Problem 15
Question
Find each product and write the result in standard form. $$ (3+5 i)(3-5 i) $$
Step-by-Step Solution
Verified Answer
Thus, the product of \(3+5i\) and \(3-5i\) in standard form is 34.
1Step 1: Identify and multiply the real parts
First, identify the real parts of the complex number, which are the numbers without the imaginary unit 'i'. These are 3 in both cases. Thus, start by multiplying these together to get \(3 \times 3 = 9\).
2Step 2: Multiply the imaginary parts
Next, identify and multiply the coefficients of the imaginary parts together. These are +5 and -5. Hence, the multiplication gives \((+5i) \times (-5i) = -25i^2\). Remember that \(i^2\) is -1, therefore \(-25i^2\) simplifies to 25.
3Step 3: Combine the real and imaginary parts
Finally, you combine the results of the real and the imaginary parts. The real part from the multiplication is 9 and the real part from the multiplication of the imaginary parts is 25. The result is \(9 + 25 = 34\).
Other exercises in this chapter
Problem 15
After a \(20 \%\) reduction, you purchase a television for \(\$ 336\) What was the television's price before the reduction?
View solution Problem 15
Solve and check each linear equation. $$\begin{array}{l}{25-[2+5 y-3(y+2)]=} \\\\{-3(2 y-5)-[5(y-1)-3 y+3]}\end{array}$$
View solution Problem 15
Graph each equation in Exercises \(13-28 .\) Let \(x=-3,-2,-1,0\) \(1,2,\) and 3. $$y=x-2$$
View solution Problem 16
Solve each radical equation in Exercises 11–30. Check all proposed solutions. $$\sqrt{6 x+1}=x-1$$
View solution