Problem 15
Question
For Problems \(1-18\), solve each of the inequalities and express the solution sets in interval notation. $$ 0.09 x+0.1(x+200)>77 $$
Step-by-Step Solution
Verified Answer
The solution is \((300, \infty)\).
1Step 1: Expand the Expression
The inequality given is \(0.09x + 0.1(x + 200) > 77\). Start by expanding the term \(0.1(x + 200)\). This will give us \(0.1x + 20\).
2Step 2: Combine Like Terms
Now combine the like terms in the inequality: \(0.09x + 0.1x + 20 > 77\). This simplifies to \(0.19x + 20 > 77\).
3Step 3: Isolate the Variable Term
Subtract 20 from both sides of the inequality to isolate the term with \(x\): \(0.19x > 77 - 20\). This simplifies to \(0.19x > 57\).
4Step 4: Solve for the Variable
Divide both sides by 0.19 to solve for \(x\): \(x > \frac{57}{0.19}\). Calculating this gives \(x > 300\).
5Step 5: Write the Solution in Interval Notation
Express the solution \(x > 300\) in interval notation. The solution in interval notation is \((300, \infty)\).
Key Concepts
Interval NotationExpanding ExpressionsCombining Like TermsSolving Inequalities
Interval Notation
Interval notation is a way of writing subsets of the real number line. It's often used to express solutions to inequalities. This method simplifies the expression of range, using brackets and parentheses to denote inclusive or exclusive bounds.
For example, when expressing solutions for inequalities:
For example, when expressing solutions for inequalities:
- An open parenthesis "](" or ")" is used when the number is not included in the solution set (exclusive).
- A closed bracket "[" or "]" indicates the number is included (inclusive).
Expanding Expressions
To solve mathematical expressions efficiently, it's vital to properly expand them. Expanding an expression usually involves distributing a multiplier over terms inside parentheses.
In the inequality \(0.09x + 0.1(x + 200) > 77\), you see multiplication with 0.1 across terms inside the parentheses. This results in:
In the inequality \(0.09x + 0.1(x + 200) > 77\), you see multiplication with 0.1 across terms inside the parentheses. This results in:
- \(0.1 \times x\) becoming \(0.1x\)
- \(0.1 \times 200\) becoming 20
Combining Like Terms
The next logical step after expanding expressions is to combine like terms. Like terms have the same variable raised to the same power. This consolidation is crucial since it simplifies expressions further.
In the example \(0.09x + 0.1x + 20 > 77\), the terms \(0.09x\) and \(0.1x\) are like terms because they both have the variable \(x\). Combining these yields:
In the example \(0.09x + 0.1x + 20 > 77\), the terms \(0.09x\) and \(0.1x\) are like terms because they both have the variable \(x\). Combining these yields:
- \(0.09x + 0.1x = 0.19x\)
Solving Inequalities
Solving inequalities involves isolating the variable so that the inequality can be rewritten in simple terms. Once we have simplified an inequality, the goal is to have the variable by itself on one side.From the step \(0.19x + 20 > 77\):
- Subtract 20 from both sides: \(0.19x > 57\).
- Now, divide each side by 0.19 to isolate \(x\): \(x > \frac{57}{0.19}\).
- This calculation gives \(x > 300\).
Other exercises in this chapter
Problem 14
Solve each equation. \(-8 y-2=18\)
View solution Problem 15
For Problems \(1-16\), solve each equation. $$ |4 x-3|+2=2 $$
View solution Problem 15
Express each interval as an inequality using the variable \(x\). For example, we can express the interval \([5, \infty\) ) as \(x \geq 5\). \([-7, \infty)\)
View solution Problem 15
Use the formula to solve for the given variable. Solve the formula \(A=\frac{1}{2} h\left(b_{1}+b_{2}\right)\) for \(b_{2}\) and complete the following chart. \
View solution