Problem 15
Question
Find the second derivative of each function. $$ f(x)=\frac{27}{\sqrt[3]{x}} $$
Step-by-Step Solution
Verified Answer
The second derivative is \( f''(x) = \frac{12}{x^{\frac{7}{3}}} \).
1Step 1: Rewrite the Function
Start by rewriting the function with a power notation, as this will make it easier to differentiate. The function is given as \( f(x) = \frac{27}{\sqrt[3]{x}} \). This can be rewritten using exponents: \( f(x) = 27x^{-\frac{1}{3}} \).
2Step 2: Find the First Derivative
Differentiate the function \( f(x) = 27x^{-\frac{1}{3}} \) using the power rule \( \frac{d}{dx}[x^n] = nx^{n-1} \). Thus, the first derivative \( f'(x) \) is \( f'(x) = 27 \cdot (-\frac{1}{3}) x^{-\frac{1}{3} - 1} = -9x^{-rac{4}{3}} \).
3Step 3: Find the Second Derivative
Differentiate the first derivative \( f'(x) = -9x^{-\frac{4}{3}} \) again using the power rule. The second derivative \( f''(x) \) is given by \( f''(x) = -9 \cdot (-\frac{4}{3}) x^{-\frac{4}{3} - 1} = 12x^{-\frac{7}{3}} \).
4Step 4: Simplify the Second Derivative
Rewrite the second derivative \( f''(x) = 12 x^{-\frac{7}{3}} \) to its original radical form, if necessary. This is \( f''(x) = \frac{12}{x^{\frac{7}{3}}} \).
Key Concepts
Power RuleFirst DerivativeSecond DerivativeFunction Differentiation
Power Rule
The power rule is a fundamental tool in calculus used for differentiating functions involving power terms. It's particularly handy for differentiating expressions where variables are raised to constant powers. The rule is straightforward: to differentiate a function of the form \( x^n \), multiply by the power \( n \) and reduce the power by one, i.e., \( \frac{d}{dx}[x^n] = nx^{n-1} \). This effectively reduces the power of the variable by one degree, while maintaining the same coefficient—a simple yet powerful technique.
In the given exercise, applying the power rule allows the transformation of the original function, \( f(x) = \frac{27}{\sqrt[3]{x}} \), into a format more amenable to differentiation. It turns into \( 27x^{-\frac{1}{3}} \) which is now a straightforward candidate for the power rule. This step simplifies the problem significantly by converting roots and denominators to exponents. Thus, making the differentiation process logical and systematic.
In the given exercise, applying the power rule allows the transformation of the original function, \( f(x) = \frac{27}{\sqrt[3]{x}} \), into a format more amenable to differentiation. It turns into \( 27x^{-\frac{1}{3}} \) which is now a straightforward candidate for the power rule. This step simplifies the problem significantly by converting roots and denominators to exponents. Thus, making the differentiation process logical and systematic.
First Derivative
The first derivative of a function provides us with the rate at which the function's output changes with respect to change in input. It's essential for understanding the function's behavior, such as its slope and tendency—whether it's increasing or decreasing. In this context, the differentiation of the rewritten function yields useful insights.
For the function \( f(x) = 27x^{-\frac{1}{3}} \), employing the power rule results in the first derivative: \( f'(x) = -9x^{-\frac{4}{3}} \). Here's what the process looks like with the power rule applied:
For the function \( f(x) = 27x^{-\frac{1}{3}} \), employing the power rule results in the first derivative: \( f'(x) = -9x^{-\frac{4}{3}} \). Here's what the process looks like with the power rule applied:
- The original exponent \(-\frac{1}{3}\) is reduced by 1 to get \(-\frac{4}{3}\).
- Multiply the coefficient (27) by the new exponent \(-\frac{1}{3}\) to get \(-9\).
Second Derivative
The second derivative of a function tells us about the concavity of the function and its acceleration; it is a derivative of the first derivative. In essence, it answers questions about how the rate of change is changing, shedding light on the curvature of the function.
For our exercise, the first derivative \( f'(x) = -9x^{-\frac{4}{3}} \) is differentiated using the power rule once more to obtain the second derivative, \( f''(x) = 12x^{-\frac{7}{3}} \). The calculation involves:
For our exercise, the first derivative \( f'(x) = -9x^{-\frac{4}{3}} \) is differentiated using the power rule once more to obtain the second derivative, \( f''(x) = 12x^{-\frac{7}{3}} \). The calculation involves:
- Multiplying \(-9\) by \(-\frac{4}{3}\), leading to the coefficient 12.
- Subtracting 1 from the exponent \(-\frac{4}{3}\) to get \(-\frac{7}{3}\).
Function Differentiation
Function differentiation is a core process in calculus that involves finding how a function changes at any given point. Differentiation transforms a function into its derivative, providing critical information such as slope, velocity, and acceleration, all of which are vital for analyzing real-world phenomena.
When differentiating functions like \( f(x) = \frac{27}{\sqrt[3]{x}} \), the initial task often involves reformatting the function. By converting division and roots into exponents, as seen here with \( 27x^{-\frac{1}{3}} \), we facilitate easier differentiation practices.
This differentiation process unfolds in multiple steps for different orders, each providing deeper insights into the function:
When differentiating functions like \( f(x) = \frac{27}{\sqrt[3]{x}} \), the initial task often involves reformatting the function. By converting division and roots into exponents, as seen here with \( 27x^{-\frac{1}{3}} \), we facilitate easier differentiation practices.
This differentiation process unfolds in multiple steps for different orders, each providing deeper insights into the function:
- The **first derivative** gives us the gradient or slope; it answers how steep the curve is at any point.
- The **second derivative** informs on concavity and informs about the acceleration of change.
Other exercises in this chapter
Problem 14
Find the derivative of each function by using the Product Rule. Simplify your answers. $$ f(x)=\left(x^{2}+2 x\right)(2 x+1) $$
View solution Problem 15
Use the Generalized Power Rule to find the derivative of each function. $$ h(z)=\left(3 z^{2}-5 z+2\right)^{4} $$
View solution Problem 15
Using your own words, explain in terms of instantaneous rates of change why the derivative is undefined where a function has a discontinuity.
View solution Problem 15
Find the following limits without using a graphing calculator or making tables. $$ \lim _{x \rightarrow 5} \frac{3 x^{2}-5 x}{7 x-10} $$
View solution