Problem 15
Question
Evaluate each expression. \(C(5,2)\)
Step-by-Step Solution
Verified Answer
The combination \( C(5, 2) \) is 10.
1Step 1: Understanding the Combination Formula
To find the combination of 5 items taken 2 at a time, we use the combination formula:\[ C(n, r) = \frac{n!}{r!(n-r)!} \]In this exercise, \( n = 5 \) and \( r = 2 \).
2Step 2: Substitute Values into the Formula
Substitute \( n = 5 \) and \( r = 2 \) into the formula:\[ C(5, 2) = \frac{5!}{2!(5-2)!} \]This means we need to calculate \( 5! \), \( 2! \), and \( 3! \) (since \( 5-2 = 3 \)).
3Step 3: Calculate Factorials
First, calculate the factorials:- \( 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \)- \( 2! = 2 \times 1 = 2 \)- \( 3! = 3 \times 2 \times 1 = 6 \)
4Step 4: Plug Factorials into the Combination Formula
Now, substitute the factorial values back into the combination formula:\[ C(5, 2) = \frac{120}{2 \times 6} \]
5Step 5: Simplify the Expression
Simplify the fraction:\[ \frac{120}{2 \times 6} = \frac{120}{12} = 10 \]
6Step 6: Final Answer
The number of combinations of 5 items taken 2 at a time is 10.
Key Concepts
FactorialsCombinatoricsCombination Formula
Factorials
A factorial is an operation that you perform on a number and it is denoted by an exclamation point (!). The factorial of a number is the product of that number and all the positive integers below it.
For instance, when you see \( 5! \), it means 5 multiplied by all the numbers below it: \( 5 \times 4 \times 3 \times 2 \times 1 \). This results in 120. Factorials are fundamental in combinatorics, as they help us calculate permutations and combinations.
Here’s a quick guide on how to compute factorials:
For instance, when you see \( 5! \), it means 5 multiplied by all the numbers below it: \( 5 \times 4 \times 3 \times 2 \times 1 \). This results in 120. Factorials are fundamental in combinatorics, as they help us calculate permutations and combinations.
Here’s a quick guide on how to compute factorials:
- Start with the number you want the factorial of (denoted \( n \)).
- Multiply \( n \) by every number less than it down to 1.
- The resulting product is \( n! \).
Combinatorics
Combinatorics is a branch of mathematics dealing with combinations, permutations, and the counting of these arrangements. It's all about finding ways to organize a set of items. Whether you're arranging books on a shelf or choosing a subset of items, combinatorics provides the tools you need to calculate possible combinations efficiently.
In this field, you often deal with:
In this field, you often deal with:
- Permutations: Arrangements where order matters.
- Combinations: Selections where order does not matter.
Combination Formula
The combination formula is a mathematical way to find out how many different groups can be selected from a set of items, where the order of selection does not matter. This formula is written as \( C(n, r) = \frac{n!}{r!(n-r)!} \) where:
2. Calculate \( r! \), the factorial of the number of items to choose.
3. Calculate \((n-r)!\), the factorial of the difference between total items and chosen items.
4. Substitute these values into the formula and simplify.
For example, if you want to find out how many ways you can choose 2 items out of 5 (written as \( C(5, 2) \)), substitute into the formula to get \( \frac{5!}{2! \times 3!} \). After calculating the factorials and simplifying, you find there are 10 combinations.
- \( n \) is the total number of items.
- \( r \) is the number of items to be chosen.
2. Calculate \( r! \), the factorial of the number of items to choose.
3. Calculate \((n-r)!\), the factorial of the difference between total items and chosen items.
4. Substitute these values into the formula and simplify.
For example, if you want to find out how many ways you can choose 2 items out of 5 (written as \( C(5, 2) \)), substitute into the formula to get \( \frac{5!}{2! \times 3!} \). After calculating the factorials and simplifying, you find there are 10 combinations.
Other exercises in this chapter
Problem 15
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