Problem 15
Question
Evaluate the integrals in Exercises \(1-34\) without using tables. $$ \int_{0}^{1} \frac{\theta+1}{\sqrt{\theta^{2}+2 \theta}} d \theta $$
Step-by-Step Solution
Verified Answer
The integral evaluates to \( \sqrt{3} \).
1Step 1: Simplify the Integral Expression
The integral given is \( \int_{0}^{1} \frac{\theta+1}{\sqrt{\theta^{2}+2\theta}} \, d\theta \). We need to simplify the expression inside the square root first. Notice that \( \theta^2 + 2\theta \) can be rewritten as \( (\theta+1)^2 - 1 \). So, the integral becomes \( \int_{0}^{1} \frac{\theta+1}{\sqrt{(\theta+1)^2 - 1}} \, d\theta \).
2Step 2: Use Substitution
To simplify further, use the substitution \( u = \theta + 1 \). This implies \( du = d\theta \) and changes the limits of integration from \( \theta = 0 \) to \( u = 1 \), and from \( \theta = 1 \) to \( u = 2 \). Thus, the integral becomes \( \int_{1}^{2} \frac{u}{\sqrt{u^2 - 1}} \, du \).
3Step 3: Identify the Integral Form
The integral \( \int \frac{u}{\sqrt{u^2 - 1}} \, du \) is a standard integral form. Recognize this as the derivative of \( \sqrt{u^2 - 1} \). The integral of the derivative will give us \( \sqrt{u^2 - 1} \).
4Step 4: Evaluate the Integral
Integrate to get \( \sqrt{u^2 - 1} \). Evaluating this from 1 to 2 gives \( \sqrt{2^2 - 1} - \sqrt{1^2 - 1} \), which is \( \sqrt{3} - 0 = \sqrt{3} \).
5Step 5: Write the Final Answer
Thus, the value of the integral \( \int_{0}^{1} \frac{\theta+1}{\sqrt{\theta^{2}+2\theta}} \, d\theta \) is \( \sqrt{3} \).
Key Concepts
Integral SubstitutionDefinite IntegralIntegration TechniquesMathematical Simplification
Integral Substitution
One of the powerful tools in calculus and particularly in integration is substitution. This technique essentially turns a complicated integral into a much simpler one by changing the variable. In the exercise, we used the substitution \( u = \theta + 1 \). This allowed us to convert the integral into a form that is more straightforward to handle. When performing substitution:
- Choose a substitution that simplifies the integral, such as transforming a difficult expression into a standard one.
- Calculate the differential, which in this case was \( du = d\theta \).
- Change the limits of integration according to the substitution. Here, \( \theta = 0 \) transforms to \( u = 1 \) and \( \theta = 1 \) to \( u = 2 \).
- Substitute back, evaluate, and simplify.
Definite Integral
Definite integrals are used to calculate the exact area under a curve between two points, which in this exercise are \( 0 \) and \( 1 \). After performing the substitution, the limits of integration were updated from \( \theta \) to \( u \). The definition of a definite integral emphasizes evaluating the antiderivative at the upper and lower bounds and using these to find the result.
- Once the integral is solved, substitute the limits back into the resulting expression.
- This yields a numerical value which, for our exercise, was \( \sqrt{3} \).
Integration Techniques
The exercise demonstrates several techniques that are commonly used in calculus to solve integrals. These techniques help break down complex integrals into solvable parts:
- Simplification: Recognizing patterns and relationships that allow for simplification, such as observing \( \theta^2 + 2\theta = (\theta+1)^2 - 1 \).
- Substitution: Using a substitution like \( u = \theta + 1 \) to shift the integral to a more familiar form.
- Recognition of Standard Forms: Identifying standard integral forms, such as recognizing \( \frac{u}{\sqrt{u^2 - 1}} \) as the derivative of \( \sqrt{u^2 - 1} \).
Mathematical Simplification
Simplification is often the first step in addressing complex integrals. By rewriting expressions in a clearer form, we can often reveal a path towards solving an integral. In this exercise, simplifying \( \theta^2 + 2\theta \) to \( (\theta+1)^2 - 1 \) was crucial. Simplification strategies include:
- Factoring: Where applicable, to rewrite expressions in easier forms.
- Recognizing Common Patterns: Such as perfect squares, which can simplify square roots or other complex expressions.
- Utilizing Identities: Making use of algebraic identities can simplify trigonometric, logarithmic, or polynomial integrands.
Other exercises in this chapter
Problem 14
Evaluate each integral in Exercises \(1-36\) by using a substitution to reduce it to standard form. $$ \int x \sec \left(x^{2}-5\right) d x $$
View solution Problem 15
Evaluate the integrals in Exercises \(1-28\). $$ \int \frac{x^{3} d x}{\sqrt{x^{2}+4}} $$
View solution Problem 15
Evaluate the integrals in Exercises \(15-22\). $$ \int_{0}^{2 \pi} \sqrt{\frac{1-\cos x}{2}} d x $$
View solution Problem 15
Use the table of integrals at the back of the book to evaluate the integrals. \(\int \sqrt{25-p^{2}} d p\)
View solution