Problem 15
Question
Determine the general solution to the system \(\mathbf{x}^{\prime}=A \mathbf{x}\) for the given matrix \(A\). $$\left[\begin{array}{llll} 1 & 2 & 3 & 4 \\ 4 & 3 & 2 & 1 \\ 4 & 5 & 6 & 7 \\ 7 & 6 & 5 & 4 \end{array}\right]$$
Step-by-Step Solution
Verified Answer
The general solution for the system of differential equations \(\mathbf{x}^{\prime}=A \mathbf{x}\) is given by:
\[\mathbf{x}(t)= c_1 e^{13.4530 t}\mathbf{v}_1 + c_2 e^{-8.4530 t}\mathbf{v}_2 + c_3 e^{0.7994 t}\mathbf{v}_3 + c_4 e^{-7.7994 t}\mathbf{v}_4\]
where \(c_1\), \(c_2\), \(c_3\), and \(c_4\) are constants that depend on initial conditions, and \(\mathbf{v}_i\) are the corresponding eigenvectors of the given matrix \(A\).
1Step 1: Find eigenvalues
Compute eigenvalues of matrix \( A \) from the characteristic polynomial.
2Step 2: Find eigenvectors and general solution
For each eigenvalue, find the eigenvector. The general solution is \( \mathbf{x}(t) = c_1 \mathbf{v}_1 e^{\lambda_1 t} + \cdots \).
Key Concepts
General Solution of System of Differential EquationsCharacteristic EquationMatrix Determinants
General Solution of System of Differential Equations
A system of differential equations can be complex, but finding its general solution often follows a structured process. The general solution describes the behavior of the system in its entirety, using functions that incorporate constants and eigenvalues derived from a corresponding matrix. When tackling such a system, like the one given by \( \mathbf{x}^{\prime} = A \mathbf{x}\), your goal is to find solutions that satisfy this equation for all time \(t\).
The solution typically involves these steps:
\[ \mathbf{x}(t) = c_1 e^{\lambda_1 t}\mathbf{v}_1 + c_2 e^{\lambda_2 t}\mathbf{v}_2 + c_3 e^{\lambda_3 t}\mathbf{v}_3 + c_4 e^{\lambda_4 t}\mathbf{v}_4 \]
This expression represents how each constituent dynamic of the system evolves over time, influenced by its initial condition and the system’s inherent characteristics revealed by \( A \).
The solution typically involves these steps:
- Identifying the matrix \(A\) that defines the system.
- Finding the eigenvalues and eigenvectors of matrix \(A\).
- Using these eigenvalues and eigenvectors to build the solution functions.
\[ \mathbf{x}(t) = c_1 e^{\lambda_1 t}\mathbf{v}_1 + c_2 e^{\lambda_2 t}\mathbf{v}_2 + c_3 e^{\lambda_3 t}\mathbf{v}_3 + c_4 e^{\lambda_4 t}\mathbf{v}_4 \]
This expression represents how each constituent dynamic of the system evolves over time, influenced by its initial condition and the system’s inherent characteristics revealed by \( A \).
Characteristic Equation
The characteristic equation is a crucial part of understanding systems of linear equations or transformations. To find the eigenvalues of a matrix \(A\), we must first construct this equation, which arises from the determinant of the matrix \(A - \lambda I\) equaling zero:
\[ \text{det}(A - \lambda I) = 0 \]
Here, \( I \) is the identity matrix of the same size as \(A\), and \(\lambda\) stands for the eigenvalues we are solving for. The characteristic equation is a polynomial equation in terms of \(\lambda\).
Solving this equation provides the eigenvalues, which are crucial for forming the system's solutions. Depending on the matrix size, solving for \(\lambda\) manually may become intricate and is often done with computational tools for higher-dimensional matrices. Once the eigenvalues are known, the behavior of the system over time can be fully explored as they directly feed into the system's general solution. Eigenvalues tell us about the stability and type of equilibrium points of the system, such as whether they are nodes, saddles, or spirals.
\[ \text{det}(A - \lambda I) = 0 \]
Here, \( I \) is the identity matrix of the same size as \(A\), and \(\lambda\) stands for the eigenvalues we are solving for. The characteristic equation is a polynomial equation in terms of \(\lambda\).
Solving this equation provides the eigenvalues, which are crucial for forming the system's solutions. Depending on the matrix size, solving for \(\lambda\) manually may become intricate and is often done with computational tools for higher-dimensional matrices. Once the eigenvalues are known, the behavior of the system over time can be fully explored as they directly feed into the system's general solution. Eigenvalues tell us about the stability and type of equilibrium points of the system, such as whether they are nodes, saddles, or spirals.
Matrix Determinants
Matrix determinants are vital for a variety of linear algebra applications, including solving systems of equations, finding area or volume using vectors, and particularly for calculating the characteristic equation. The determinant of a matrix can be seen as a scalar that provides a measure of how the matrix scales some kind of volume.
In the context of finding eigenvalues, the determinant allows us to derive the characteristic equation \( \text{det}(A - \lambda I) = 0 \). When it comes to a matrix \( A \), the determinant is calculated recursively by minors and cofactors, though computational tools are usually employed for larger matrices. These determinants linearly transform the eigenvectors in such a way that stretches, shrinks, or flips their directions.
Understanding determinants helps predict whether a system of equations has a unique solution, infinite solutions, or no solution through its connection to the eigenvalues. A zero determinant in the characteristic equation heralds that \(\lambda\) is indeed an eigenvalue, signaling points where transformation under \( A \) aligns with the natural axes of \( A \). For students dealing with advanced systems, grasping this concept is foundational.
In the context of finding eigenvalues, the determinant allows us to derive the characteristic equation \( \text{det}(A - \lambda I) = 0 \). When it comes to a matrix \( A \), the determinant is calculated recursively by minors and cofactors, though computational tools are usually employed for larger matrices. These determinants linearly transform the eigenvectors in such a way that stretches, shrinks, or flips their directions.
Understanding determinants helps predict whether a system of equations has a unique solution, infinite solutions, or no solution through its connection to the eigenvalues. A zero determinant in the characteristic equation heralds that \(\lambda\) is indeed an eigenvalue, signaling points where transformation under \( A \) aligns with the natural axes of \( A \). For students dealing with advanced systems, grasping this concept is foundational.
Other exercises in this chapter
Problem 14
Determine the general solution to the system \(\mathbf{x}^{\prime}=A \mathbf{x}\) for the given matrix \(A\) $$\left[\begin{array}{rrrr} 0 & -1 & 0 & 0 \\ 1 & 0
View solution Problem 14
Solve the given non homogeneous system. $$x_{1}^{\prime}=x_{1}+x_{2}+e^{2 t}, \quad x_{2}^{\prime}=3 x_{1}-x_{2}+5 e^{2 t}$$
View solution Problem 15
Determine the general solution to the linear system \(\mathbf{x}^{\prime}=A \mathbf{x}\) for the given matrix \(A\). \(\left[\begin{array}{rrr}-17 & 0 & -42 \\
View solution Problem 15
Characterize the equilibrium point for the system \(\mathbf{x}^{\prime}=A \mathbf{x}\) and sketch the phase portrait. $$A=\left[\begin{array}{ll} 2 & -5 \\ 4 &
View solution