Problem 15
Question
Identify the acids and bases in the following reactions: a. \(\mathrm{HCl}(a q)+\mathrm{NaOH}(a q) \rightarrow \mathrm{NaCl}(a q)+\mathrm{H}_{2} \mathrm{O}(\ell)\) b. \(\mathrm{MgCO}_{3}(s)+2 \mathrm{HCl}(a q) \rightarrow\) \(\mathrm{MgCl}_{2}(a q)+\mathrm{CO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(\ell)\) c. \(2 \mathrm{NH}_{3}(a q)+\mathrm{H}_{2} \mathrm{SO}_{4}(a q) \rightarrow\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{4}(a q)\)
Step-by-Step Solution
Verified Answer
Question: Identify the acids and bases in the following three chemical reactions:
a) HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)
b) MgCO3(s) + 2 HCl(aq) → MgCl2(aq) + CO2(g) + H2O(l)
c) 2 NH3(aq) + H2SO4(aq) → (NH4)2SO4(aq)
Answer:
a) Acid: HCl, Base: NaOH
b) Acid: HCl, Base: MgCO3
c) Acid: H2SO4, Base: NH3
1Step 1: Reaction a: Identifying acid and base
In the reaction \(\mathrm{HCl}(a q)+\mathrm{NaOH}(a q) \rightarrow \mathrm{NaCl}(a q)+\mathrm{H}_{2} \mathrm{O}(\ell)\), we can identify that HCl donates a proton (H+) and NaOH accepts a proton (H+). Therefore, HCl is the acid in this reaction, and NaOH is the base.
2Step 2: Reaction b: Identifying acid and base
In the reaction \(\mathrm{MgCO}_{3}(s)+2 \mathrm{HCl}(a q) \rightarrow \mathrm{MgCl}_{2}(a q)+\mathrm{CO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(\ell)\), we can identify that HCl donates a proton (H+) and MgCO3 accepts a proton (H+). Therefore, HCl is the acid in this reaction, and MgCO3 is the base.
3Step 3: Reaction c: Identifying acid and base
In the reaction \(2 \mathrm{NH}_{3}(a q)+\mathrm{H}_{2} \mathrm{SO}_{4}(a q) \rightarrow\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{4}(a q)\), we can identify that H2SO4 donates two protons (2 H+) and NH3 accepts two protons (2 H+). Therefore, H2SO4 is the acid in this reaction, and NH3 is the base.
Key Concepts
Proton DonorsProton AcceptorsNeutralization Reactions
Proton Donors
In acid-base chemistry, a proton donor is a substance that releases a proton, or hydrogen ion (\(H^+\)), during a reaction. Acids are typical proton donors. For instance, in the reactions examined, hydrochloric acid (\(HCl\)) donates a proton in reactions (a) and (b). Similarly, sulfuric acid (\(H_2SO_4\)) acts as a proton donor in reaction (c). When an acid donates a proton, it often forms a conjugate base. For example:
- When \(HCl\) donates a proton, it forms \(Cl^-\) as its conjugate base.
- For \(H_2SO_4\), losing a proton results in \(HSO_4^-\). \(HSO_4^-\) can give up another proton to form \(SO_4^{2-}\) in a subsequent reaction.
Proton Acceptors
Proton acceptors are substances that gain a proton (\(H^+\)) during a chemical reaction. These are often base substances. For example, in the reactions provided, sodium hydroxide (\(NaOH\)) accepts a proton from \(HCl\), turning into water (\(H_2O\)) in reaction (a). In response (c), ammonia (\(NH_3\)) accepts protons from sulfuric acid to form ammonium sulfate (\((NH_4)_2SO_4\)).The role of proton acceptors is crucial for neutralizing acids in reactions, leading to the formation of water and salt.
- In reaction (b), magnesium carbonate (\(MgCO_3\)) acts as the base, accepting protons to facilitate the breakdown into water and carbon dioxide.
- Learning to identify bases in reactions enhances comprehension of processes such as neutralization and buffer systems, which stabilize pH in biological environments.
Neutralization Reactions
Neutralization occurs when an acid and a base react to form water and a salt, often resulting in a solution that is neither acidic nor basic. This concept is exemplified in the given reactions. Consider reaction (a) of \(HCl\) and \(NaOH\). HCl donates a proton to \(NaOH\), resulting in the creation of water and sodium chloride (\(NaCl\)), which is an example of a neutralization reaction.Neutralization is not only fundamental in laboratory settings but also in real-life applications:
- In reaction (b), \(MgCO_3\) neutralizes the acid \(HCl\), forming magnesium chloride (\(MgCl_2\)), carbon dioxide (\(CO_2\)), and water (\(H_2O\)), each playing a part in this complete reaction.
- For reaction (c), ammonia (\(NH_3\)) reacts with \(H_2SO_4\), where the neutralization results in ammonium sulfate (\((NH_4)_2SO_4\)).
Other exercises in this chapter
Problem 13
In an aqueous solution of \(\mathrm{NH}_{3},\) which species acts as a Bronsted- Lowry acid and which is the Brensted-Lowry base?
View solution Problem 14
Both KOH and Ba(OH), are strong bases. Does this mean that solutions of the two compounds with the same molarity have the same capacity to accept hydrogen ions?
View solution Problem 16
Identify the acids and bases in the following reactions: a. \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{N}(a q)+\mathrm{H}_{2} \mathrm{O}(\ell) \rightleftharpoon
View solution Problem 17
Identify the conjugate base of each of the following compounds: \(\mathrm{HNO}_{2}, \mathrm{HClO}, \mathrm{H}_{3} \mathrm{PO}_{4},\) and \(\mathrm{NH}_{3}\)
View solution