Problem 15
Question
Find the largest possible domain and the corresponding range of each function. Determine the equation of the level curves \(f(x, y)=c\), together with the possible values of \(c .\) \(f(x, y)=\ln \left(y-x^{2}\right)\)
Step-by-Step Solution
Verified Answer
Domain: \(y > x^2\); Range: all real numbers; Level curves: \(y = x^2 + e^c\), \(c\) can be any real number.
1Step 1: Understanding the Function's Domain
To find the largest possible domain of the function \(f(x, y) = \ln(y - x^2)\), we need the argument of the logarithm \((y - x^2)\) to be positive. This implies that \(y - x^2 > 0\). Therefore, the domain of \(f\) is all points \((x, y)\) where \(y > x^2\).
2Step 2: Determining the Range of the Function
The range of the function \(f(x, y) = \ln(y - x^2)\) is all real numbers. Since \(y - x^2 > 0\), \(\ln(y - x^2)\) can take any real value by appropriately choosing the value of \(y\) relative to \(x\) to vary \(y - x^2\).
3Step 3: Finding the Level Curves Equation
The level curves of the function are given by setting the function equal to a constant \(c\): \(f(x, y) = c\), which means \(\ln(y - x^2) = c\). This equation simplifies to \(y - x^2 = e^c\). Each level curve will be an upward-facing parabola given by \(y = x^2 + e^c\).
4Step 4: Identifying Possible Values for the Constant
For \(y = x^2 + e^c\) to be meaningful, \(e^c\) must be positive (since it is an exponential function). Therefore, \(c\) can be any real number, because \(e^c\) is always positive for any real value of \(c\).
Key Concepts
Domain and RangeLogarithmic FunctionsLevel Curves
Domain and Range
The concepts of domain and range are essential in understanding functions. The domain refers to all the possible input values for which the function is defined. Here, we deal with the function \( f(x, y) = \ln(y - x^2) \). For a logarithmic function of form \( \ln(a) \), the argument \( a \) must be greater than zero. This condition ensures that \( (y - x^2) > 0 \), meaning
The range is the set of all possible output values the function can yield. Because a logarithmic function can approach any real number as its argument changes, the range of \( f(x, y) = \ln(y - x^2) \) spans all real numbers. By selecting appropriate \( y \) values larger than \( x^2 \), the expression \( y - x^2 \) can cover all positive values, allowing \( \ln(y - x^2) \) to output any real number.
- \( y > x^2 \)
The range is the set of all possible output values the function can yield. Because a logarithmic function can approach any real number as its argument changes, the range of \( f(x, y) = \ln(y - x^2) \) spans all real numbers. By selecting appropriate \( y \) values larger than \( x^2 \), the expression \( y - x^2 \) can cover all positive values, allowing \( \ln(y - x^2) \) to output any real number.
Logarithmic Functions
Logarithmic functions provide a unique insight into mathematical relationships, particularly through their ability to represent inverse exponential behavior. The function we are dealing with is \( f(x, y) = \ln(y - x^2) \), and this is a natural logarithmic function.
A key characteristic of logarithmic functions is that they can only be defined with positive arguments. This is because the logarithm of a non-positive number is undefined in the realm of real numbers. For our function, the requirement of \( (y - x^2) > 0 \) must hold for \( \ln(y - x^2) \) to be valid.
These properties are why logarithmic functions are adept at describing phenomena with wide-ranging scales, including in fields like acoustics and earthquake intensity, where real-world measurements are converted via a logarithm for better interpretability and manipulation.
A key characteristic of logarithmic functions is that they can only be defined with positive arguments. This is because the logarithm of a non-positive number is undefined in the realm of real numbers. For our function, the requirement of \( (y - x^2) > 0 \) must hold for \( \ln(y - x^2) \) to be valid.
- This implies that the function reflects scenarios where \( y \) significantly exceeds \( x^2 \).
These properties are why logarithmic functions are adept at describing phenomena with wide-ranging scales, including in fields like acoustics and earthquake intensity, where real-world measurements are converted via a logarithm for better interpretability and manipulation.
Level Curves
Level curves give a snapshot of a function's behavior at specific output values by holding the function constant. For our function \( f(x, y) = \ln(y - x^2) \), a level curve is defined by fixing the function's output, say \( c \). Thus, \( \ln(y - x^2) = c \) implies:
Since \( e^c \) is always positive, the shift ensures the curves lie above the parabola formed by \( y = x^2 \). The constant \( c \) can vary over all real numbers, adjusting the elevation of the level curves across the plane.
Understanding level curves allows one to visualize how the function's output changes with \( x \) and \( y \). Each curve signifies a uniform functional value and aids in grasping the nature of a 3D surface, providing insights into gradients and topographical features akin to contour lines found on geographic maps.
- \( y - x^2 = e^c \)
- or rearranged, \( y = x^2 + e^c \)
Since \( e^c \) is always positive, the shift ensures the curves lie above the parabola formed by \( y = x^2 \). The constant \( c \) can vary over all real numbers, adjusting the elevation of the level curves across the plane.
Understanding level curves allows one to visualize how the function's output changes with \( x \) and \( y \). Each curve signifies a uniform functional value and aids in grasping the nature of a 3D surface, providing insights into gradients and topographical features akin to contour lines found on geographic maps.
Other exercises in this chapter
Problem 15
The growth rate \(r\) of a particular organism is affected by both the availability of food and the number of competitors for the food source. Denote the amount
View solution Problem 15
Show that \(f(x, y)\) is differentiable at the indicated point. $$ f(x, y)=x+y^{2}-2 x y ;(-1,2) $$
View solution Problem 15
In Problems 1-16, find \(\partial f / \partial x\) and \(\partial f / \partial y\) for the given functions. $$ f(x, y)=\log _{3}\left(y^{2}-x^{2}\right) $$
View solution Problem 15
The functions are defined on the rectangular domain $$ D=\\{(x, y):-1 \leq x \leq 1,-1 \leq y \leq 1\\} $$ Find the absolute maxima and minima of \(f\) on \(D\)
View solution