Problem 15
Question
In \(3-22,\) evaluate each expression. $$ _{10} P_{4} \div 4 ! $$
Step-by-Step Solution
Verified Answer
The result of the expression is 210.
1Step 1: Understand the Symbols
The expression is \( _{10}P_{4} \div 4! \). Here, \( _{10}P_{4} \) refers to a permutation, which represents the number of ways to arrange 4 items out of 10. The symbol \( 4! \) (read as "4 factorial") means the product of all positive integers up to 4: \( 4 \times 3 \times 2 \times 1 \).
2Step 2: Calculate the Permutation \( _{10}P_{4} \)
The formula for permutation is \( _{n}P_{r} = \frac{n!}{(n-r)!} \). For \( _{10}P_{4} \), this means: \[ _{10}P_{4} = \frac{10!}{(10-4)!} = \frac{10!}{6!} \]. Calculating further, we get: \[ 10 \times 9 \times 8 \times 7 = 5040 \] since \( 6! \) cancels out the rest of the \( 10! \).
3Step 3: Calculate \( 4! \)
The factorial of 4, \( 4! \), is calculated by multiplying all integers from 1 to 4: \[ 4! = 4 \times 3 \times 2 \times 1 = 24 \].
4Step 4: Divide the Permutation by 4!
Now, divide the result from the permutation by the factorial: \[ \frac{5040}{24} = 210 \].
5Step 5: Conclusion
The final value after performing the division is 210.
Key Concepts
Understanding FactorialsCombinatorics in ActionExploring the Permutation Formula
Understanding Factorials
Factorials are a crucial concept in permutations and combinations. The factorial of a non-negative integer \( n \) is denoted by \( n! \) and is defined as the product of all positive integers less than or equal to \( n \). For example, \( 4! \) means
They form the building blocks for both permutations and combinations. When \( n \) is 0 or 1, the factorial of \( n \) is defined as 1, which serves as the base case in computations.
Understanding how to compute and utilize factorials can significantly simplify solving permutation problems.
- Multiply: \(4 \times 3 \times 2 \times 1 \)
- This equals: 24
They form the building blocks for both permutations and combinations. When \( n \) is 0 or 1, the factorial of \( n \) is defined as 1, which serves as the base case in computations.
Understanding how to compute and utilize factorials can significantly simplify solving permutation problems.
Combinatorics in Action
Combinatorics is the branch of mathematics that studies the counting, arrangement, and combination of objects. It is the foundation for understanding permutations and combinations.
When dealing with permutations, we are interested in the number of ways to arrange a set of items. This is different from combinations, which focus on the selection of items without considering the order.
When dealing with permutations, we are interested in the number of ways to arrange a set of items. This is different from combinations, which focus on the selection of items without considering the order.
- Permutations: Order matters. Calculate using factorials.
- Combinations: Order doesn’t matter. Typically fewer possibilities than permutations.
Exploring the Permutation Formula
The permutation formula is used to find the number of ways \( r \) objects can be arranged from a set of \( n \) objects. The formula is denoted as \( _{n}P_{r} \), which is computed by dividing the factorial of \( n \) by the factorial of \( n-r \):\[ _{n}P_{r} = \frac{n!}{(n-r)!} \]For example, to calculate \( _{10}P_{4} \):
- Compute \( 10! \), representing all possible arrangements of 10 items.
- Divide by \( 6! \) (i.e., \((10-4)!\)), which removes the arrangements not involving the 4 selected items.
- The result is: \(10 \times 9 \times 8 \times 7 = 5040\) arrangements.
Other exercises in this chapter
Problem 15
In \(12-17,\) write the \(n\) th term of each binomial expansion. $$ (x-y)^{9}, n=5 $$
View solution Problem 15
In \(14-17\) , use the normal approximation to estimate each probability. Round your answers to three decimal places. . \(P(\text { more than } 20 \text { succe
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State whether the events are independent or dependent. Buying a magazine and a snack for a train trip
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In \(12-17,\) write the \(n\) th term of each binomial expansion. $$ (3 a+2 b)^{7}, n=6 $$
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