Problem 15
Question
In Exercises \(1-16,\) find a parametrization of the surface. (There are many correct ways to do these, so your answers may not be the same as those in the back of the book.) $$ \begin{array}{l}{\text { Circular cylinder band The portion of the cylinder }(x-2)^{2}+} \\ {z^{2}=4 \text { between the planes } y=0 \text { and } y=3}\end{array} $$
Step-by-Step Solution
Verified Answer
The parametrization is \\( (x, y, z) = (2 + 2\cos(\theta), t, 2\sin(\theta)) \\) with \\( \theta \in [0, 2\pi] \\) and \\( t \in [0, 3] \\).
1Step 1: Understand the equation
The given equation \( (x-2)^2 + z^2 = 4 \) represents a cylinder centered at \(x=2\) with radius 2 in the x-z plane. This cylinder extends infinitely along the y-axis.
2Step 2: Determine the boundaries
The specified portion of the cylinder is between the planes \(y = 0\) and \(y = 3\), which means it extends from y=0 to y=3 along the y-axis.
3Step 3: Parametrize the circular cross-section
The circular cross-section of the cylinder can be parametrized using trigonometric functions. Set \(x = 2 + 2\cos(\theta)\) and \(z = 2\sin(\theta)\), where \(\theta\) varies from \(0\) to \(2\pi\) to cover the full circle.
4Step 4: Include the linear axis
Include the y-axis, which varies linearly between the two boundary planes. Define \(y = t\), where \(t\) ranges from 0 to 3.
5Step 5: Write the parametrization
Combine the parameters from the previous steps into a vector function: \((x, y, z) = (2 + 2\cos(\theta), t, 2\sin(\theta))\). \(\theta\) ranges from 0 to \2\pi\ and \(t\) ranges from 0 to 3.
Key Concepts
Circular CylinderTrigonometric FunctionsVector FunctionParametric Equations
Circular Cylinder
A circular cylinder is a three-dimensional geometric shape that has straight parallel lines running the length of the shape. The shape is defined by its circular cross-sections. In the given exercise, the circular cylinder is defined by the equation
- \((x-2)^2 + z^2 = 4\)
Trigonometric Functions
Trigonometric functions are essential tools in parameterizing shapes like circles and cylinders. They allow us to describe circular motions and oscillations. For parametrizing the circular cross-section of the cylinder, we use the functions:
- \(x = 2 + 2\cos(\theta)\)
- \(z = 2\sin(\theta)\)
Vector Function
A vector function gives a mathematical description of a curve or surface in space. It aggregates multiple functions into one concise representation. For the circular cylinder, the vector function created encapsulates both circular motion and linear translation along the y-axis.
- \((x, y, z) = (2 + 2\cos(\theta), t, 2\sin(\theta))\)
Parametric Equations
Parametric equations are valuable for describing geometric figures where simple Cartesian equations aren’t sufficient. They capture complex surfaces by expressing each coordinate (e.g., \(x, y, z\)) as functions of one or more variables, often called parameters. In this exercise, we use parameters \(\theta\) and \(t\) to reflect both circular and linear aspects of the cylinder:
- \(x = 2 + 2\cos(\theta)\)
- \(y = t\)
- \(z = 2\sin(\theta)\)
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