\).
3Step 3: Substitute into First Equation
Substitute \(y = 2x - 14\) into the first simplified equation to solve for x,\(4x - 3(2x - 14) = 8\),\(4x - 6x + 42 = 8\),\(-2x + 42 = 8\),\(-2x = -34\),\(x = 17\).
4Step 4: Solve for Other Variable
Substitute x = 17 into the equation solved for y from Step 2,\(y = 2(17) - 14\),\(y = 34 - 14\),\(y = 20\).
Key Concepts
System of EquationsAlgebraic SimplificationSolving for Variables
System of Equations
When dealing with a system of equations, we are working with two or more equations that share the same set of unknowns. In this particular exercise, we have a pair of equations featuring the variables \(x\) and \(y\), which are intertwined. Our goal is to find the values of \(x\) and \(y\) that satisfy both equations simultaneously.
- The essence of a system of equations is to determine the common solution that all equations agree upon.
- These systems can be solved through various methods, such as substitution, elimination, or graphing.
- The substitution method involves solving one equation for a single variable and then substituting that expression into another equation.
Algebraic Simplification
Simplifying equations is a pivotal step in solving them efficiently. The goal is to rewrite the equations in a form that is easier to manipulate.
- In the given exercise, both initial equations undergo a simplification process to make them more manageable.
- For instance, the equation \(2x - 3y = 8 - 2x\) is simplified by moving terms involving \(x\) to one side resulting in \(4x - 3y = 8\).
- Similarly, \(3x + 4y = x + 3y + 14\) simplifies to \(2x - y = 14\) after rearranging terms.
Solving for Variables
Solving for variables involves isolating a variable to determine its value. In this exercise, once the equations are simplified, each variable is solved step by step.
- Initially, from the second simplified equation \(2x - y = 14\), we solve for \(y\) by expressing it in terms of \(x\). This gives \(y = 2x - 14\).
- This expression is then substituted back into the first equation \(4x - 3y = 8\) to solve for \(x\).
- After substituting, the calculations simplify to \(-2x = -34\), leading to \(x = 17\).
Other exercises in this chapter
Problem 15
Graph each inequality. $$x^{2}+y^{2}>25$$
View solution Problem 15
In Exercises \(1-18,\) solve each system by the substitution method. $$ \left\\{\begin{array}{l} x+y=1 \\ x^{2}+x y-y^{2}=-5 \end{array}\right. $$
View solution Problem 15
Solve each system. $$\left\\{\begin{array}{rr} x+y & =-4 \\ y-z & =1 \\ 2 x+y+3 z & =-21 \end{array}\right.$$
View solution Problem 16
write the partial fraction decomposition of each rational expression. $$ \frac{x}{x^{2}+2 x-3} $$
View solution