Problem 15
Question
If possible, find each of the following. (a) \(A+B\) (b) \(3 A\) (c) \(2 A-3 B\) $$A=\left[\begin{array}{rr}2 & -6 \\\3& 1\end{array}\right]$$ $$B=\left[\begin{array}{ll}-1 & 0 \\\\-2 & 3\end{array}\right]$$
Step-by-Step Solution
Verified Answer
(a) \(\begin{pmatrix} 1 & -6 \\ 1 & 4 \end{pmatrix}\), (b) \(\begin{pmatrix} 6 & -18 \\ 9 & 3 \end{pmatrix}\), (c) \(\begin{pmatrix} 7 & -12 \\ 12 & -7 \end{pmatrix}\)."}
1Step 1: Add Matrices A and B
To add two matrices, simply add corresponding elements. For matrices A and B, \[A = \begin{pmatrix} 2 & -6 \ 3 & 1 \end{pmatrix}\] \[B = \begin{pmatrix} -1 & 0 \ -2 & 3 \end{pmatrix}\].Calculate each element: \[A + B = \begin{pmatrix} 2 + (-1) & -6 + 0 \ 3 + (-2) & 1 + 3 \end{pmatrix} = \begin{pmatrix} 1 & -6 \ 1 & 4 \end{pmatrix}\].
2Step 2: Multiply Matrix A by Scalar 3
To find \(3A\), multiply each element of matrix A by 3:\[A = \begin{pmatrix} 2 & -6 \ 3 & 1 \end{pmatrix}\]Then, \[3A = \begin{pmatrix} 3 \times 2 & 3 \times (-6) \ 3 \times 3 & 3 \times 1 \end{pmatrix} = \begin{pmatrix} 6 & -18 \ 9 & 3 \end{pmatrix}\].
3Step 3: Find 2A - 3B
First, calculate \(2A\) by multiplying each element of matrix A by 2:\[2A = \begin{pmatrix} 2 \times 2 & 2 \times (-6) \ 2 \times 3 & 2 \times 1 \end{pmatrix} = \begin{pmatrix} 4 & -12 \ 6 & 2 \end{pmatrix}\].Then, calculate \(3B\) by multiplying each element of matrix B by 3:\[3B = \begin{pmatrix} 3 \times (-1) & 3 \times 0 \ 3 \times (-2) & 3 \times 3 \end{pmatrix} = \begin{pmatrix} -3 & 0 \ -6 & 9 \end{pmatrix}\].Subtract \(3B\) from \(2A\):\[2A - 3B = \begin{pmatrix} 4 - (-3) & -12 - 0 \ 6 - (-6) & 2 - 9 \end{pmatrix} = \begin{pmatrix} 7 & -12 \ 12 & -7 \end{pmatrix}\].
Key Concepts
Matrix AdditionScalar MultiplicationMatrix Subtraction
Matrix Addition
Matrix addition is a fundamental operation where two matrices of the same dimensions are combined. Each element from one matrix is added to the corresponding element of the other matrix. For this to work, both matrices must have identical dimensions, meaning the same number of rows and columns.
Let's look at an example with matrices \( A \) and \( B \):
Let's look at an example with matrices \( A \) and \( B \):
- \( A = \begin{pmatrix} 2 & -6 \ 3 & 1 \end{pmatrix} \)
- \( B = \begin{pmatrix} -1 & 0 \ -2 & 3 \end{pmatrix} \)
- Top left: \( 2 + (-1) = 1 \)
- Top right: \( -6 + 0 = -6 \)
- Bottom left: \( 3 + (-2) = 1 \)
- Bottom right: \( 1 + 3 = 4 \)
Scalar Multiplication
Scalar multiplication involves multiplying every element of a matrix by a single number, known as a scalar. This operation is crucial when dealing with systems of linear equations or modifications in vector spaces.
Consider matrix \( A = \begin{pmatrix} 2 & -6 \ 3 & 1 \end{pmatrix} \) and a scalar 3. To find \( 3A \), multiply each element in \( A \) by 3:
Consider matrix \( A = \begin{pmatrix} 2 & -6 \ 3 & 1 \end{pmatrix} \) and a scalar 3. To find \( 3A \), multiply each element in \( A \) by 3:
- Top left: \( 3 \times 2 = 6 \)
- Top right: \( 3 \times (-6) = -18 \)
- Bottom left: \( 3 \times 3 = 9 \)
- Bottom right: \( 3 \times 1 = 3 \)
Matrix Subtraction
Matrix subtraction works similarly to addition, but involves subtracting elements from one matrix by those of another. As with addition, both matrices must have the same dimensions to perform subtraction.
Take matrices \( 2A \) and \( 3B \), which are results from earlier calculations:
Take matrices \( 2A \) and \( 3B \), which are results from earlier calculations:
- \( 2A = \begin{pmatrix} 4 & -12 \ 6 & 2 \end{pmatrix} \)
- \( 3B = \begin{pmatrix} -3 & 0 \ -6 & 9 \end{pmatrix} \)
- Top left: \( 4 - (-3) = 7 \)
- Top right: \( -12 - 0 = -12 \)
- Bottom left: \( 6 - (-6) = 12 \)
- Bottom right: \( 2 - 9 = -7 \)
Other exercises in this chapter
Problem 14
Predict the results of \(I_{n} A\) and \(A I_{n}\). Then verify your prediction. $$ I_{4}=\left[\begin{array}{llll} 1 & 0 & 0 & 0 \\ 0 & 1 & 0 & 0 \\ 0 & 0 & 1
View solution Problem 14
If possible, solve the system. $$ \begin{array}{rr} -x-5 y+2 z= & 2 \\ x+y+2 z= & 2 \\ 3 x+y-4 z= & -10 \end{array} $$
View solution Problem 15
Let \(A\) be the given matrix. Find det \(A\) by using the method of co factors. $$ \left[\begin{array}{rrr} 0 & 0 & 0 \\ -8 & 3 & -9 \\ 15 & 5 & 9 \end{array}\
View solution Problem 15
The augmented matrix is in row-echelon form and represents a linear system. Solve the system by using backwand substitution, if possible. Write the solution as
View solution