Problem 15
Question
Differentiate two ways: first, by using the Quotient Rule; then, by dividing the expressions before differentiating. Compare your results as a check. Use a graphing calculator to check your results. \(g(x)=\frac{3 x^{7}-x^{3}}{x}\)
Step-by-Step Solution
Verified Answer
Both methods yield the same derivative: \( g'(x) = 18x^5 - 2x \).
1Step 1: Differentiate using Quotient Rule
The Quotient Rule is used to differentiate a function of the form \( \frac{u}{v} \), where \( u = 3x^7 - x^3 \) and \( v = x \). The rule states that:\( \frac{d}{dx} \left( \frac{u}{v} \right) = \frac{v \cdot u' - u \cdot v'}{v^2} \)First, find the derivatives:\( u' = 21x^6 - 3x^2 \)\( v' = 1 \)Now apply the Quotient Rule:\( g'(x) = \frac{x(21x^6 - 3x^2) - (3x^7 - x^3) \cdot 1}{x^2} \)Simplify the expression:\( g'(x) = \frac{21x^7 - 3x^3 - 3x^7 + x^3}{x^2} \)Combine like terms:\( g'(x) = \frac{18x^7 - 2x^3}{x^2} \)Simplify further to get:\( g'(x) = 18x^5 - 2x \).
2Step 2: Simplify the expression before differentiating
Before differentiating, simplify \( g(x) = \frac{3x^7 - x^3}{x} \) by dividing each term by \( x \):\( g(x) = \frac{3x^7}{x} - \frac{x^3}{x} \)\( g(x) = 3x^6 - x^2 \)Now differentiate directly:\( g'(x) = \frac{d}{dx}(3x^6) - \frac{d}{dx}(x^2)\)Calculate each derivative:\( \frac{d}{dx}(3x^6) = 18x^5 \)\( \frac{d}{dx}(x^2) = 2x \)Thus, \( g'(x) = 18x^5 - 2x \).
3Step 3: Comparison and verification using a graphing tool
Both methods result in \( g'(x) = 18x^5 - 2x \). Use a graphing calculator to plot \( g(x) = \frac{3x^7 - x^3}{x} \) and its derivative \( g'(x) = 18x^5 - 2x \). Verify that the derivative function matches the slope of the original function's curve at various points.
Key Concepts
Quotient RuleSimplifying ExpressionsGraphing Calculator
Quotient Rule
The Quotient Rule is a key principle in calculus for differentiating functions that are expressed as a ratio of two other functions. When you encounter a function of the form \( \frac{u}{v} \), where both \( u \) and \( v \) are differentiable functions, the Quotient Rule provides a structured method to find the derivative. The rule is expressed as follows:\[\frac{d}{dx} \left( \frac{u}{v} \right) = \frac{v \cdot u' - u \cdot v'}{v^2}\]This rule states that the derivative of \( \frac{u}{v} \) is computed by:
- Multiplying \( v \) by the derivative of \( u \), \( u' \).
- Subtracting the product of \( u \) and the derivative of \( v \), \( v' \).
- Finally, dividing the result by \( v^2 \), the square of \( v \).
Simplifying Expressions
Simplifying expressions before differentiating can save you time and effort, especially with functions that are composed of multiple terms. In our original exercise, the function \( g(x) = \frac{3 x^{7}-x^{3}}{x} \) was simplified by dividing each term in the numerator by \( x \), resulting in a simpler expression:\[g(x) = 3x^6 - x^2\]Simplifying expressions is a useful strategy when:
- The numerator can be easily divided by the denominator, reducing the function to its simplest form.
- The simplification leads to expressions that are straightforward to differentiate directly.
- You want to avoid complex or lengthy quotient rule calculations when a simpler path is available.
- \( \frac{d}{dx}(3x^6) = 18x^5 \)
- \( \frac{d}{dx}(x^2) = 2x \)
Graphing Calculator
Graphing calculators are powerful tools that allow you to visualize functions and their derivatives. In the context of this exercise, a graphing calculator can help you confirm the accuracy of your computed derivative \( g'(x) = 18x^5 - 2x \).Here's how to use a graphing calculator for the verification:
- First, input the original function \( g(x) = \frac{3x^7 - x^3}{x} \) into the calculator.
- Next, enter the derivative \( g'(x) = 18x^5 - 2x \) for graphing.
- Examine both graphs: the original function and its derivative.
- Check that the slope of the original function's graph aligns with the derivative function at various points.
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