Problem 15
Question
Evaluate each polynomial when (a) \(x=0\) and \((b) x=-1 .\) See Examples 4 and 5. $$ x^{2}-5 x-2 $$
Step-by-Step Solution
Verified Answer
When \(x = 0\), the polynomial evaluates to -2; when \(x = -1\), it evaluates to 4.
1Step 1: Substitute and Evaluate for x=0
Replace every occurrence of \(x\) in the polynomial \(x^2 - 5x - 2\) with 0. This gives us \(0^2 - 5(0) - 2\). Calculating this expression: \(0 - 0 - 2 = -2\). So, when \(x = 0\), the polynomial evaluates to -2.
2Step 2: Substitute and Evaluate for x=-1
Replace every occurrence of \(x\) in the polynomial \(x^2 - 5x - 2\) with -1. This gives us \((-1)^2 - 5(-1) - 2\). Calculating this expression: \(1 + 5 - 2 = 4\). So, when \(x = -1\), the polynomial evaluates to 4.
Key Concepts
Substitute ValuesAlgebraic ExpressionsSimplifying Polynomials
Substitute Values
When working with polynomials, one crucial step involves substituting given values into the expression. This means replacing the variable in the polynomial with specific numbers provided in the question. For the polynomial \(x^2 - 5x - 2\), if you're asked to substitute \(x = 0\), you replace every \(x\) with 0. This turns the expression into \(0^2 - 5(0) - 2\).
This concept of substitution is essential not only in polynomial evaluation but also in other areas of algebra. By replacing variables with numbers, you get a clearer understanding of how the polynomial behaves with different inputs.
- First, you perform the operations inside the expression, such as exponentiation and multiplication.
- Next, you simplify it by continuing with subtraction or addition.
This concept of substitution is essential not only in polynomial evaluation but also in other areas of algebra. By replacing variables with numbers, you get a clearer understanding of how the polynomial behaves with different inputs.
Algebraic Expressions
An algebraic expression is a mathematical phrase that can include numbers, variables, and operations. The expression \(x^2 - 5x - 2\) is a polynomial, which is a specific type of algebraic expression.
These components are joined by addition or subtraction to form the entire expression. Understanding how to read and interpret each part of an algebraic expression will help you when you simplify and evaluate it.
- It has three terms: \(x^2\), \(-5x\), and \(-2\).
- "\(x^2\)" is called a quadratic term because it has an exponent of 2.
- "\(-5x\)" is linear because the variable is to the power of 1.
- The "constant term" is \(-2\), as it doesn’t involve a variable.
These components are joined by addition or subtraction to form the entire expression. Understanding how to read and interpret each part of an algebraic expression will help you when you simplify and evaluate it.
Simplifying Polynomials
After substituting values into a polynomial, the next step is simplifying the equation to find the result. Simplifying means performing the operations in a predetermined order (known as "order of operations") until you reach a single number.
In the given polynomial \(x^2 - 5x - 2\), when \(x = 0\), the polynomial simplifies directly to \(-2\). For \(x = -1\), the steps are: calculate \((-1)^2 = 1\), then \(-5 \times -1 = 5\), finally add these results with \(-2\) yielding \(1 + 5 - 2 = 4\).
Simplification allows you to see how the polynomial responds to different values and is fundamental in algebra.
- First, handle any exponentiations, such as squaring.
- Next, do any multiplications or divisions.
- Finally, perform any additions or subtractions.
In the given polynomial \(x^2 - 5x - 2\), when \(x = 0\), the polynomial simplifies directly to \(-2\). For \(x = -1\), the steps are: calculate \((-1)^2 = 1\), then \(-5 \times -1 = 5\), finally add these results with \(-2\) yielding \(1 + 5 - 2 = 4\).
Simplification allows you to see how the polynomial responds to different values and is fundamental in algebra.
Other exercises in this chapter
Problem 14
Multiply. \(2 x(6 x+3)\)
View solution Problem 15
Add using a vertical format. $$ \begin{array}{r} 10 a^{3}-8 a^{2}+4 a+9 \\ 5 a^{3}+9 a^{2}-7 a+7 \end{array} $$
View solution Problem 15
Simplify each expression. Write each result using positive exponents only. $$ \frac{z^{-4}}{z^{-7}} $$
View solution Problem 15
Evaluate each expression with the given replacement values. $$ 5 x^{3} \text { when } x=3 $$
View solution