Problem 15
Question
In Exercises 15-20, write the augmented matrix for the system of linear equations. \( \left\\{ \begin{array}{l} 4x - 3y = -5 \\ -x + 3y = 12 \end{array} \right. \)
Step-by-Step Solution
Verified Answer
The augmented matrix for the system of linear equations is \[ \begin{bmatrix} 4 & -3 & -5 \ -1 & 3 & 12 \end{bmatrix} \]
1Step 1: Identify the coefficients and constants
For the given system of linear equations, \n 4x - 3y = -5 and \n -x + 3y = 12, \n the coefficients and constants for each equation are: \n For the first equation, the coefficient of x is 4, the coefficient of y is -3, and the constant is -5; \n For the second equation, the coefficient of x is -1, the coefficient of y is 3, and the constant is 12.
2Step 2: Write the augmented matrix - 1
Write the coefficients and constants of the equations as rows of a matrix. For the first row, write the coefficients of x and y, and the constant from the first equation as follows: [4, -3, -5].
3Step 3: Write the augmented matrix - 2
For the second row, write the coefficients of x and y, and the constant from the second equation as follows: [-1, 3, 12].
4Step 4: The augmented matrix
By placing the numbers train in the matrix, the augmented matrix for the given system of linear equations becomes \n \[ \begin{bmatrix} 4 & -3 & -5 \ -1 & 3 & 12 \end{bmatrix} \]
Key Concepts
Understanding Systems of Linear EquationsExploring CoefficientsPerforming Row Operations
Understanding Systems of Linear Equations
A system of linear equations is a set of two or more linear equations involving the same set of variables. They are named 'linear' because they each represent a line in a coordinate plane when plotted. The main idea is to find the point or points where these lines intersect, which corresponds to the solution of the system.
Systems can have:
- a single unique solution, meaning the lines intersect at one point,
- infinitely many solutions, which occurs when the lines are on top of each other, or
- no solution, which is when the lines are parallel and never meet.
Exploring Coefficients
Coefficients are the numbers that multiply the variables in an equation. In the context of systems of linear equations, coefficients accompany variables such as \( x \) and \( y \) and show the influence each variable has on the equation. For example, in the equation \(4x - 3y = -5\), 4 is the coefficient of \( x \) and -3 is the coefficient of \( y \). Similarly, in the equation \(-x + 3y = 12\), the coefficient of \( x \) is -1 and 3 is the coefficient for \( y \). These coefficients are essential because they help determine the slope and position of the line represented by the equation when it is graphed. When combined with their constants, these coefficients give us a complete equation that contributes to forming the augmented matrix used to solve the system.
Performing Row Operations
Row operations are techniques used to manipulate matrices to simplify the solving process of systems of linear equations. These operations are crucial for transforming the matrix into simpler forms like row-echelon form or reduced row-echelon form, from which solutions can be easily deduced.
There are three primary types of row operations:
- Row swapping: Exchanging two rows in the matrix.
- Row scaling: Multiplying all entries of a row by a non-zero scalar.
- Row addition: Adding a multiple of one row to another row.
Other exercises in this chapter
Problem 15
In Exercises 13-24, find the inverse of the matrix (if it exists). \(\left[ \begin{array}{r} 1 & -2 \\ 2 & -3 \end{array} \right]\)
View solution Problem 15
In Exercises 11-18, if possible, find (a) \(A+B\), (b) \(A-B\), (c ) \(3A\), and (d) \(3A-2B\). \(A = \left[ \begin{array}{r} 4 & 5 & -1 & 3 & 4 \\ 1 & 2 & -2 &
View solution Problem 16
In Exercises 7-16, use Cramer's Rule to solve (if possible) the system of equations. \(\begin{cases} 5x - 4y + z = -14 \\ -x + 2y - 2z = 10 \\ 3x + y + z = 1 \e
View solution Problem 16
In Exercises 5-20, find the determinant of the matrix. \(\left[ \begin{array}{r} 4 && 7 \\ -2 && 5 \end{array} \right]\)
View solution