Problem 15
Question
Find the least common denominator of the rational expressions. $$\frac{3}{x^{2}-x-20} \text { and } \frac{x}{2 x^{2}+7 x-4}$$
Step-by-Step Solution
Verified Answer
The least common denominator of the given rational expressions is \((x+4)*(x-5)*(2x-1)\)
1Step 1: Factorise the denominators
The first step is to factorise the denominators. The factors of \(x^{2}-x-20\) are \((x+4)\) and \((x-5)\), because \(-5 * 4 = -20\) and \(-5 + 4 = -1\). Similarly, the factors of \(2x^2+7x-4\) are \((2x-1)\) and \((x+4)\), because \(1*4* 2 = -8\) and \(-8 + 7 = -1\).
2Step 2: Identify the common factors
Having factored the denominators, we can now identify the common factors. From the factorised denominators, it is clear that \((x+4)\) is the common factor.
3Step 3: Find the least common denominator
The least common denominator is obtained by multiplying the unique factors from both expressions. Thus, the least common denominator for the given rational expressions is \((x+4)*(x-5)*(2x-1)\).
Other exercises in this chapter
Problem 15
Find all numbers for which each rational expression is undefined. If the rational expression is defined for all real numbers, so state. $$\frac{y+3}{4 y^{2}+y-3
View solution Problem 15
Simplify complex rational expression by the method of your choice. \(\frac{\frac{x}{5}-\frac{5}{x}}{\frac{1}{5}+\frac{1}{x}}\)
View solution Problem 15
Solve each rational equation. $$\frac{x-2}{2 x}+1=\frac{x+1}{x}$$
View solution Problem 15
Multiply as indicated. $$\frac{y^{2}-7 y-30}{y^{2}-6 y-40} \cdot \frac{2 y^{2}+5 y+2}{2 y^{2}+7 y+3}$$
View solution