Problem 15
Question
Find \(\frac{d y}{d x}\). $$ y=4 \sqrt{x} $$
Step-by-Step Solution
Verified Answer
\( \frac{d y}{d x} = \frac{2}{\sqrt{x}} \)
1Step 1: Understand the Function
We are given the function \( y = 4 \sqrt{x} \). This function involves a square root of \( x \), which can be rewritten using exponent notation to simplify differentiation.
2Step 2: Rewrite the Function
Rewrite the square root as a power: \( y = 4 \cdot x^{1/2} \). This step helps in applying the derivative rule for functions of the type \( x^n \).
3Step 3: Apply the Power Rule
To find the derivative of \( y = 4x^{1/2} \), use the power rule: \( \frac{d}{dx} [x^n] = n \cdot x^{n-1} \).
4Step 4: Differentiate the Function
Apply the power rule to differentiate: \( \frac{d}{dx} [4x^{1/2}] = 4 \cdot \frac{1}{2} \cdot x^{-1/2} \).
5Step 5: Simplify the Derivative
Simplify the expression: \( \frac{d y}{d x} = 2x^{-1/2} \). Rewriting with a square root gives \( \frac{d y}{d x} = \frac{2}{\sqrt{x}} \).
Key Concepts
Power RuleSquare Root FunctionExponent Notation
Power Rule
The Power Rule is a fundamental aspect of differentiation that simplifies finding derivatives of functions with exponents. Whenever you have a power of a variable, say - \( x^n \), the Power Rule states that the derivative is obtained by:- multiplying by the power (\( n \)),- and then reducing the power by one.
This is mathematically represented as:- \( \frac{d}{dx}[x^n] = n \cdot x^{n-1} \).
For example, when differentiating \( x^3 \), you multiply by the exponent, 3, and decrease the exponent by 1, resulting in \( 3x^2 \).
This rule is crucial for quickly handling derivatives of polynomials and any expressions that can be rewritten with exponents. It's simple yet powerful, making differentiation more efficient.
This is mathematically represented as:- \( \frac{d}{dx}[x^n] = n \cdot x^{n-1} \).
For example, when differentiating \( x^3 \), you multiply by the exponent, 3, and decrease the exponent by 1, resulting in \( 3x^2 \).
This rule is crucial for quickly handling derivatives of polynomials and any expressions that can be rewritten with exponents. It's simple yet powerful, making differentiation more efficient.
Square Root Function
The square root function is a specific type of mathematical function that can be quite common in calculus. It is generally expressed as:- \( \sqrt{x} \).
For differentiation purposes, it is beneficial to transform it into exponent notation. This is because operations on powers are easier.
The square root of a number or variable corresponds to raising that number or variable to the power of \( \frac{1}{2} \). Therefore:- \( \sqrt{x} = x^{1/2} \).
This transformation allows us to apply the Power Rule, making differentiation a smooth process. Whenever you encounter a square root in calculus, consider using this conversion to streamline finding derivatives.
For differentiation purposes, it is beneficial to transform it into exponent notation. This is because operations on powers are easier.
The square root of a number or variable corresponds to raising that number or variable to the power of \( \frac{1}{2} \). Therefore:- \( \sqrt{x} = x^{1/2} \).
This transformation allows us to apply the Power Rule, making differentiation a smooth process. Whenever you encounter a square root in calculus, consider using this conversion to streamline finding derivatives.
Exponent Notation
Exponent Notation is a way to express numbers, particularly when dealing with roots and powers, in a more uniform way. It involves writing expressions in the form:- \( x^n \), where \( n \) is any real number.
Some key points about exponent notation include:
Some key points about exponent notation include:
- Converting roots to powers. For example, \( \sqrt{x} \) is \( x^{1/2} \).
- Remembering laws of exponents, such as multiplying powers (\( x^a \cdot x^b = x^{a+b} \)).
- Knowing how to handle negative exponents, like \( x^{-n} = \frac{1}{x^n} \).
Other exercises in this chapter
Problem 14
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