Problem 15
Question
Consider the vaporization of liquid water to steam at a pressure of 1 atm. (a) Is this process endothermic or exothermic? (b) In what temperature range is it a spontaneous process? (c) In what temperature range is it a nonspontaneous process? (d) At what temperature are the two phases in equilibrium?
Step-by-Step Solution
Verified Answer
a) The vaporization of liquid water to steam is an endothermic process.
b) It is spontaneous for temperatures higher than \(\frac{\Delta H}{\Delta S}\).
c) It is nonspontaneous for temperatures lower than \(\frac{\Delta H}{\Delta S}\).
d) The two phases are in equilibrium at 100°C (373.15 K) at 1 atm pressure.
1Step 1: a) Endothermic or Exothermic
To answer this question, we need to think about the process of vaporization. When liquid water turns into steam, it needs to absorb energy in the form of heat to overcome the intermolecular forces holding the water molecules together in the liquid phase. As the water absorbs heat, the process is endothermic.
2Step 2: b) Spontaneous Temperature Range
To determine if the process is spontaneous, we will consider the sign of Gibbs free energy change (ΔG). If ΔG is negative, the process is spontaneous. The equation for Gibbs free energy change is:
ΔG = ΔH - TΔS,
where ΔH is the enthalpy change, T is the temperature in Kelvin, and ΔS is the entropy change.
In the case of vaporization, we know that ΔH > 0 (since it's endothermic) and ΔS > 0 (since gases have higher entropy than liquids). So, for the process to be spontaneous (ΔG < 0), we need:
0 > ΔH - TΔS,
which implies:
T > ΔH/ΔS.
Thus, the process is spontaneous for temperatures higher than ΔH/ΔS.
3Step 3: c) Nonspontaneous Temperature Range
For nonspontaneous processes, ΔG > 0. Using the same Gibbs free energy change equation (ΔG = ΔH - TΔS), we can write the condition for nonspontaneity as:
0 < ΔH - TΔS,
which implies:
T < ΔH/ΔS.
Thus, the process is nonspontaneous for temperatures lower than ΔH/ΔS.
4Step 4: d) Equilibrium Temperature
At equilibrium, the Gibbs free energy change (ΔG) is zero; both phases coexist, and the rate of vaporization equals the rate of condensation.
Using the Gibbs free energy change equation (ΔG = ΔH - TΔS), we can write the condition for equilibrium as:
0 = ΔH - TΔS,
which implies:
T = ΔH/ΔS.
The Clapeyron equation is often used to find the equilibrium temperature, but it requires additional information such as the specific enthalpy and entropy changes for the process or the saturation vapor pressure at different temperatures.
In the case of water, at 1 atm pressure, the equilibrium temperature between liquid water and steam is 373.15 K (100°C), which is the normal boiling point of water.
In summary:
a) The vaporization of liquid water to steam is an endothermic process.
b) It is spontaneous for temperatures higher than ΔH/ΔS.
c) It is nonspontaneous for temperatures lower than ΔH/ΔS.
d) The two phases are in equilibrium at 100°C (373.15 K) at 1 atm pressure.
Key Concepts
Endothermic processGibbs free energyEquilibrium temperatureSpontaneous process
Endothermic process
When we talk about an endothermic process, we refer to a reaction or transformation that absorbs energy from its surroundings in the form of heat. This concept is quite significant in understanding how substances like water change from one phase to another. During vaporization, when water turns into steam, energy is needed to overcome the intermolecular forces that hold water molecules together in liquid form.
- The absorbed energy is used to break these bonds, allowing molecules to move more freely in the gaseous state.
- This absorption of heat means the process is endothermic; it requires an input of energy from the environment.
Gibbs free energy
In thermodynamics, Gibbs free energy is a critical concept for predicting whether a process can occur spontaneously. It combines enthalpy, entropy, and temperature to determine the outcome of a reaction. The equation used is:\[\Delta G = \Delta H - T\Delta S\]In this equation:
- \( \Delta G \) represents the change in Gibbs free energy.
- \( \Delta H \) is the change in enthalpy — the heat absorbed or released.
- \( T \) is the temperature in Kelvin.
- \( \Delta S \) refers to the change in entropy — the measure of disorder or randomness.
- \( \Delta H \) is positive as it requires heat absorption.
- \( \Delta S \) is also positive, since gases exhibit higher entropy than liquids.
Equilibrium temperature
The equilibrium temperature is the point at which two phases coexist in balance. This concept can be illustrated using the vaporization of water. At equilibrium:
- The speed at which liquid water turns into steam equals the speed at which steam condenses back into water.
- The Gibbs free energy change \( (\Delta G) \) is zero, meaning the process is perfectly balanced.
Spontaneous process
A process is considered spontaneous when it occurs naturally without the need for external energy. Using Gibbs free energy as our guide, we identify spontaneity by a negative \( \Delta G \). For the vaporization of water:
- Spontaneity occurs at temperatures where the system's entropy increase and absorbed heat lead to a decrease in free energy (\( \Delta G < 0 \)).
- Above a specific temperature, determined by \( T > \frac{\Delta H}{\Delta S} \), the vaporization becomes spontaneous.
Other exercises in this chapter
Problem 13
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