Problem 15
Question
Evaluate each sum, where \(d\) is a positive integer. $$\sum_{d | 6} d$$
Step-by-Step Solution
Verified Answer
The sum of all the divisors of \(6\) is given by \(\sum_{d | 6} d = 1+2+3+6 = 12\).
1Step 1: Find the Divisors of 6
First, we need to list all the divisors of \(6\). The divisors are the positive integers that can divide \(6\) without leaving a remainder. They are \(1\), \(2\), \(3\), and \(6\).
2Step 2: Sum the Divisors
Next, we will add up all the divisors we found in step 1. The sum is given by:
$$\sum_{d | 6} d = 1+2+3+6$$
3Step 3: Calculate the Sum
Now, we simply evaluate the sum:
$$1+2+3+6 = 12$$
So, the sum of all the divisors of \(6\) is \(12\).
Key Concepts
DivisorsSummationInteger Arithmetic
Divisors
In mathematics, divisors are numbers that divide another number completely, without leaving a remainder. This means if we have a number like 6, we look for all integers that can multiply with another whole number to result in 6. For instance:
- 1 is a divisor because 1 × 6 = 6.
- 2 is a divisor because 2 × 3 = 6.
- 3 is a divisor because 3 × 2 = 6.
- 6 is a divisor because 6 × 1 = 6.
Summation
Summation is the process of adding numbers together to get a total. It's a fundamental part of arithmetic and is denoted using the Greek letter sigma (
∑
). In the context of divisors, summation allows us to add all the divisors of a number together.
For the problem at hand, we work with ∑_{d | 6} d. This means we need to sum all the divisors of 6:
For the problem at hand, we work with ∑_{d | 6} d. This means we need to sum all the divisors of 6:
- 1 + 2 + 3 + 6 = 12.
Integer Arithmetic
Integer arithmetic refers to operations performed on whole numbers including addition, subtraction, multiplication, and division. Using integer arithmetic, one performs calculations with no fractions or decimals. It is crucial for basic math problems, especially those involving divisors and summation.
To find the sum of divisors:
To find the sum of divisors:
- Add: Begin with the arithmetic operation of addition to combine numbers. Here, perform 1 + 2 + 3 + 6.
- Result: The sum equals 12, showcasing integer addition.
Other exercises in this chapter
Problem 15
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Let \(a \in \mathbf{Z}, S=\\{a, a+1, \ldots\\}, T \subseteq S,\) and \(a \in T .\) Let \(k\) be any element of \(S\) such that whenever \(k \in T, k+1 \in T .\)
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