Problem 15
Question
Determine whether each value of \(x\) is a solution of the inequality. Inequality $$-1<\frac{3-x}{2} \leq 1$$ Values (a) \(x=-1\) (b) \(x=\sqrt{5}\) (c) \(x=1\) (d) \(x=5\)
Step-by-Step Solution
Verified Answer
The values \(x=-1\) and \(x=1\) are solutions to the inequality \(-1<\frac{3-x}{2} \leq 1\), while the values \(x=\sqrt{5}\) and \(x=5\) are not solutions.
1Step 1 Substitute the value (a)
First substitute \(x=-1\) into the inequality \(-1<\frac{3-x}{2} \leq 1\). This results in: \(-1<\frac{3+1}{2}\) which simplifies to \(-1<2\) which is a true statement. Hence, \(x=-1\) is a solution to the inequality.
2Step 2 Substitute the value (b)
Meanwhile, substitute \(x=\sqrt{5}\) into the inequality: \(-1<\frac{3-\sqrt{5}}{2}\). This simplifies to: \(-1<-\frac{\sqrt{5}-3}{2}\) which is false. Therefore, \(x=\sqrt{5}\) is not a solution of the inequality.
3Step 3 Substitute the value (c)
Substitute \(x=1\) into the inequality: \(-1<\frac{3-1}{2}\). This simplifies to: \(-1<1\) which is a true statement. Thus, \(x=1\) is a solution to the inequality.
4Step 4 Substitute the value (d)
Substitute \(x=5\) into the inequality: \(-1<\frac{3-5}{2}\). This simplifies to: \(-1<-1\), which is false. Hence, \(x=5\) is not a solution to the inequality.
Key Concepts
Solving InequalitiesSubstitution MethodAlgebraic ExpressionsStep-by-Step Solutions
Solving Inequalities
Solving inequalities involves finding the set of values that satisfy a particular condition. An inequality, unlike an equation, contains signs such as \( <, >, \leq, \) and \( \geq \), which mean "less than", "greater than", "less than or equal to", and "greater than or equal to" respectively. When solving inequalities, the ultimate goal is to establish which values make the inequality true. To solve these, you often need to perform similar operations as you would with equations. However, remember that if you multiply or divide the inequality by a negative number, the inequality sign must be reversed. For example, if you have an inequality like \(-2x > 6\), you would divide both sides by \(-2\), which yields \(x < -3\). The key is ensuring the direction of the inequality remains correct once those operations are done.
Substitution Method
The substitution method is a technique that allows you to determine if specific values satisfy an equation or inequality. It is very simple to apply. Here's how it works:
- Take the value you want to test.
- Replace the variable in the inequality or equation with this value.
- Simplify the expression to see if it holds true.
Algebraic Expressions
Algebraic expressions consist of numbers, variables, and arithmetic operations like addition, subtraction, multiplication, and division. A fundamental understanding of these expressions is essential when solving inequalities, as they often form the core component of such problems.For the expression \(\frac{3-x}{2}\), you have the variable \(x\) and constants both in the numerator (3) and in the denominator (2). This expression simplifies differently based on the value substituted for \(x\). Manipulating algebraic expressions requires several skills:
- Identifying which operations to perform first (following the order of operations).
- Simplifying fractions to their lowest terms when necessary.
- Rewriting expressions to isolate the variable on one side.
Step-by-Step Solutions
Providing a step-by-step solution is crucial in understanding how to approach and solve algebraic inequalities effectively. This methodical approach helps in breaking down the problem into manageable parts, allowing for thorough comprehension.In the original problem:
- Each solution starts by substituting the given \(x\) value into the inequality.
- The inequality is simplified to verify its truth.
- A decision is made whether the substituted value is a solution.
Other exercises in this chapter
Problem 15
(a) create a scatter plot of the data, (b) draw a line of fit that passes through two of the points, and (c) use the two points to find an equation of the line.
View solution Problem 15
Solving an Equation of Quadratic Type In Exercises 13-16, find all solutions of the equation algebraically. Check your solutions. $$36 t^{4}+29 t^{2}-7=0$$
View solution Problem 15
Solve the quadratic equation by factoring. Check your solutions in the original equation. $$3 x^{2}=8-2 x$$
View solution Problem 15
Write the complex number in standard form. $$-8 i-i^{2}$$
View solution