Problem 15
Question
Find the indefinite integral and check your result by differentiation. $$ \int d u $$
Step-by-Step Solution
Verified Answer
The indefinite integral of du is \(u + C\), where \(C\) is the constant of integration.
1Step 1: Compute Indefinite Integral
The given function is \(\int du\) which means an integral with respect to \(u\). The integral of \(du\) is simply \(u\), as the integral of \(1\) with respect to \(u\) is \(u\). So the antiderivative \(F(u) = u + C\), where C is the constant of integration.
2Step 2: Check the result by differentiation
In order to check if the computed antiderivative is correct, differentiate it with respect to \(u\). The derivative of \(u\) is \(1\) and the derivative of a constant is \(0\). Therefore, \(F'(u) = 1 + 0 = 1\). Thus, the differentiation result checks out with the original function.
Other exercises in this chapter
Problem 15
Use the Log Rule to find the indefinite integral. $$ \int \frac{1}{3-2 x} d x $$
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Use the Midpoint Rule with \(n=4\) to approximate the area of the region bounded by the graph of \(f\) and the \(x\) -axis over the interval. Compare your resul
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Sketch the region bounded by the graphs of the functions and find the area of the region. $$ y=x^{3}-2 x+1, y=-2 x, x=1 $$
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