Problem 15
Question
Given that \(\mathbf{r}(t)=\frac{\sin \angle t}{t} \mathbf{i}+(t-2)^{5} \mathbf{j}+t \ln t \mathbf{k}\), find \(\lim _{t \rightarrow 0^{+}} \mathbf{r}(t)\).
Step-by-Step Solution
Verified Answer
The limit is \( \mathbf{i} - 32 \mathbf{j} \).
1Step 1: Determine Each Component
The vector function is given as \( \mathbf{r}(t) = \frac{\sin t}{t} \mathbf{i} + (t-2)^{5} \mathbf{j} + t \ln t \mathbf{k} \). We need to find the limit for each component separately as \( t \to 0^{+} \).
2Step 2: Evaluate Limit of First Component
Consider \( \frac{\sin t}{t} \). As \( t \to 0 \), \( \frac{\sin t}{t} \to 1 \). This is a standard limit result.
3Step 3: Evaluate Limit of Second Component
Consider \( (t-2)^{5} \). As \( t \to 0 \), the expression \( t-2 \to -2 \), hence \( (t-2)^{5} \to (-2)^{5} = -32 \).
4Step 4: Evaluate Limit of Third Component
Consider \( t \ln t \). As \( t \to 0^{+} \), we transform this using L'Hôpital's Rule by rewriting as \[ \lim_{t \to 0^{+}} \frac{\ln t}{1/t} \]. Apply L'Hôpital's Rule: differentiate numerator and denominator to get \[ \lim_{t \to 0^{+}} \frac{1/t}{-1/t^2} = \lim_{t \to 0^{+}} -t = 0 \].
5Step 5: Assemble the Limits
Combine the evaluated limits for each component to form the limit of the vector function: \( \lim_{t \to 0^{+}} \mathbf{r}(t) = 1 \mathbf{i} - 32 \mathbf{j} + 0 \mathbf{k} \). Thus, the result is \( \mathbf{i} - 32 \mathbf{j} \).
Key Concepts
Limit of Vector FunctionsL'Hôpital's RuleVector Components
Limit of Vector Functions
Understanding the limit of vector functions involves calculating the limit of each component of the vector separately. A vector function is generally defined in terms of its i, j, and k components, each of which can be a function of a parameter, like time or space.
- For the vector function \( \mathbf{r}(t) = \frac{\sin t}{t} \mathbf{i} + (t-2)^{5} \mathbf{j} + t \ln t \mathbf{k} \), we evaluate the limits of \( \frac{\sin t}{t} \), \( (t-2)^5 \), and \( t \ln t \) separately as \( t \to 0^{+} \).
- The approach of evaluating each component's limit is critical because each function within the vector might have a different behavior as the parameter approaches a specific value.
- This means that even when handling a complex vector function, we break it down into simpler, more manageable parts.
L'Hôpital's Rule
L'Hôpital's Rule is a powerful tool in calculus used to evaluate limits involving indeterminate forms, such as \( \frac{0}{0} \) or \( \frac{\infty}{\infty} \). The rule states that for functions \( f(t) \) and \( g(t) \) which are differentiable,
- if \( \lim_{t \to a} \frac{f(t)}{g(t)} \) yields an indeterminate form, then \( \lim_{t \to a} \frac{f(t)}{g(t)} = \lim_{t \to a} \frac{f'(t)}{g'(t)} \) provided the limit on the right-hand side exists.
- In our exercise, to find the limit of \( t \ln t \) as \( t \to 0^{+} \), we rewrote this as a fraction: \( \lim_{t \to 0^{+}} \frac{\ln t}{1/t} \).
- Upon differentiating, we found \( \frac{1/t}{-1/t^2} \) yielding \( -t \). Thus, the limit simplifies to \( 0 \) as \( t \to 0^{+} \).
Vector Components
Vectors are essential in representing quantities with both magnitude and direction. A vector in a 3D space is typically expressed in terms of its components along the coordinate axes:
- The \( \mathbf{i} \), \( \mathbf{j} \), and \( \mathbf{k} \) represent the unit vectors along the x, y, and z axes, respectively.
- When a vector is given by \( \mathbf{r}(t) = f(t) \mathbf{i} + g(t) \mathbf{j} + h(t) \mathbf{k} \), each function \( f(t) \), \( g(t) \), and \( h(t) \) defines how the vector behaves in its respective direction.
- Breaking down vectors into components provides a clearer understanding of their effect in each independent direction and simplifies mathematical operations such as addition, subtraction, and finding limits.
Other exercises in this chapter
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