Problem 15
Question
Draw a graph of \(y=x^{3}-x .\) Where is the slope zero?
Step-by-Step Solution
Verified Answer
The slope is zero at \(x = \pm \sqrt{\frac{1}{3}}\).
1Step 1: Differentiate the function
To determine where the slope of the function is zero, we need to find the derivative of the function. Differentiate the function \(y = x^3 - x\) with respect to \(x\): \[ \frac{dy}{dx} = 3x^2 - 1. \]
2Step 2: Set the derivative equal to zero
To find where the slope is zero, set the derivative equal to zero: \[ 3x^2 - 1 = 0. \] This will help us identify the critical points where the slope of the tangent to the curve is zero.
3Step 3: Solve for \(x\)
Solve the equation \(3x^2 - 1 = 0\) for \(x\). Add 1 to both sides to obtain \(3x^2 = 1\). Divide both sides by 3: \[ x^2 = \frac{1}{3}. \] Take the square root of both sides to find \(x\): \[ x = \pm \sqrt{\frac{1}{3}}. \]
4Step 4: Identify the points with zero slope
The points where the slope of the graph is zero are at \(x = \sqrt{\frac{1}{3}}\) and \(x = -\sqrt{\frac{1}{3}}\). These values of \(x\) correspond to the locations on the curve where the slope is zero.
Key Concepts
DerivativeSlopeCritical PointsGraph of a Function
Derivative
In calculus, a derivative represents the rate of change of a function with respect to one of its variables. For the function given, the derivative helps us determine how the function behaves as the variable changes. The derivative of a function at a certain point tells us the slope of the tangent line at that point.
- To find the derivative, we differentiate the function.
- The differentiation turns the function into another expression that gives us the slope for any point on the curve.
Slope
The slope of a function at any given point is the value of the derivative at that point. It indicates the steepness and direction of the function's graph.
- A positive slope means the function is increasing.
- A negative slope indicates the function is decreasing.
- A zero slope points to a horizontal tangent, often a critical point.
Critical Points
Critical points in a function occur where the derivative is zero or undefined. They are essential for understanding the function's behavior, as they can indicate local maxima, minima, or points of inflection.
- To find critical points, set the derivative equal to zero.
- Solutions to this give the x-values where the graph might change direction.
Graph of a Function
A graph of a function visually displays how the function's values change over a range of inputs. It helps in understanding the overall behavior of the function, including trends and key characteristics like maxima, minima, and inflection points.
- The function \( y = x^3 - x \) shows both growth and decline because it is a cubic function.
- Where the derivative equals zero, the graph either reaches a peak, a dip, or changes concavity.
Other exercises in this chapter
Problem 14
Find the derivatives of the functions in \(1-26\). $$ \sqrt{x}(\sqrt{x}+1)(\sqrt{x}+2) $$
View solution Problem 14
Find the derivative of the derivative (the second derivative) of \(y=3 x^{2}\). What is the third derivative?
View solution Problem 15
In Problems \(1-20\), find the numbers \(c\) that make \(f(x)\) into (A) a continuous function and (B) a differentiable function. In one case \(f(x) \rightarrow
View solution Problem 15
Find the derivatives of the functions in \(1-26\). $$ \frac{1}{2} x^{2} \sin x-x \cos x+\sin x $$
View solution