Problem 15
Question
How many numbers can be formed from the digits \(1,2,3\), and 4 if repetitions are not allowed? (Note: 42 and 231 are examples of such numbers.)
Step-by-Step Solution
Verified Answer
24 numbers can be formed.
1Step 1: Understand the Problem
We need to find out how many unique numbers can be formed using each of the digits 1, 2, 3, and 4 once in each number. Repetition of digits is not allowed and we want to use all digits in each number.
2Step 2: Determine the Number of Digits
We have four distinct digits: 1, 2, 3, and 4. We want to form numbers using all four digits. Therefore, each number will be a four-digit number.
3Step 3: Calculate Permutations
The number of permutations of four distinct items (or digits) is given by the factorial of the number of items. Since we are using 4 digits, we calculate \(4!\).
4Step 4: Compute the Factorial
Calculate \(4!\) (4 factorial), which is \(4 \times 3 \times 2 \times 1\). This results in 24. Thus, 24 different numbers can be formed.
Key Concepts
FactorialDistinct DigitsCombinatorics
Factorial
The concept of factorial is fundamental in permutations and many areas of mathematics. Factorial, denoted as \( n! \), is the product of all positive integers less than or equal to \( n \). It plays a crucial role in determining how many ways items can be arranged or ordered.
For instance, calculating \( 4! \) means multiplying all whole numbers from 1 to 4:
For instance, calculating \( 4! \) means multiplying all whole numbers from 1 to 4:
- \( 4 \times 3 \times 2 \times 1 = 24 \)
Distinct Digits
When considering numbers formed by a set of digits, the term 'distinct' is key. It means each digit in the set is different from the others. For example, in our problem, the digits 1, 2, 3, and 4 are distinct. Each digit can only be used once per number.
Distinct digits are important in permutations because they limit the number of possible combinations. Repetition would allow for more combinations, but distinctness restricts choices.
Distinct digits are important in permutations because they limit the number of possible combinations. Repetition would allow for more combinations, but distinctness restricts choices.
- First position: Any of the 4 digits
- Second position: One of the remaining 3 digits
- Third position: One of the remaining 2 digits
- Fourth position: The last remaining digit
Combinatorics
Combinatorics is a branch of mathematics dealing with counting, arranging, and combining items. It provides the tools to tackle questions like the one in our exercise about forming numbers with certain requirements.
In our problem, we utilized permutations because we are arranging 4 distinct digits. Permutations consider the order of the items, making it different from combinations, which disregards order. Combinatorics helps solve problems about arranging objects or selecting items from a group, often resulting in calculations using factorial numbers.
In our problem, we utilized permutations because we are arranging 4 distinct digits. Permutations consider the order of the items, making it different from combinations, which disregards order. Combinatorics helps solve problems about arranging objects or selecting items from a group, often resulting in calculations using factorial numbers.
- We ask how many ways 4 different digits can be arranged.
- The order of digits matters in forming specific numbers.
- Using the concept of permutations, we find \( 4! = 24 \) arrangements.
Other exercises in this chapter
Problem 15
Exer. 15-16: Consider any eight points such that no three are collinear. How many lines are determined?
View solution Problem 15
Rewrite as an expression that does not contain factorials. $$ \frac{(2 n+2) !}{(2 n) !} $$
View solution Problem 15
Exer. 1-26: Prove that the statement is true for every positive integer \(n\). $$ n
View solution Problem 15
Exer. 13-18: Find the specified term of the arithmetic sequence that has the two given terms. $$ a_{1} ; \quad a_{6}=2.7, \quad a_{7}=5.2 $$
View solution