Problem 15
Question
Exer. 1-34: Write the expression in the form \(a+b i\), where \(a\) and \(b\) are real numbers. (a) \(i^{43}\) (b) \(i^{-20}\)
Step-by-Step Solution
Verified Answer
(a) \(i^{43} = -i = 0 - i\). (b) \(i^{-20} = 1 = 1 + 0i\).
1Step 1: Understand Powers of i
The imaginary unit \(i\) has a special property: \(i^2 = -1\). This leads to cyclical powers: \(i^3 = i^2 \times i = -i\), \(i^4 = i^3 \times i = 1\). Then it repeats: \(i^5 = i\). Thus any power of \(i\) can be simplified using these identities.
2Step 2: Simplify i^43
To simplify \(i^{43}\), notice that \(43 \div 4 = 10\) remainder \(3\). Therefore, \(i^{43} = (i^4)^{10} \times i^3 = 1^{10} \times i^3 = i^3 = -i\).
3Step 3: Result of Part (a)
Given the simplification, \(i^{43} = -i\). Hence, in the form \(a + bi\), where \(a\) and \(b\) are real numbers: \(a = 0\) and \(b = -1\).
4Step 4: Simplify i^-20
To simplify \(i^{-20}\), use the reciprocal identities: \(i^{-1} = \frac{1}{i} = -i\). Similarly, \(i^{-2} = \frac{1}{i^2} = -\frac{1}{-1} = 1\), \(i^{-3} = \frac{1}{i^3} = i\), and \(i^{-4} = \frac{1}{i^4} = 1\). Notice the negative powers also repeat every four. Since \(-20\) divided by \(4\) leaves a remainder of \(0\), \(i^{-20} = (i^{-4})^5 = 1^5 = 1\).
5Step 5: Result of Part (b)
Therefore, \(i^{-20} = 1\). In the form \(a + bi\), \(a = 1\) and \(b = 0\).
Key Concepts
Powers of Imaginary UnitAlgebraReal and Imaginary Components
Powers of Imaginary Unit
The imaginary unit, denoted as \(i\), plays a crucial role in complex numbers. Primarily, it is defined by the equation \(i^2 = -1\). This definition results in a repeating cycle every four powers:
- \(i^1 = i\)
- \(i^2 = -1\)
- \(i^3 = -i\)
- \(i^4 = 1\)
Algebra
Algebra is a branch of mathematics dealing with symbols and the rules for manipulating those symbols. In the context of the imaginary unit \(i\), algebra helps us succinctly express and solve equations involving complex numbers. Utilizing algebraic techniques such as simplifying expressions, recognizing patterns, and applying identities is vital for dealing with powers of \(i\).Simplifying expressions like \(i^{43}\) and \(i^{-20}\) involves recognizing their positions within the sequence of repeated cycles discussed earlier. Algebra allows us to group terms, apply modular arithmetic, and employ arithmetic identities. By understanding these patterns and rules, complex powers become more approachable.
Real and Imaginary Components
Complex numbers are numbers that have both a real and an imaginary component, usually expressed in the form \(a + bi\), where \(a\) and \(b\) are real numbers, and \(i\) represents the imaginary unit. For any expression involving \(i\), such as \(i^{43}\) and \(i^{-20}\), your task is to simplify it to this standard form.For \(i^{43}\), which simplifies to \(-i\), this can be rewritten as \(0 + (-1)i\), where:
- \(a = 0\)
- \(b = -1\)
- \(a = 1\)
- \(b = 0\)
Other exercises in this chapter
Problem 15
Exer. 13-20: Express the interval as an inequality in the variable \(x\). $$ [-4,-1] $$
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Solve the equation. $$\frac{3}{y}+\frac{6}{y}-\frac{1}{y}=11$$
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Exer. 1-40: Solve the inequality, and express the solutions in terms of intervals whenever possible. $$ 25 x^{2}-9 x
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