Problem 15
Question
In \(3-26,\) prove that each equation is an identity. $$ \frac{\sec \theta}{\csc \theta}=\tan \theta $$
Step-by-Step Solution
Verified Answer
\(\frac{\sec \theta}{\csc \theta} = \tan \theta\) is an identity because both sides simplify to \(\frac{\sin \theta}{\cos \theta}\).
1Step 1: Understand the Identity and Given Equation
We are given the equation \( \frac{\sec \theta}{\csc \theta} = \tan \theta \). The task is to prove that this is an identity, meaning it holds true for all values of \( \theta \) for which functions are defined.
2Step 2: Express Trigonometric Functions in Terms of Sine and Cosine
Recall the definitions of the trigonometric functions involved: \( \sec \theta = \frac{1}{\cos \theta} \) and \( \csc \theta = \frac{1}{\sin \theta} \). Also, \( \tan \theta = \frac{\sin \theta}{\cos \theta} \). Substitute these into the given equation.
3Step 3: Rewrite the Left Side
Substituting the definitions, we get:\[\frac{\sec \theta}{\csc \theta} = \frac{\frac{1}{\cos \theta}}{\frac{1}{\sin \theta}}.\]This simplifies to:\[\frac{\sin \theta}{\cos \theta}.\]
4Step 4: Compare with Right Side
Notice that the expression \( \frac{\sin \theta}{\cos \theta} \) is identical to \( \tan \theta \). Therefore, the given equation contradicts to:\[\tan \theta = \tan \theta.\]This confirms that the original equation \( \frac{\sec \theta}{\csc \theta} = \tan \theta \) is indeed an identity.
Key Concepts
Secant FunctionCosecant FunctionTangent FunctionSine and Cosine Expressions
Secant Function
The secant function, denoted as \( \sec \theta \), is one of the core trigonometric identities. It plays an essential role in simplifying and understanding trigonometric expressions. The secant of an angle \( \theta \) is defined as the reciprocal of the cosine function. This means:
- \( \sec \theta = \frac{1}{\cos \theta} \)
Cosecant Function
The cosecant function, represented by \( \csc \theta \), is another important trigonometric identity. Similar to the secant function, the cosecant is defined as the reciprocal of the sine function. In mathematical terms, this is expressed as:
- \( \csc \theta = \frac{1}{\sin \theta} \)
Tangent Function
The tangent function, denoted as \( \tan \theta \), is a fundamental trigonometric function that can be expressed through the ratios of sine and cosine. The tangent of an angle \( \theta \) can be described as:
- \( \tan \theta = \frac{\sin \theta}{\cos \theta} \)
Sine and Cosine Expressions
Sine and cosine functions are the most basic and crucial functions in trigonometry. They form the building blocks for other trigonometric identities and expressions. Understanding how they interact is essential for manipulating and simplifying complex trigonometric expressions.The sine and cosine functions are defined as follows:
- \( \sin \theta \) - the y-coordinate of the unit circle at angle \( \theta \)
- \( \cos \theta \) - the x-coordinate of the unit circle at angle \( \theta \)
Other exercises in this chapter
Problem 15
If \(\sin A=\frac{24}{25}\) and \(90^{\circ}
View solution Problem 15
In \(3-17,\) find the exact value of \(\tan (A+B)\) and of \(\tan (A-B)\) for each given pair of values. $$ A=\pi, B=\frac{\pi}{3} $$
View solution Problem 15
\(\ln 3-17,\) find the exact value of \(\sin (A-B)\) and of \(\sin (A+B)\) for each given pair of values. \(A=\frac{3 \pi}{2}, B=2 \pi\)
View solution Problem 15
In \(3-17,\) find the exact value of \(\cos (A+B)\) for each given pair of values. \(A=\frac{\pi}{2}, B=\frac{2 \pi}{3}\)
View solution