Problem 15
Question
Exer. 11-46: Simplify. $$ \left(\frac{1}{6} a^{5}\right)\left(-3 a^{2}\right)\left(4 a^{7}\right) $$
Step-by-Step Solution
Verified Answer
The simplified expression is \(-2a^{14}\).
1Step 1: Multiply the coefficients
First, identify and multiply the numerical coefficients in the expression. The coefficients are \(\frac{1}{6}\), \(-3\), and \(4\). Multiply them: \[ \frac{1}{6} \times (-3) \times 4 = \frac{1}{6} \times (-12) = -2. \]
2Step 2: Apply the Product of Powers Property
Next, apply the product of powers property to the variable part, \(a^5\), \(a^2\), and \(a^7\). According to this property, when multiplying bases with the same exponent, you add the exponents: \[ a^5 \times a^2 \times a^7 = a^{5+2+7} = a^{14}. \]
3Step 3: Combine the Results
Combine the results from Steps 1 and 2 to write the simplified expression. Use the coefficient \(-2\) and the power of \(a\) that we calculated: \[-2a^{14}.\] This is the simplified form of the expression.
Key Concepts
Simplifying ExpressionsProduct of Powers PropertyPolynomials
Simplifying Expressions
One of the key skills in algebra is simplifying expressions. When we simplify an expression, we aim to make it as straightforward and concise as possible. This often involves combining numbers and variables in a way that is clearer and more manageable.
Consider the expression \(\left(\frac{1}{6} a^{5}\right)\left(-3 a^{2}\right)\left(4 a^{7}\right)\). To simplify it, we separate the numerical coefficients (\(\frac{1}{6}\), \(-3\), and \(4\)) from the variable parts.
Consider the expression \(\left(\frac{1}{6} a^{5}\right)\left(-3 a^{2}\right)\left(4 a^{7}\right)\). To simplify it, we separate the numerical coefficients (\(\frac{1}{6}\), \(-3\), and \(4\)) from the variable parts.
- First, multiply the coefficients. It helps to perform each multiplication step-by-step. Here, we multiply \(\frac{1}{6} \times (-3) \times 4\) together to get \(-2\).
- Then, handle the variable, which is multiple terms of \(a\) with different exponents.
Product of Powers Property
A fundamental property used in algebra, the Product of Powers Property, helps in simplifying expressions involving exponents. This property states that when you multiply two powers with the same base, you simply add the exponents.
For example:
For example:
- If you have \(a^5\), \(a^2\), and \(a^7\), they all share the base \(a\).
- By using the property, \(a^5 \times a^2 \times a^7\) becomes \(a^{5+2+7} = a^{14}\).
Polynomials
Polynomials are expressions that include variables raised to various powers and coefficients. In algebra, understanding how to manipulate and simplify polynomials is essential. They can vary from simple expressions like \(3x+7\) to more complex forms such as \(x^3 + 2x^2 - x + 5\).
In the exercise \(\left(\frac{1}{6} a^{5}\right)\left(-3 a^{2}\right)\left(4 a^{7}\right)\), we have a polynomial expression with one type of variable, \(a\). The key operations involve:
In the exercise \(\left(\frac{1}{6} a^{5}\right)\left(-3 a^{2}\right)\left(4 a^{7}\right)\), we have a polynomial expression with one type of variable, \(a\). The key operations involve:
- Multiplying coefficients to handle the numerical portion.
- Applying properties like the Product of Powers to simplify the variable part.
Other exercises in this chapter
Problem 15
Write the expression in the form \(a+b i\), where \(a\) and \(b\) are real numbers. (a) \(i^{43}\) (b) \(i^{-30}\)
View solution Problem 15
Express as a polynomial. $$ (x+1)\left(2 x^{2}-2\right)\left(x^{3}+5\right) $$
View solution Problem 15
Exer. 15-18: The given numbers are coordinates of points \(\boldsymbol{A}, \boldsymbol{B}\), and \(\boldsymbol{C}\), respectively, on a coordinate line. Find th
View solution Problem 16
Write the expression in the form \(a+b i\), where \(a\) and \(b\) are real numbers. (a) \(i^{92}\) (b) \(i^{-33}\)
View solution